./kernelbenchhardv3runskimi · kimi
kimi / kimi session: ? cwd: ?
INCOMPLETE SESSION. hit wall-clock budget (SIGTERM). The transcript below is usable but may be missing the agent's final tool calls or summary. Don't score this run as a clean failure or success.
harness
kimi
model
kimi
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tools called
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events
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input toks
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output toks
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solution.py
benchmark.log
check.log
result.json
"""KDA forward solution with custom CUDA and Triton kernels."""
from __future__ import annotations

import torch
import torch.nn as nn
from torch.utils.cpp_extension import load_inline
import triton
import triton.language as tl

# ---------------------------------------------------------------------------
# CUDA forward substitution kernel (loaded inline)
# ---------------------------------------------------------------------------
_CUDA_FWD_SUBST_SRC = """
__global__ void fwd_subst_kernel(float* __restrict__ A, int C, int batch) {
    int b = blockIdx.x;
    if (b >= batch) return;
    int tid = threadIdx.x;
    __shared__ float s_A[64][64];
    __shared__ float s_row[64];
    float* mat = A + b * C * C;
    for (int idx = tid; idx < C * C; idx += blockDim.x) {
        s_A[idx / C][idx % C] = mat[idx];
    }
    __syncthreads();
    for (int i = 1; i < C; i++) {
        if (tid < i) s_row[tid] = s_A[i][tid];
        __syncthreads();
        if (tid < i) {
            float sum = 0.0f;
            for (int k = 0; k < i; k++) {
                sum += s_row[k] * s_A[k][tid];
            }
            s_A[i][tid] += sum;
        }
        __syncthreads();
    }
    for (int idx = tid; idx < C * C; idx += blockDim.x) {
        mat[idx] = s_A[idx / C][idx % C];
    }
}
torch::Tensor fwd_subst(torch::Tensor A) {
    int batch = A.size(0);
    int C = A.size(1);
    fwd_subst_kernel<<<batch, 64>>>(A.data_ptr<float>(), C, batch);
    return A;
}
"""

_fwd_subst_mod = load_inline(
    name="kda_fwd_subst_v2",
    cpp_sources="torch::Tensor fwd_subst(torch::Tensor A);",
    cuda_sources=_CUDA_FWD_SUBST_SRC,
    functions=["fwd_subst"],
    extra_cuda_cflags=["-O3"],
    verbose=False,
)


# ---------------------------------------------------------------------------
# Triton kernel: inter-chunk recurrence + output
# ---------------------------------------------------------------------------
@triton.jit
def kda_inter_chunk_kernel(
    q_ptr,
    k_ptr,
    u_ptr,
    w_ptr,
    g_ptr,
    Aqk_ptr,
    o_ptr,
    B: tl.constexpr,
    T: tl.constexpr,
    H: tl.constexpr,
    K: tl.constexpr,
    V: tl.constexpr,
    BT: tl.constexpr,
    BV: tl.constexpr,
    scale: tl.constexpr,
):
    i_v = tl.program_id(0)
    i_bh = tl.program_id(1)
    i_b = i_bh // H
    i_h = i_bh % H

    NT = T // BT

    b_S1 = tl.zeros((64, BV), dtype=tl.float32)
    b_S2 = tl.zeros((64, BV), dtype=tl.float32)

    q_base = q_ptr + (i_b * T * H + i_h) * K
    k_base = k_ptr + (i_b * T * H + i_h) * K
    u_base = u_ptr + (i_b * T * H + i_h) * V
    w_base = w_ptr + (i_b * T * H + i_h) * K
    g_base = g_ptr + (i_b * T * H + i_h) * K
    Aqk_base = Aqk_ptr + (i_b * T * H + i_h) * BT
    o_base = o_ptr + (i_b * T * H + i_h) * V

    for i_t in range(NT):
        t0 = i_t * BT

        p_u = tl.make_block_ptr(
            u_base, (T, V), (H * V, 1), (t0, i_v * BV), (BT, BV), (1, 0)
        )
        b_v = tl.load(p_u, boundary_check=(0, 1)).to(tl.float32)

        p_w = tl.make_block_ptr(
            w_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
        )
        b_w = tl.load(p_w, boundary_check=(0, 1))
        b_v -= tl.dot(b_w, b_S1.to(b_w.dtype))

        p_w = tl.make_block_ptr(
            w_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
        )
        b_w = tl.load(p_w, boundary_check=(0, 1))
        b_v -= tl.dot(b_w, b_S2.to(b_w.dtype))

        b_o = tl.zeros((BT, BV), dtype=tl.float32)

        p_q = tl.make_block_ptr(
            q_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
        )
        p_g = tl.make_block_ptr(
            g_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
        )
        b_q = tl.load(p_q, boundary_check=(0, 1))
        b_g = tl.load(p_g, boundary_check=(0, 1)).to(tl.float32)
        b_qg = (b_q * tl.exp(b_g)).to(b_q.dtype)
        b_o += tl.dot(b_qg, b_S1.to(b_qg.dtype))

        p_q = tl.make_block_ptr(
            q_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
        )
        p_g = tl.make_block_ptr(
            g_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
        )
        b_q = tl.load(p_q, boundary_check=(0, 1))
        b_g = tl.load(p_g, boundary_check=(0, 1)).to(tl.float32)
        b_qg = (b_q * tl.exp(b_g)).to(b_q.dtype)
        b_o += tl.dot(b_qg, b_S2.to(b_qg.dtype))

        b_o *= scale

        p_Aqk = tl.make_block_ptr(
            Aqk_base, (T, BT), (H * BT, 1), (t0, 0), (BT, BT), (1, 0)
        )
        b_Aqk = tl.load(p_Aqk, boundary_check=(0, 1))
        o_i = tl.arange(0, BT)
        m_s = o_i[:, None] >= o_i[None, :]
        b_Aqk = tl.where(m_s, b_Aqk, 0.0).to(b_v.dtype)
        b_o += tl.dot(b_Aqk, b_v.to(b_Aqk.dtype))

        p_o = tl.make_block_ptr(
            o_base, (T, V), (H * V, 1), (t0, i_v * BV), (BT, BV), (1, 0)
        )
        tl.store(p_o, b_o.to(o_ptr.dtype.element_ty), boundary_check=(0, 1))

        last_idx = t0 + BT - 1
        p_glast1 = g_base + last_idx * H * K + tl.arange(0, 64)
        p_glast2 = g_base + last_idx * H * K + 64 + tl.arange(0, 64)
        b_glast1 = tl.load(p_glast1, mask=tl.arange(0, 64) < 64, other=0.0).to(tl.float32)
        b_glast2 = tl.load(p_glast2, mask=tl.arange(0, 64) < 64, other=0.0).to(tl.float32)
        b_decay1 = tl.exp(b_glast1)
        b_decay2 = tl.exp(b_glast2)
        b_S1 *= b_decay1[:, None]
        b_S2 *= b_decay2[:, None]

        p_k = tl.make_block_ptr(
            k_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
        )
        p_g = tl.make_block_ptr(
            g_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
        )
        b_k = tl.load(p_k, boundary_check=(0, 1))
        b_g = tl.load(p_g, boundary_check=(0, 1)).to(tl.float32)
        b_kg = b_k * tl.exp(b_glast1[None, :] - b_g)
        b_S1 += tl.dot(b_kg.to(b_v.dtype).T, b_v.to(b_k.dtype))

        p_k = tl.make_block_ptr(
            k_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
        )
        p_g = tl.make_block_ptr(
            g_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
        )
        b_k = tl.load(p_k, boundary_check=(0, 1))
        b_g = tl.load(p_g, boundary_check=(0, 1)).to(tl.float32)
        b_kg = b_k * tl.exp(b_glast2[None, :] - b_g)
        b_S2 += tl.dot(b_kg.to(b_v.dtype).T, b_v.to(b_k.dtype))


# ---------------------------------------------------------------------------
# Model
# ---------------------------------------------------------------------------
class Model(nn.Module):
    def __init__(self, B: int, T: int, H: int, K: int, V: int, chunk_size: int = 64):
        super().__init__()
        self.B, self.T, self.H, self.K, self.V = B, T, H, K, V
        self.chunk_size = chunk_size
        self.scale = float(K) ** -0.5
        self.register_buffer("_dummy", torch.zeros(1), persistent=False)

    def forward(
        self,
        q: torch.Tensor,
        k: torch.Tensor,
        v: torch.Tensor,
        g: torch.Tensor,
        beta: torch.Tensor,
    ) -> torch.Tensor:
        dtype = v.dtype
        B, T, H, K = q.shape
        V = v.shape[-1]
        BT = self.chunk_size
        assert T % BT == 0
        NT = T // BT

        qf, kf, vf, gf, bf = (x.to(torch.float32) for x in (q, k, v, g, beta))
        qf = qf * self.scale

        # Chunked layout contiguous
        qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).contiguous()
        kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).contiguous()
        vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4).contiguous()
        gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).contiguous()
        bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2).contiguous()

        gf = gf.cumsum(-2)

        # ---- Intra-chunk A_kk ----
        kg = kf * gf.exp()
        kgn = kf * (-gf).exp()

        BHN = B * H * NT
        kg_flat = kg.reshape(BHN, BT, K)
        kgn_flat = kgn.reshape(BHN, BT, K)

        A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1))
        A = A.view(B, H, NT, BT, BT)

        mask_diag_upper = torch.triu(torch.ones(BT, BT, dtype=torch.bool, device=q.device), diagonal=0)
        A = A * bf[..., None]
        A = -A.masked_fill(mask_diag_upper, 0)

        A_flat = A.view(BHN, BT, BT)
        A_flat = _fwd_subst_mod.fwd_subst(A_flat)
        A = A_flat.view(B, H, NT, BT, BT)

        I = torch.eye(BT, dtype=torch.float32, device=q.device)
        A = (A + I) * bf[..., None, :]

        w = torch.matmul(A, (gf.exp() * kf))
        u = torch.matmul(A, vf)

        qg = qf * gf.exp()
        qg_flat = qg.reshape(BHN, BT, K)
        Aqk = torch.bmm(qg_flat, kgn_flat.transpose(-2, -1))
        Aqk = Aqk.view(B, H, NT, BT, BT)
        mask_strict = torch.triu(torch.ones(BT, BT, dtype=torch.bool, device=q.device), diagonal=1)
        Aqk = Aqk.masked_fill(mask_strict, 0)

        # ---- Inter-chunk recurrence via Triton kernel ----
        # Use original (B, T, H, K/V) layout for the kernel to avoid extra copies
        # qf_flat is already standard layout after permute+reshape
        qf_flat = qf.permute(0, 2, 3, 4, 1).reshape(B, T, H, K)
        kf_flat = kf.permute(0, 2, 3, 4, 1).reshape(B, T, H, K)
        u_flat = u.permute(0, 2, 3, 4, 1).reshape(B, T, H, V)
        w_flat = w.permute(0, 2, 3, 4, 1).reshape(B, T, H, K)
        gf_flat = gf.permute(0, 2, 3, 4, 1).reshape(B, T, H, K)
        Aqk_flat = Aqk.permute(0, 2, 3, 4, 1).reshape(B, T, H, BT)
        o = torch.empty_like(v)

        BV = 32
        grid = (triton.cdiv(V, BV), B * H)
        kda_inter_chunk_kernel[grid](
            qf_flat,
            kf_flat,
            u_flat,
            w_flat,
            gf_flat,
            Aqk_flat,
            o,
            B=B,
            T=T,
            H=H,
            K=K,
            V=V,
            BT=BT,
            BV=BV,
            scale=self.scale,
            num_warps=4,
            num_stages=1,
        )

        return o.to(dtype)


# Module-level shape shims
B = 2
T = 1024
H = 8
K = 128
V = 128
CHUNK_SIZE = 64


def get_inputs():
    torch.manual_seed(0)
    q = torch.randn(B, T, H, K, dtype=torch.bfloat16) * 0.1
    k = torch.randn(B, T, H, K, dtype=torch.bfloat16) * 0.1
    v = torch.randn(B, T, H, V, dtype=torch.bfloat16) * 0.1
    g = (torch.randn(B, T, H, K, dtype=torch.float32) * 0.1 - 0.05)
    beta = torch.sigmoid(torch.randn(B, T, H, dtype=torch.bfloat16))
    return [q, k, v, g, beta]


def get_init_inputs():
    return [B, T, H, K, V, CHUNK_SIZE]
/home/infatoshi/cuda/KernelBench-Hard/.venv/lib/python3.11/site-packages/torch/_inductor/compile_fx.py:322: UserWarning: TensorFloat32 tensor cores for float32 matrix multiplication available but not enabled. Consider setting `torch.set_float32_matmul_precision('high')` for better performance.
  warnings.warn(
shape=0 variant=eager tflops=0.050 gbps=0.583 ms=43.216
shape=0 variant=compiled tflops=0.506 gbps=5.942 ms=4.241
shape=0 variant=sota tflops=7.629 gbps=89.514 ms=0.282
shape=0 variant=solution tflops=5.971 gbps=70.068 ms=0.360
shape=0 solution_peak_fraction=0.0299
shape=1 variant=eager tflops=0.052 gbps=0.612 ms=82.394
shape=1 variant=compiled tflops=0.487 gbps=5.718 ms=8.814
shape=1 variant=sota tflops=13.533 gbps=158.801 ms=0.317
shape=1 variant=solution tflops=6.097 gbps=71.540 ms=0.704
shape=1 solution_peak_fraction=0.0305
shape=2 variant=eager tflops=0.033 gbps=0.391 ms=128.748
shape=2 variant=compiled tflops=0.262 gbps=3.079 ms=16.367
shape=2 variant=sota tflops=12.732 gbps=149.401 ms=0.337
shape=2 variant=solution tflops=4.416 gbps=51.819 ms=0.973
shape=2 solution_peak_fraction=0.0221
shape=3 variant=eager tflops=0.016 gbps=0.192 ms=65.730
shape=3 variant=compiled tflops=0.209 gbps=2.457 ms=5.129
shape=3 variant=sota tflops=3.758 gbps=44.098 ms=0.286
shape=3 variant=solution tflops=2.250 gbps=26.400 ms=0.477
shape=3 solution_peak_fraction=0.0112
peak_fraction: 0.0218
RESULT: LOW
PASS
{
    "problem": "02_kda_cutlass",
    "harness": "kimi",
    "model": "kimi-k2.6",
    "reasoning_effort": "",
    "has_solution": true,
    "correct": true,
    "peak_fraction": 0.0218,
    "elapsed_seconds": 2700,
    "harness_exit_code": 124,
    "session_complete": false,
    "usage": {"input_tokens": null, "output_tokens": null, "cache_read_tokens": null, "cache_creation_tokens": null, "reasoning_tokens": null, "total_cost_usd": null}
}

timeline (152 events)

assistant
reasoning (439 chars)
Let me understand the task: 1. I need to implement Kimi Delta Attention (KDA) forward in chunk form 2. The target hardware is RTX PRO 6000 (SM120 Blackwell, GDDR7, 1.8 TB/s) 3. I need to write a custom kernel in solution.py 4. The reference implementation is in reference.py 5. I need to handle specific shapes and pass check.py Let me first read the reference.py and other files to understand the operation, then plan my implementation.
ReadFile /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/reference.py
args
{
  "path": "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/reference.py"
}
ReadFile
args
{
  "raw": "{\"path\": \"/home/infatos"
}
tool
stdout (6205 chars) — TRUNCATED
<system>143 lines read from file starting from line 1. Total lines in file: 143. End of file reached.</system>
     1	"""Naive PyTorch reference for Kimi Delta Attention (KDA) forward, chunk form.
     2	
     3	This is the correctness oracle, NOT the SOTA baseline. It mirrors the
     4	chunk-parallel formulation in fla/ops/kda/naive.py (Songlin Yang et al.)
     5	without any Triton or CUDA optimization.
     6	
     7	Inputs (per the FLA convention):
     8	  q, k : (B, T, H, K)   bf16   -- queries / keys
     9	  v    : (B, T, H, V)   bf16   -- values
    10	  g    : (B, T, H, K)   fp32   -- per-channel log-decay (in-chunk cumsum applied)
    11	  beta : (B, T, H)      bf16   -- write strength
    12	
    13	Output:
    14	  o    : (B, T, H, V)   bf16
    15	
    16	The agent must reproduce this output (within bf16 tolerance) using a CUTLASS
    17	CuTe kernel on SM120 -- NOT by calling fla.ops.chunk_kda directly.
    18	"""
    19	from __future__ import annotations
    20	
    21	import torch
    22	import torch.nn as nn
    23	from einops import rearrange
    24	
    25	OP_TYPE = "linear_attention"
    26	SUPPORTED_PRECISIONS = ["bf16"]
    27	HARDWARE_REQUIRED = ["RTX_PRO_6000", "H100", "B200"]
    28	
    29	
    30	def _naive_chunk_kda(
    31	    q: torch.Tensor,
    32	    k: torch.Tensor,
    33	    v: torch.Tensor,
    34	    g: torch.Tensor,
    35	    beta: torch.Tensor,
    36	    scale: float,
    37	    chunk_size: int = 64,
    38	) -> torch.Tensor:
    39	

... (4705 more chars)
assistant
ReadFile
args
{
  "raw": "{\"path\": \"/home/infatos"
}
tool
stdout (4724 chars) — TRUNCATED
<system>113 lines read from file starting from line 1. Total lines in file: 113. End of file reached.</system>
     1	"""Correctness runner for KDA forward (chunk form).
     2	
     3	Runs solution.Model vs reference.Model across all shapes in shapes.py, 3 seeds
     4	each, with per-dtype atol/rtol (bf16 default 1e-2 plus a 5e-2 override for
     5	this problem). Also rejects forbidden ops by grep.
     6	"""
     7	import re
     8	import sys
     9	from pathlib import Path
    10	
    11	import torch
    12	import yaml
    13	
    14	# Make the repo's src/ importable
    15	REPO_ROOT = Path(__file__).resolve().parents[2]
    16	sys.path.insert(0, str(REPO_ROOT))
    17	
    18	from src.eval.correctness import check_correctness  # noqa: E402
    19	
    20	
    21	def _apply_shape(reference, shape):
    22	    """Override reference's module-level shape shims so get_inputs/get_init_inputs match."""
    23	    for k, v in shape.items():
    24	        setattr(reference, k, v)
    25	
    26	
    27	def main():
    28	    try:
    29	        import reference
    30	        import shapes
    31	        import solution
    32	    except Exception as e:
    33	        print(f"FAIL: import error: {e}")
    34	        sys.exit(1)
    35	
    36	    problem_yaml = Path("problem.yaml")
    37	    meta = yaml.safe_load(problem_yaml.read_text()) if problem_yaml.exists() else {}
    38	
    39	    # --- Forbidden-op check ------------------------------------------------
    40	    sol_

... (3224 more chars)
assistant
ReadFile
args
{
  "raw": "{\"path\": \"/home/infatos"
}
tool
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<system>133 lines read from file starting from line 1. Total lines in file: 133. End of file reached.</system>
     1	"""Roofline benchmark for KDA forward (chunk form).
     2	
     3	For each shape: times eager reference, compiled reference, SOTA (FLA's Triton
     4	chunk_kda, if available on this GPU), and the agent's solution. Reports
     5	achieved TFLOPS, GB/s, and peak_fraction.
     6	
     7	Output lines the harness picks up:
     8	  shape=<idx> variant=<name> tflops=<N> gbps=<N> ms=<N>
     9	  peak_fraction: <N>  (geomean over shapes of solution's peak_fraction)
    10	"""
    11	import sys
    12	from math import exp, log
    13	from pathlib import Path
    14	
    15	import torch
    16	import yaml
    17	
    18	REPO_ROOT = Path(__file__).resolve().parents[2]
    19	sys.path.insert(0, str(REPO_ROOT))
    20	
    21	from src.eval.roofline import compute_gbps, compute_tflops, peak_fraction  # noqa: E402
    22	from src.eval.timing import time_fn  # noqa: E402
    23	from src.hardware import get as get_hw  # noqa: E402
    24	
    25	
    26	def _eval_formula(expr: str, vars: dict) -> float:
    27	    return float(eval(expr, {"__builtins__": {}}, vars))
    28	
    29	
    30	def _apply_shape(reference, shape):
    31	    for k, v in shape.items():
    32	        setattr(reference, k, v)
    33	
    34	
    35	def main():
    36	    import reference
    37	    import shapes
    38	    import solution
    39	
    40	    meta = yaml.safe_load(Path("problem.yaml")

... (3922 more chars)
assistant
ReadFile
args
{
  "raw": "{\"path\": \"/home/infatoshi/cuda/Kernel"
}
tool
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<system>54 lines read from file starting from line 1. Total lines in file: 54. End of file reached.</system>
     1	name: 02_kda_cutlass
     2	display_name: "Kimi Delta Attention (chunk forward) via CUTLASS CuTe"
     3	precision: bf16
     4	regime: compute
     5	
     6	# Approximate FLOPs per forward call. KDA forward (chunk form) breakdown per
     7	# token across all heads:
     8	#   - intra-chunk Aqk (q @ k.T with decay): 2*BT*K
     9	#   - intra-chunk Akk + cumulative invert : ~3*BT*K + BT^2
    10	#   - w = A @ (g.exp()*k):                  2*BT*K
    11	#   - u = A @ v:                            2*BT*V
    12	#   - inter-chunk q @ S:                    2*K*V
    13	#   - inter-chunk (Aqk @ v_i):              2*BT*V
    14	#   - state update S += k.T @ v_i:          2*K*V
    15	# Aggregating with a constant of 4 (typical for chunked linear attention) gives
    16	# the formula below. Used only for roofline reporting -- not graded directly.
    17	flops_formula: "4 * B * T * H * (K*V + CHUNK_SIZE*K + CHUNK_SIZE*V)"
    18	
    19	# Bytes moved (lower bound): one read of q,k,v,g,beta and one write of o.
    20	bytes_formula: "B*T*H*K*2 + B*T*H*K*2 + B*T*H*V*2 + B*T*H*K*4 + B*T*H*2 + B*T*H*V*2"
    21	
    22	hardware: [RTX_PRO_6000]
    23	peak_tflops_key: bf16  # KDA's heavy work is bf16 @ bf16 -> fp32 GEMM-equivalent
    24	peak_bandwidth_key: dram
    25	
    26	# bf16 default tolerance from src/eval/correctness.py is 1e-2 atol/rtol; KDA's
    27	# long recurr

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<system>19 lines read from file starting from line 1. Total lines in file: 19. End of file reached.</system>
     1	"""Canonical shape sweep for KDA forward (chunk form).
     2	
     3	Mix of:
     4	  - short-context training-step scale (T=1024)
     5	  - mid-context (T=2048) which is the headline benchmark
     6	  - long-context that stresses the inter-chunk recurrence (T=4096)
     7	  - thin-batch decode-style (B=1, T=2048, fewer heads)
     8	
     9	Constraints:
    10	  - T % chunk_size == 0 (chunk_size = 64)
    11	  - K, V are the per-head channel dims; KDA in Kimi Linear uses K=V=128
    12	"""
    13	
    14	SHAPES = [
    15	    {"B": 2, "T": 1024, "H": 8, "K": 128, "V": 128, "CHUNK_SIZE": 64},
    16	    {"B": 2, "T": 2048, "H": 8, "K": 128, "V": 128, "CHUNK_SIZE": 64},
    17	    {"B": 1, "T": 4096, "H": 8, "K": 128, "V": 128, "CHUNK_SIZE": 64},
    18	    {"B": 1, "T": 2048, "H": 4, "K": 128, "V": 128, "CHUNK_SIZE": 64},
    19	]
assistant
reasoning (2535 chars)
Let me understand the algorithm from reference.py: 1. Inputs: q, k (B, T, H, K) bf16; v (B, T, H, V) bf16; g (B, T, H, K) fp32; beta (B, T, H) bf16 2. chunk_size = 64, T is multiple of 64 3. q = q * scale 4. Reshape to chunk form: (B, H, N, C, D) where N = T/64, C = 64 5. g = g.cumsum(-2) # in-chunk cumsum 6. Build A_kk (intra-chunk K-K interaction): - A[..., i] = einsum("...cd, ...d -> ...c", k * exp(g - g_i), k_i) for each i in [0, C) - A = A * beta[..., None] - A = -A.masked_fill(mask_diag_upper, 0) # lower triangular, no diag - For i in 1..BT-1: A[..., i, :i] = A[..., i, :i] + sum over j of A[..., i, j] * A[..., j, :i] # cumulative invert - A = (A + I) * beta[..., None, :] 7. w = A @ (exp(g) * k) # (B, H, N, C, K) 8. u = A @ v # (B, H, N, C, V) 9. Inter-chunk recurrent pass: - S = zeros(B, H, K, V) - For each chunk i: - Compute Aqk = einsum("...cd, ...d -> ...c", q_i * exp(g_i - g_j), k_j) for each j - Aqk = Aqk.masked_fill(mask_strict_upper, 0) # lower triangular, strict (no diag) - v_i = u_i - w_i @ S - o_i = (q_i * exp(g_i)) @ S + Aqk @ v_i - S = S * exp(g_i[:, :, -1]).exp().reshape(...) - S = S + rearrange(exp(g_i[:,:,-1:] - g_i) * k_i, ...) @ v_i This is a complex chunked linear attention algorithm. Let me think about how to implement this efficiently. The main operations are: 1. Intra-chunk: Building A matrix (C x C) per chunk 2. Intra-chunk: Matrix multiplies with A 3. Inter-chunk: Recurrent state updates with GEMMs For a custom kernel, I have a few options: 1. Triton - easier to write, but might not reach peak SM120 2. CUDA C++ with load_inline - flexible 3. CUTLASS CuTe - complex but can reach peak performance 4. Inline PTX - most control but very tedious Given the algorithm complexity and the fact that I need to handle multiple shapes, Triton might be the most practical approach. However, the problem explicitly mentions CUTLASS CuTe on SM120. But Triton is also acceptable. Let me think about what operations are needed: - Computing A_kk involves per-chunk operations with cumsum and matrix multiplies - The inter-chunk recurrence is sequential over chunks For efficiency, I should think about fusing operations. But given the complexity, I might start with a PyTorch implementation that breaks down the operations and see if torch.compile or manual optimization can get us there. But the problem says "This needs to be a real custom kernel." Let me first check what hardware we're actually on, and what tools are available.
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{
  "command": "nvidia-smi --query-gpu=name,compute_cap,memory.total --format=csv,noheader"
}
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  "raw": "{\"command\":"
}
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<system>Command executed successfully.</system>
NVIDIA RTX PRO 6000 Blackwell Workstation Edition, 12.0, 97887 MiB
assistant
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args
{
  "command": "which nvcc && nvcc --version | head -3"
}
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{
  "raw": "{\"command\":"
}
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<system>Command executed successfully.</system>
/usr/local/cuda-13/bin/nvcc
nvcc: NVIDIA (R) Cuda compiler driver
Copyright (c) 2005-2026 NVIDIA Corporation
Built on Mon_Mar_02_09:52:23_PM_PST_2026
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<system>Command executed successfully.</system>
3.6.0
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<system>Command executed successfully.</system>
2.11.0+cu130
NVIDIA RTX PRO 6000 Blackwell Workstation Edition
(12, 0)
assistant
reasoning (1229 chars)
Good, we have SM120 Blackwell, CUDA 13.0, PyTorch 2.11, Triton 3.6.0. Let me check if CUTLASS is available and look at the FLA library for reference. Actually, let me first understand the algorithm better. Let me look at the FLA implementation to understand the chunk-parallel KDA forward better. Since I can't call it, I can read it for reference. Let me also think about the kernel strategy. For SM120 Blackwell, we have: - Blackwell architecture with new TCGen05 MMA units - Much higher FP16/BF16 throughput - Triton 3.6 should have some Blackwell support The key question is: can I write this in Triton and get good performance, or do I need CUTLASS? For a problem like this, a fused Triton kernel would be the most practical. The algorithm has: 1. Intra-chunk computations (can be parallelized across chunks) 2. Inter-chunk recurrence (sequential) For the inter-chunk recurrence, we could use a scan/associative scan approach or just process chunks sequentially. Since the chunks are reasonably large (64 tokens), and we have B*H parallel units, the sequential part might be acceptable if the intra-chunk work is well-parallelized. Let me look at the FLA source code for reference on how they implement this in Triton.
Shell
args
{
  "command": "find /home/infatoshi -path \"*/fla/ops/kda*\" -type f 2>/dev/null | head -20"
}
Shell
args
{
  "command": "pip show flash-linear-attention 2>/dev/null | head -5 || echo \"FLA not installed\""
}
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{
  "raw": "{\"command\": \"python -c \\\"import cutlass; print(cutlass.__version__)\\\" "
}
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<system>Command executed successfully.</system>
Name: flash-linear-attention
Version: 0.4.2
Summary: Fast linear attention models and layers
Home-page: 
Author: 
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{
  "raw": "{\"command\": \""
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<system>Command executed successfully.</system>
CUTLASS python bindings not installed
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<system>Command executed successfully.</system>
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/backends/__init__.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/backends/flashkda.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/backends/tilelang/__init__.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/backends/tilelang/chunk_bwd_dqkg.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/__init__.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/chunk_intra_token_parallel.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/naive.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/chunk_bwd.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/fused_recurrent.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/gate.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/chunk.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/chunk_fwd.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/chunk_intra.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/wy_fast.py
/home/infatoshi/.cache/uv/archive-v0/iFZrSVxXzSlD8QXgcEf3G/vllm/model_executor/layers/fla/ops/kda.py
/home/infatoshi/.cache/uv/archive-v0/pD3XxLT5AwqAQ7PonqFRK/vllm/model_executor/layers/fla/ops/kda.py
/home/inf

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assistant
reasoning (86 chars)
Let me read the FLA chunk_fwd.py and related files to understand the algorithm better.
ReadFile /home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/chunk_fwd.py
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  "path": "/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/chunk_fwd.py"
}
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  "raw": "{\"path\": \"/home/infatoshi/."
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<system>135 lines read from file starting from line 1. Total lines in file: 135. End of file reached.</system>
     1	# Copyright (c) 2023-2026, Songlin Yang, Yu Zhang, Zhiyuan Li
     2	#
     3	# This source code is licensed under the MIT license found in the
     4	# LICENSE file in the root directory of this source tree.
     5	# For a list of all contributors, visit:
     6	#   https://github.com/fla-org/flash-linear-attention/graphs/contributors
     7	
     8	import torch
     9	
    10	from fla.ops.common.chunk_delta_h import chunk_gated_delta_rule_fwd_h
    11	from fla.ops.cp import FLACPContext
    12	from fla.ops.cp.chunk_delta_h import chunk_gated_delta_rule_fwd_h_pre_process, compress_h0
    13	from fla.ops.gla.chunk import chunk_gla_fwd_o_gk
    14	from fla.ops.kda.chunk_intra import chunk_kda_fwd_intra
    15	from fla.ops.kda.gate import kda_gate_chunk_cumsum
    16	from fla.ops.utils import chunk_local_cumsum
    17	from fla.ops.utils.constant import RCP_LN2
    18	
    19	
    20	def chunk_kda_fwd(
    21	    q: torch.Tensor,
    22	    k: torch.Tensor,
    23	    v: torch.Tensor,
    24	    g: torch.Tensor,
    25	    beta: torch.Tensor,
    26	    scale: float,
    27	    initial_state: torch.Tensor,
    28	    output_final_state: bool,
    29	    cu_seqlens: torch.LongTensor | None = None,
    30	    cu_seqlens_cpu: torch.LongTensor | None = None,
    31	    chunk_indices: torch.LongTensor | None = None,
    32	    chunk_size: int = 64,
    33	    safe_gat

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  "raw": "{\"path\": \"/home/infatoshi/."
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<system>914 lines read from file starting from line 1. Total lines in file: 914. End of file reached.</system>
     1	# Copyright (c) 2023-2026, Songlin Yang, Yu Zhang, Zhiyuan Li
     2	#
     3	# This source code is licensed under the MIT license found in the
     4	# LICENSE file in the root directory of this source tree.
     5	# For a list of all contributors, visit:
     6	#   https://github.com/fla-org/flash-linear-attention/graphs/contributors
     7	
     8	import torch
     9	import triton
    10	import triton.language as tl
    11	
    12	from fla.ops.kda.chunk_intra_token_parallel import chunk_kda_fwd_intra_token_parallel
    13	from fla.ops.kda.wy_fast import recompute_w_u_fwd
    14	from fla.ops.utils import prepare_chunk_indices
    15	from fla.ops.utils.op import exp2, gather
    16	from fla.utils import IS_GATHER_SUPPORTED, IS_TF32_SUPPORTED, autotune_cache_kwargs
    17	
    18	if IS_TF32_SUPPORTED:
    19	    SOLVE_TRIL_DOT_PRECISION = tl.constexpr('tf32')
    20	else:
    21	    SOLVE_TRIL_DOT_PRECISION = tl.constexpr('ieee')
    22	
    23	################################################################################
    24	# Fused inter + solve_tril kernel: compute off-diagonal Akk and solve in one pass
    25	################################################################################
    26	
    27	
    28	@triton.heuristics({
    29	    'IS_VARLEN': lambda args: args['cu_seqlens'] is not None,
    30	})
    31	@triton.autotune(
    32	    config

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<system>385 lines read from file starting from line 1. Total lines in file: 385. End of file reached.</system>
     1	# Copyright (c) 2023-2026, Songlin Yang, Yu Zhang, Zhiyuan Li
     2	#
     3	# This source code is licensed under the MIT license found in the
     4	# LICENSE file in the root directory of this source tree.
     5	# For a list of all contributors, visit:
     6	#   https://github.com/fla-org/flash-linear-attention/graphs/contributors
     7	
     8	# Related files are modified and supported by the Moonshot AI Team
     9	
    10	import torch
    11	
    12	from fla.modules.l2norm import l2norm_bwd, l2norm_fwd
    13	from fla.ops.backends import dispatch
    14	from fla.ops.cp import FLACPContext
    15	from fla.ops.kda.chunk_bwd import chunk_kda_bwd
    16	from fla.ops.kda.chunk_fwd import chunk_kda_fwd
    17	from fla.ops.utils.index import prepare_chunk_indices
    18	from fla.utils import autocast_custom_bwd, autocast_custom_fwd, input_guard
    19	
    20	
    21	class ChunkKDAFunction(torch.autograd.Function):
    22	    @staticmethod
    23	    @input_guard
    24	    @autocast_custom_fwd
    25	    def forward(
    26	        ctx,
    27	        q: torch.Tensor,
    28	        k: torch.Tensor,
    29	        v: torch.Tensor,
    30	        g: torch.Tensor,
    31	        beta: torch.Tensor,
    32	        A_log: torch.Tensor,
    33	        dt_bias: torch.Tensor,
    34	        scale: float,
    35	        initial_state: torch.Tensor,
    36	        o

... (18190 more chars)
assistant
reasoning (15091 chars)
This is a very complex algorithm. Let me break down what I need to do: 1. The reference.py provides a naive PyTorch implementation of chunk-parallel KDA forward 2. I need to write a custom kernel in solution.py 3. The shapes are manageable: K=V=128, chunk_size=64, H up to 8, B up to 2, T up to 4096 Looking at the reference implementation, the algorithm steps are: 1. Reshape to chunk form 2. Compute g = g.cumsum(-2) (in-chunk cumsum already applied... wait, the comment says "in-chunk cumsum already applied" but then the reference does `g = g.cumsum(-2)`. Let me re-read.) Actually, looking at the reference more carefully: - `g = g.cumsum(-2)` applies cumsum along the chunk dimension - The comment in the forward says `g` is "per-channel log-decay with in-chunk cumsum already applied" - but then the reference still applies cumsum. This is confusing. Wait, looking at FLA's chunk_kda_fwd: - It calls `chunk_local_cumsum(g, scale=RCP_LN2, chunk_size=chunk_size)` first - So the `g` input might not have cumsum applied, and the reference applies it But the problem statement says: "g of shape (B, T, H, K) in fp32 (per-channel log-decay with in-chunk cumsum already applied)" Hmm, but the reference does `g = g.cumsum(-2)`. So either the problem statement means something slightly different, or I should follow the reference exactly. Let me re-read the reference: `g = g.cumsum(-2)` - this is the in-chunk cumsum. So if the input already has in-chunk cumsum applied... wait no, the reference reshapes first: `g = rearrange(g, "b (n c) h d -> b h n c d", c=BT)` and then `g = g.cumsum(-2)`. The cumsum is applied within each chunk. So maybe the input g doesn't have cumsum yet, and the problem statement is wrong, or it does and we should skip it. Actually wait, the problem statement says "per-channel log-decay with in-chunk cumsum already applied". But the reference applies cumsum. Let me look more carefully at FLA's implementation. In FLA's `chunk_kda_fwd`, they call `chunk_local_cumsum(g, ...)` which applies cumsum within each chunk. Then `chunk_kda_fwd_intra` uses this cumsum'd g. And in `chunk_kda_fwd_intra`, the `chunk_kda_fwd_kernel_intra_sub_chunk` kernel computes `b_gm = (b_g - b_gn)` where `b_gn` is gathered from a specific position, suggesting the g has already been cumsum'd. But the reference does `g = g.cumsum(-2)` after reshaping. So for correctness with the reference, I should do exactly what the reference does. Now, for the kernel implementation. Given the complexity of the algorithm, I have a few options: **Option 1: PyTorch operations with careful fusion** I could decompose the algorithm into PyTorch ops and use `torch.compile` or custom kernels for parts. But the problem says "This needs to be a real custom kernel." **Option 2: Triton** Write the key parts in Triton. This is probably the most practical approach given the time constraints. The algorithm involves: - Intra-chunk A_kk computation (lower-triangular matrix with decay) - Forward substitution (cumulative invert) on A_kk - Matrix multiplies for w and u - Inter-chunk recurrence with state updates **Option 3: CUDA C++ with load_inline** Write inline CUDA. Very powerful but takes more time. Given the complexity and the fact that FLA already has a Triton implementation that I can study, I'll go with a Triton-based approach. But I can't just copy FLA's code - I need to write my own. Let me think about how to structure this: The naive reference has these main phases: 1. **Intra-chunk A_kk build**: For each chunk, compute a BT×BT lower triangular matrix 2. **Forward substitution on A_kk**: Solve (I + A) to get A_inv, then A = A_inv * beta 3. **Compute w = A @ (exp(g) * k)** and **u = A @ v** 4. **Inter-chunk recurrence**: For each chunk, update state S and compute output For a Triton kernel, I need to think about what can be fused: - The intra-chunk A_kk computation can be done per chunk - The forward substitution is small (64×64) but has data dependencies - The inter-chunk recurrence is sequential over chunks For simplicity and correctness, I could: 1. Write a Triton kernel for building A_kk per chunk (fusing the diagonal and off-diagonal) 2. Do forward substitution in PyTorch (or another Triton kernel) 3. Compute w and u with batched matmuls 4. Write a Triton kernel for the inter-chunk recurrence Actually, looking at the shapes: - B=2, T=1024/2048, H=8, K=V=128 - Total chunks = B * H * (T/64) = 2 * 8 * 16 = 256 chunks for T=1024, or 512 for T=2048 For each chunk, we have a 64×64 matrix. The forward substitution on a 64×64 matrix per chunk is very fast in PyTorch. Let me think about a simpler but still custom approach: I can write Triton kernels for the main compute-intensive parts and use PyTorch for the small sequential parts. Actually, let me look at what the FLA Triton kernels do. They have: - `chunk_kda_fwd_kernel_intra_sub_chunk`: computes diagonal 16×16 blocks - `chunk_kda_fwd_kernel_inter_solve_fused`: computes off-diagonal blocks + forward substitution + merge - `recompute_w_u_fwd`: computes w and u from A_inv, k, v, beta - `chunk_gated_delta_rule_fwd_h`: inter-chunk state recurrence - `chunk_gla_fwd_o_gk`: final output computation This is a LOT of kernels. For my solution, I need to balance performance and implementation time. Let me think about a pragmatic approach: 1. First, write a simpler Triton-based solution that decomposes into several kernels but gets correctness 2. Then profile and optimize if needed Actually, wait. Let me re-read the problem more carefully. The user says: "This needs to be a real custom kernel — the whole point of the problem is to write the chunk-parallel attention yourself" And "The intended path is CUTLASS CuTe on SM120 but Triton, CUDA C++ via load_inline, or inline PTX are also fine if you prefer." So Triton is acceptable. But I need to write real custom kernels, not just call PyTorch ops. Let me start by understanding the algorithm very carefully from the reference. ### Algorithm Breakdown (from reference.py) **Inputs**: q, k (B, T, H, K); v (B, T, H, V); g (B, T, H, K); beta (B, T, H); scale **Phase 1: Preprocessing** - Convert to float32 - q = q * scale - Reshape to (B, H, N, C, D) where C=64, N=T/64 - g = g.cumsum(-2) # cumsum within each chunk **Phase 2: Build A_kk (intra-chunk K-K interaction)** ```python A = zeros(B, H, N, C, C) for i in range(C): k_i = k[..., i, :] # (B, H, N, K) g_i = g[..., i:i+1, :] # (B, H, N, 1, K) A[..., i] = einsum("...cd, ...d -> ...c", k * exp(g - g_i), k_i) A = A * beta[..., None] # beta shape (B, H, N, C) -> (B, H, N, C, 1) A = -A.masked_fill(mask_diag_upper, 0) # lower triangular, no diagonal # Forward substitution for i in range(1, C): A[..., i, :i] = A[..., i, :i] + sum_j(A[..., i, j] * A[..., j, :i]) A = (A + I) * beta[..., None, :] # (B, H, N, C, C) ``` **Phase 3: Compute w and u** ```python w = A @ (exp(g) * k) # (B, H, N, C, K) u = A @ v # (B, H, N, C, V) ``` **Phase 4: Inter-chunk recurrence** ```python S = zeros(B, H, K, V) for i in range(N): q_i = q[:, :, i] # (B, H, C, K) k_i = k[:, :, i] # (B, H, C, K) u_i = u[:, :, i] # (B, H, C, V) g_i = g[:, :, i] # (B, H, C, K) w_i = w[:, :, i] # (B, H, C, K) # Compute Aqk (lower triangular, strict upper masked) Aqk = zeros(B, H, C, C) for j in range(C): k_j = k[:, :, i, j] # (B, H, K) g_j = g[:, :, i, j:j+1] # (B, H, 1, K) Aqk[..., j] = einsum("...cd, ...d -> ...c", q_i * exp(g_i - g_j), k_j) Aqk = Aqk.masked_fill(mask_strict_upper, 0) # no diagonal v_i = u_i - w_i @ S # (B, H, C, V) o_i = (q_i * exp(g_i)) @ S + Aqk @ v_i # (B, H, C, V) # Update state S = S * exp(g_i[:, :, -1]).exp().reshape(B, H, K, 1) S = S + rearrange(exp(g_i[:,:,-1:] - g_i) * k_i, "b h c k -> b h k c") @ v_i ``` Wait, `exp(g_i[:, :, -1]).exp()` - that's `exp(exp(g_i[..., -1]))`? That seems wrong. Let me re-read. Actually, in the reference: ```python S = S * rearrange(g_i[:, :, -1].exp(), "b h k -> b h k 1") ``` This is `S = S * exp(g_i[:, :, -1]).unsqueeze(-1)`. But then the next line: ```python S = S + rearrange((g_i[:, :, -1:] - g_i).exp() * k_i, "b h c k -> b h k c") @ v_i ``` Hmm wait, the first line uses `g_i[:, :, -1].exp()` and the second uses `(g_i[:, :, -1:] - g_i).exp()`. Both are `exp(...)` not `exp(exp(...))`. But then there's `exp(g_i[:, :, -1]).exp()` which is `exp(exp(...))`. Let me look more carefully... Oh wait, I misread. The line is: ```python S = S * rearrange(g_i[:, :, -1].exp(), "b h k -> b h k 1") ``` This is `exp(g_i[:, :, -1])` reshaped. Not `exp(exp(...))`. And the next line: ```python S = S + rearrange((g_i[:, :, -1:] - g_i).exp() * k_i, "b h c k -> b h k c") @ v_i ``` This is `exp(g_i[:,:,-1:] - g_i) * k_i`, which makes sense. OK so the state update is: 1. `S = S * exp(g_i[:, :, -1]).unsqueeze(-1)` # decay the state 2. `S = S + (exp(g_i[:,:,-1:] - g_i) * k_i).transpose(-2, -1) @ v_i` # add new contributions This is a standard gated linear attention recurrence. Now, looking at FLA's code more carefully, they use `exp2` (base-2 exponential) rather than `exp` (base-e). The reference uses `.exp()` which is base-e. I need to match the reference exactly. Let me now plan my implementation strategy. ### Strategy: Triton kernels for key compute Given time constraints, I'll implement this with a combination of Triton kernels and PyTorch ops, but the key compute (A_kk build, forward substitution, w/u compute, inter-chunk) will be in Triton. Actually, let me think about what a minimal but effective implementation looks like: **Phase 1**: Cumsum on g - can be done in PyTorch or a simple Triton kernel **Phase 2**: Build A_kk. For each chunk, compute a C×C lower-triangular matrix. This is essentially: ```python for i in range(C): for j in range(i): A[..., i, j] = sum_k(k[..., i, k] * k[..., j, k] * exp(g[..., i, k] - g[..., j, k])) ``` With beta applied. This can be computed as a batched matrix multiply with masking. Actually, for a chunk of size C=64 and K=128: - For each chunk, A is 64×64 - We can compute it as: A = (k.unsqueeze(-2) * k.unsqueeze(-3) * exp(g.unsqueeze(-2) - g.unsqueeze(-3))).sum(-1) - Then apply beta and mask In PyTorch, this would be a huge memory overhead but for C=64 and K=128, it's manageable per chunk. Wait, I can do this more efficiently with einsum: ```python # k shape: (B, H, N, C, K) # g shape: (B, H, N, C, K) # For A_kk: A = torch.einsum("bhnic,bhnjc->bhnij", k * g.exp(), k * (-g).exp()) # But this computes all i,j pairs. We need exp(g_i - g_j), not exp(g_i) * exp(-g_j) # Actually: exp(g_i - g_j) = exp(g_i) * exp(-g_j), so: kg = k * g.exp() # (B, H, N, C, K) kng = k * (-g).exp() # (B, H, N, C, K) A = torch.einsum("bhnic,bhnjc->bhnij", kg, kng) ``` Wait, that's not right either. Let me think: We want `sum_k k[i,k] * k[j,k] * exp(g[i,k] - g[j,k])` = `sum_k (k[i,k] * exp(g[i,k])) * (k[j,k] * exp(-g[j,k]))` So yes: ```python kg_pos = k * g.exp() kg_neg = k * (-g).exp() A = torch.einsum("bhnic,bhnjc->bhnij", kg_pos, kg_neg) ``` But this computes the FULL matrix, including upper triangular. We need to mask it to lower triangular without diagonal. For Aqk: ```python qg_pos = q * g.exp() Aqk = torch.einsum("bhnic,bhnjc->bhnij", qg_pos, kg_neg) ``` And mask to strict lower triangular. This is much more efficient than the naive loop! And for C=64, the 64×64 matrix is tiny. Similarly, the forward substitution: ```python for i in range(1, C): A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2) ``` This is essentially: for each row i, update using all previous rows j < i. In matrix form, if we have L = A[..., :i, :i], then row i update is: `A[i, :i] = A[i, :i] + A[i, :i] @ L`... no wait. Let's expand: `sum_j A[i, j] * A[j, k]` for k < i, j can be anything < i. So for row i: `new_A[i, :i] = A[i, :i] + A[i, :i] @ A[:i, :i]` Wait, that would be `sum_j A[i,j] * A[j,k]` for j in [:i], k in [:i]. Yes! Actually, let me be more careful. The code says: ```python for i in range(1, BT): A[..., i, :i] = A[..., i, :i].clone() + (A[..., i, :, None].clone() * A[..., :, :i].clone()).sum(-2) ``` `A[..., i, :, None]` has shape (..., C, 1) `A[..., :, :i]` has shape (..., C, i) Their elementwise product has shape (..., C, i) Sum over dim -2 (the C dimension): `sum_j A[..., i, j] * A[..., j, k]` for k in [:i] But j ranges over ALL C, not just [:i]. However, A is lower triangular with zeros on and above diagonal, so A[..., i, j] = 0 for j >= i, and A[..., j, k] = 0 for j >= k (and k < i, so j >= i > k means A[j,k] could be non-zero for j < i). Wait, A is lower triangular without diagonal at this point (after `A = -A.masked_fill(mask_diag_upper, 0)`). So A[i, j] = 0 for j >= i. And for k < i, we only need j < i for A[i, j] to be non-zero. So effectively j ranges over [:i]. So: `A[i, :i] += A[i, :i] @ A[:i, :i]` This is a sequential update. For a 64×64 matrix, doing this in PyTorch per chunk is very fast. Actually, let me think about whether I can do this more efficiently in batch. The issue is that each row i depends on rows < i, so it's inherently sequential within a chunk. But across chunks and heads, it's fully parallel. For B=2, H=8, N=32 (T=2048), we have 2*8*32 = 512 independent 64×64 matrices. Doing a Python loop of 64 iterations over 512 matrices in PyTorch is trivial and very fast. So maybe the simplest approach is: 1. Use PyTorch for the small-matrix operations (A_kk build, forward substitution) 2. Use Triton for the large GEMMs and the inter-chunk recurrence Actually, let me reconsider. The main compute is in: 1. Building A_kk and Aqk: involves einsum over K dimension for each pair of positions 2. w = A @ (exp(g)*k): (B,H,N,C,C) @ (B,H,N,C,K) -> (B,H,N,C,K) 3. u = A @ v: (B,H,N,C,C) @ (B,H,N,C,V) -> (B,H,N,C,V) 4. Inter-chunk: q @ S, Aqk @ v_i, k.T @ v_i: these are K×V GEMMs For C=64, K=V=128: - A_kk build: einsum over 128 dim for 64×64 = 512K FLOPs per chunk - w: 64×64×128 = 524K FLOPs per chunk - u: 64×64×128 = 524K FLOPs per chunk - Inter-chunk per chunk: 2×64×128×128 = 2M FLOPs per chunk Total per chunk: ~3.5M FLOPs. For 512 chunks: ~1.8B FLOPs. This is actually not that much. Wait, but the problem says KDA is compute-bound. Let me recalculate. Actually for T=2048, B=2, H=8: - Total chunks = 2 * 8 * 32 = 512 - Per chunk: A_kk (64×64×128) = 524K, w (64×64×128) = 524K, u (64×64×128) = 524K, Aqk (64×64×128) = 524K, q@S (64×128×128) = 2M, Aqk@v_i (64×64×128) = 524K, state update (128×64×128) = 1M - Total per chunk ~6M FLOPs - Total = 512 * 6M = 3B FLOPs At 3B FLOPs, if we want 0.1x peak on RTX PRO 6000 (let's say ~100 TFLOPS peak for bf16), we'd need to run in 30 microseconds, which is unrealistic due to kernel launch overhead. More realistically, we might get ~1-10 TFLOPS, so 0.3-3 ms. Actually, let me check what the actual peak is for RTX PRO 6000. The problem says peak_tflops_key is bf16. Let me check the hardware module.
Shell
args
{
  "command": "<239 chars \u2014 see below>"
}
command (239 chars)
python -c "
import sys
sys.path.insert(0, '/home/infatoshi/cuda/KernelBench-Hard')
from src.hardware import get as get_hw
hw = get_hw('RTX_PRO_6000')
print('Peak TFLOPS:', hw.peak_tflops_dense)
print('Peak GB/s:', hw.peak_bandwidth_gb_s)
"
tool
stdout (243 chars)
<system>Command executed successfully.</system>
Peak TFLOPS: {'fp4': 800.0, 'nvfp4': 800.0, 'mxfp4': 800.0, 'fp6': 800.0, 'fp8': 400.0, 'bf16': 200.0, 'fp16': 200.0, 'tf32': 100.0, 'fp32': 12.0, 'int8': 400.0, 'int4': 800.0}
Peak GB/s: 1800.0
assistant
reasoning (453 chars)
OK so peak is 200 TFLOPS for bf16 on RTX PRO 6000. At 3B FLOPs for the largest shape (B=2,T=2048), we'd need: - At 10% peak = 20 TFLOPS -> 3B/20T = 0.15 ms - At 1% peak = 2 TFLOPS -> 3B/2T = 1.5 ms Given kernel launch overhead and the sequential nature of the inter-chunk recurrence, 0.15 ms is very ambitious. But the SOTA (FLA Triton) probably gets decent performance. Let me first check what performance the SOTA gets on this machine, if available.
ReadFile /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/sota.py
args
{
  "path": "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/sota.py"
}
tool
stdout (3030 chars) — TRUNCATED
<system>71 lines read from file starting from line 1. Total lines in file: 71. End of file reached.</system>
     1	"""SOTA reference for KDA forward: fla.ops.kda.chunk_kda (Triton).
     2	
     3	The agent's solution is forbidden from importing this module path (see
     4	problem.yaml.forbidden). This file is only used by benchmark.py to draw
     5	the SOTA reference line.
     6	
     7	If FLA's Triton kernel does not run on SM120 (Blackwell consumer-lineage --
     8	some Triton kernels in FLA target Hopper TMA), is_available() returns False
     9	and benchmark.py omits the SOTA variant. The H100 reference is documented
    10	in problem.yaml for context.
    11	"""
    12	from __future__ import annotations
    13	
    14	import torch
    15	
    16	
    17	def _import_fla():
    18	    try:
    19	        from fla.ops.kda import chunk_kda  # noqa: F401
    20	        return chunk_kda
    21	    except Exception:
    22	        return None
    23	
    24	
    25	def sota_forward(
    26	    q: torch.Tensor,
    27	    k: torch.Tensor,
    28	    v: torch.Tensor,
    29	    g: torch.Tensor,
    30	    beta: torch.Tensor,
    31	    scale: float | None = None,
    32	) -> torch.Tensor:
    33	    """Run FLA's Triton chunk_kda. Returns o (B, T, H, V) in v's dtype."""
    34	    chunk_kda = _import_fla()
    35	    if chunk_kda is None:
    36	        raise RuntimeError("fla.ops.kda.chunk_kda unavailable")
    37	    # FLA's chunk_kda has a richer signature (A_log, dt_bias

... (1530 more chars)
assistant
reasoning (64 chars)
Let me check if the SOTA runs on this machine to get a baseline.
Shell
args
{
  "command": "<139 chars \u2014 see below>"
}
command (139 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import sota
print('SOTA available:', sota.is_available())
"
tool
stdout (69 chars)
<system>Command executed successfully.</system>
SOTA available: True
assistant
reasoning (232 chars)
Good, the SOTA is available. Let me run benchmark.py to see current performance. But first, I need to create a basic solution.py so benchmark.py can run. Let me create a naive solution based on the reference to establish a baseline.
WriteFile /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
diff (79 lines)
--- /dev/null
+++ b//home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
@@ -0,0 +1,76 @@
+"""Initial naive solution based on reference.py for baseline."""
+from __future__ import annotations
+
+import torch
+import torch.nn as nn
+from einops import rearrange
+
+
+class Model(nn.Module):
+    def __init__(self, B: int, T: int, H: int, K: int, V: int, chunk_size: int = 64):
+        super().__init__()
+        self.B, self.T, self.H, self.K, self.V = B, T, H, K, V
+        self.chunk_size = chunk_size
+        self.scale = float(K) ** -0.5
+        self.register_buffer("_dummy", torch.zeros(1), persistent=False)
+
+    def forward(
+        self,
+        q: torch.Tensor,
+        k: torch.Tensor,
+        v: torch.Tensor,
+        g: torch.Tensor,
+        beta: torch.Tensor,
+    ) -> torch.Tensor:
+        dtype = v.dtype
+        B, T, H, K = q.shape
+        V = v.shape[-1]
+        BT = self.chunk_size
+        assert T % BT == 0
+        NT = T // BT
+
+        q, k, v, g, beta = (x.to(torch.float32) for x in (q, k, v, g, beta))
+        q = q * self.scale
+
+        q = rearrange(q, "b (n c) h d -> b h n c d", c=BT)
+        k = rearrange(k, "b (n c) h d -> b h n c d", c=BT)
+        v = rearrange(v, "b (n c) h d -> b h n c d", c=BT)
+        g = rearrange(g, "b (n c) h d -> b h n c d", c=BT)
+        beta = rearrange(beta, "b (n c) h -> b h n c", c=BT)
+
+        g = g.cumsum(-2)
+
+        mask_diag_upper = torch.triu(torch.ones(BT, BT, dtype=torch.bool, device=q.device), diagonal=0)
+        A = torch.zeros(*q.shape[:-1], BT, dtype=torch.float32, device=q.device)
+        for i in range(BT):
+            k_i = k[..., i, :]
+            g_i = g[..., i:i + 1, :]
+            A[..., i] = torch.einsum("... c d, ... d -> ... c", k * (g - g_i).exp(), k_i)
+        A = A * beta[..., None]
+        A = -A.masked_fill(mask_diag_upper, 0)
+
+        for i in range(1, BT):
+            A[..., i, :i] = A[..., i, :i].clone() + (A[..., i, :, None].clone() * A[..., :, :i].clone()).sum(-2)
+        A = (A + torch.eye(BT, dtype=torch.float32, device=q.device)) * beta[..., None, :]
+
+        w = A @ (g.exp() * k)
+        u = A @ v
+
+        S = q.new_zeros(B, H, K, V)
+        o = torch.zeros_like(v)
+        mask_strict_upper = torch.triu(torch.ones(BT, BT, dtype=torch.bool, device=q.device), diagonal=1)
+        for i in range(NT):
+            q_i, k_i, u_i, g_i, w_i = q[:, :, i], k[:, :, i], u[:, :, i], g[:, :, i], w[:, :, i]
+            Aqk = torch.zeros(B, H, BT, BT, dtype=torch.float32, device=q.device)
+            for j in range(BT):
+                k_j = k[:, :, i, j]
+                g_j = g[:, :, i, j:j + 1, :]
+                Aqk[..., j] = torch.einsum("... c d, ... d -> ... c", q_i * (g_i - g_j).exp(), k_j)
+            Aqk = Aqk.masked_fill(mask_strict_upper, 0)
+            v_i = u_i - w_i @ S
+            o[:, :, i] = (q_i * g_i.exp()) @ S + Aqk @ v_i
+            S = S * rearrange(g_i[:, :, -1].exp(), "b h k -> b h k 1")
+            S = S + rearrange((g_i[:, :, -1:] - g_i).exp() * k_i, "b h c k -> b h k c") @ v_i
+
+        o = rearrange(o, "b h n c d -> b (n c) h d")
+        return o.to(dtype)
args
{
  "path": "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py",
  "content": "<3005 chars \u2014 see diff>"
}
tool
stdout (73 chars)
<system>File successfully overwritten. Current size: 3005 bytes.</system>
assistant
reasoning (114 chars)
Let me run check.py to make sure the naive solution passes, then run benchmark.py to see the baseline performance.
Shell
args
{
  "command": "cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python check.py",
  "timeout": 120
}
tool
stdout (53 chars)
<system>Command executed successfully.</system>
PASS
assistant
reasoning (89 chars)
Good, the naive solution passes. Now let me run benchmark.py to see baseline performance.
Shell
args
{
  "command": "cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python benchmark.py",
  "timeout": 120
}
tool
stdout (348 chars)
<system>ERROR: Command killed by timeout (120s)</system>
/home/infatoshi/.local/lib/python3.12/site-packages/torch/_inductor/compile_fx.py:322: UserWarning: TensorFloat32 tensor cores for float32 matrix multiplication available but not enabled. Consider setting `torch.set_float32_matmul_precision('high')` for better performance.
  warnings.warn(
assistant
reasoning (250 chars)
The benchmark timed out, probably because the naive solution is very slow and the compiled reference is even slower (inductor is compiling). Let me run with a shorter timeout for just the solution to see how slow it is, and skip the compiled version.
Shell
args
{
  "command": "<788 chars \u2014 see below>",
  "timeout": 120
}
command (788 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import solution
import shapes

shape = shapes.SHAPES[1]  # B=2, T=2048
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
ref_model = reference.Model(*init_args).cuda().eval()
sol_model = solution.Model(*init_args).cuda().eval()

torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]

# Warmup
with torch.no_grad():
    _ = sol_model(*inputs)

torch.cuda.synchronize()
import time
start = time.time()
with torch.no_grad():
    for _ in range(10):
        _ = sol_model(*inputs)
torch.cuda.synchronize()
elapsed = (time.time() - start) / 10 * 1000
print(f'Mean ms: {elapsed:.3f}')
"
tool
stdout (64 chars)
<system>Command executed successfully.</system>
Mean ms: 77.779
assistant
reasoning (153 chars)
So the naive solution takes about 78ms for the largest shape. That's very slow. The target is probably a few ms or less. Let me check what the SOTA gets.
Shell
args
{
  "command": "<757 chars \u2014 see below>",
  "timeout": 120
}
command (757 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import sota
import shapes

shape = shapes.SHAPES[1]  # B=2, T=2048
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]
scale = float(shape['K']) ** -0.5

# Warmup
with torch.no_grad():
    _ = sota.sota_forward(*inputs, scale=scale)

torch.cuda.synchronize()
import time
start = time.time()
with torch.no_grad():
    for _ in range(50):
        _ = sota.sota_forward(*inputs, scale=scale)
torch.cuda.synchronize()
elapsed = (time.time() - start) / 50 * 1000
print(f'SOTA mean ms: {elapsed:.3f}')
"
tool
stdout (68 chars)
<system>Command executed successfully.</system>
SOTA mean ms: 0.202
assistant
reasoning (2729 chars)
The SOTA gets 0.202 ms for B=2,T=2048,H=8,K=V=128. That's incredibly fast - about 385x faster than my naive solution. Peak fraction would be: FLOPs = 4 * B * T * H * (K*V + CHUNK_SIZE*K + CHUNK_SIZE*V) = 4 * 2 * 2048 * 8 * (128*128 + 64*128 + 64*128) = 4 * 2 * 2048 * 8 * (16384 + 8192 + 8192) = 4 * 2 * 2048 * 8 * 32768 = 4,294,967,296 ≈ 4.3B FLOPs At 0.202 ms: TFLOPS = 4.3 / 0.202 = 21.3 TFLOPS Peak is 200 TFLOPS, so peak fraction = 21.3/200 = 0.107 = 10.7% For the benchmark, the threshold is RESULT: OK if gmean peak_fraction >= 0.1, else LOW. So I need to get at least ~10% of peak on average across shapes. The SOTA gets about 10.7% on the headline shape. For my solution, I probably need to be at least somewhat close to the SOTA. Now, writing a full FLA-equivalent Triton kernel from scratch is very complex. But I can try a more optimized approach using Triton for the key parts. Let me think about what makes the naive solution so slow: 1. Python loops over BT=64 for building A_kk and Aqk 2. Python loop over NT chunks for the inter-chunk recurrence 3. No fusion The main compute is: - Intra-chunk: A_kk, Aqk construction (GEMM-like) - Forward substitution (small sequential) - w, u computation (batched matmul) - Inter-chunk recurrence (sequential over chunks but GEMM-heavy) For a practical implementation, I can: 1. Use efficient PyTorch ops for the intra-chunk A matrix construction 2. Use a custom Triton kernel for the inter-chunk recurrence to fuse operations Actually, let me think more carefully. Can I get good performance with just well-written PyTorch? For A_kk construction: ```python # k: (B, H, N, C, K) # g: (B, H, N, C, K) # We want A[b,h,n,i,j] = sum_k k[b,h,n,i,k] * k[b,h,n,j,k] * exp(g[b,h,n,i,k] - g[b,h,n,j,k]) kg = k * g.exp() # (B, H, N, C, K) kg_neg = k * (-g).exp() # (B, H, N, C, K) # A = einsum("bhnic,bhnjc->bhnij", kg, kg_neg) # But this creates a (B, H, N, C, C) tensor. For B=2,H=8,N=32,C=64: 2*8*32*64*64 = 2M elements = 8MB. Very manageable! ``` For Aqk: ```python qg = q * g.exp() Aqk = torch.einsum("bhnic,bhnjc->bhnij", qg, kg_neg) ``` Forward substitution on A_kk: For B*H*N = 512 matrices of size 64×64, doing a Python loop over 64 rows is actually very fast in PyTorch because each operation is a vectorized batched operation. The inter-chunk recurrence is the tricky part because it's sequential over N chunks. But each step involves GEMMs of size (C,K) @ (K,V) which are small but numerous. Let me try an optimized PyTorch version first and see how close I can get. Actually, let me look at the FLA implementation for the inter-chunk recurrence to see if I can adapt it. Let me read `chunk_gated_delta_rule_fwd_h` and `chunk_gla_fwd_o_gk` from FLA.
Shell
args
{
  "command": "find /home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops -name \"chunk_delta_h.py\" -o -name \"chunk_gla*\" | head -10"
}
tool
stdout (226 chars)
<system>Command executed successfully.</system>
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/common/chunk_delta_h.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/cp/chunk_delta_h.py
assistant
reasoning (2111 chars)
Let me think about a more strategic approach. The SOTA gets 0.2ms which is extremely fast. To get anywhere close, I need a well-optimized custom kernel. Given the complexity of writing multiple fused Triton kernels from scratch, let me consider a different approach: can I adapt FLA's existing Triton kernels for my use case? The problem says I can't call `fla.ops.kda.chunk_kda` or similar high-level functions, but I could potentially copy and modify their lower-level Triton kernels. Wait, the problem says: "Don't import or call fla.ops.kda, fla.ops.chunk_kda, chunk_kda, fused_recurrent_kda, naive_chunk_kda, or naive_recurrent_kda." It doesn't say I can't look at their code or copy their Triton kernels. But copying their entire codebase would be against the spirit of the problem. However, I can write my own kernels inspired by their approach. Actually, let me reconsider. The problem explicitly says "The intended path is CUTLASS CuTe on SM120." But writing CUTLASS kernels for this complex algorithm would take days. Let me think about what a practical Triton implementation looks like. The key insight from FLA is that they have multiple specialized kernels: 1. `chunk_kda_fwd_kernel_intra_sub_chunk` - computes diagonal blocks 2. `chunk_kda_fwd_kernel_inter_solve_fused` - computes off-diagonal + forward substitution 3. `recompute_w_u_fwd` - computes w and u 4. `chunk_gated_delta_rule_fwd_h` - inter-chunk state recurrence 5. `chunk_gla_fwd_o_gk` - final output For a much simpler but still custom approach, I could write: 1. One Triton kernel for the entire intra-chunk computation (A_kk, forward substitution, w, u, Aqk) 2. One Triton kernel for the inter-chunk recurrence But intra-chunk has a sequential forward substitution step, which is hard to parallelize within a chunk. Alternatively, I could: 1. Use PyTorch for the small sequential intra-chunk forward substitution 2. Write a Triton kernel that fuses the inter-chunk recurrence Actually, let me first see how fast I can get with a well-optimized PyTorch implementation. Let me rewrite the naive solution using vectorized ops.
Shell
args
{
  "command": "<3210 chars \u2014 see below>",
  "timeout": 120
}
command (3210 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import shapes

shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]
q, k, v, g, beta = inputs
scale = float(shape['K']) ** -0.5

B, T, H, K = q.shape
V = v.shape[-1]
BT = 64
NT = T // BT

qf = q.float() * scale
kf = k.float()
vf = v.float()
gf = g.float()
bf = beta.float()

# Reshape
qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)  # B, H, N, C, K
kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4)
gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
bf = bf.view(B, NT, BT, H).permute(0, 2, 1, 3)  # B, H, N, C

gf = gf.cumsum(-2)

# Build A_kk using einsum
kg = kf * gf.exp()
kgn = kf * (-gf).exp()

# B,H,N,C,K @ B,H,N,C,K -> B,H,N,C,C
A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)

mask_upper = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=0)
A = A * bf.unsqueeze(-1)
A = -A.masked_fill(mask_upper, 0)

# Forward substitution
for i in range(1, BT):
    A[:, :, :, i, :i] = A[:, :, :, i, :i] + (A[:, :, :, i, :, None] * A[:, :, :, :, :i]).sum(-2)

I = torch.eye(BT, device=q.device, dtype=torch.float32)
A = (A + I) * bf.unsqueeze(-2)

w = torch.matmul(A, (gf.exp() * kf))  # B,H,N,C,K
u = torch.matmul(A, vf)  # B,H,N,C,V

# Aqk
qg = qf * gf.exp()
Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
mask_strict = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=1)
Aqk = Aqk.masked_fill(mask_strict, 0)

# Inter-chunk
S = qf.new_zeros(B, H, K, V)
o = torch.zeros_like(vf)
for i in range(NT):
    q_i = qf[:, :, i]  # B,H,C,K
    k_i = kf[:, :, i]
    u_i = u[:, :, i]
    g_i = gf[:, :, i]
    w_i = w[:, :, i]
    
    v_i = u_i - torch.matmul(w_i, S)  # B,H,C,V
    qS = torch.matmul(q_i * g_i.exp(), S)  # B,H,C,V
    Av = torch.matmul(Aqk[:, :, i], v_i)  # B,H,C,V
    o[:, :, i] = qS + Av
    
    decay = g_i[:, :, -1].exp().unsqueeze(-1)  # B,H,K,1
    S = S * decay
    
    kg_decay = (g_i[:, :, -1:].unsqueeze(-2) - g_i).exp() * k_i  # B,H,C,K
    S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)

o = o.permute(0, 2, 3, 1, 4).contiguous().view(B, T, H, V)

print('Output shape:', o.shape)
print('Output dtype:', o.dtype)

torch.cuda.synchronize()
import time
start = time.time()
for _ in range(20):
    # just the inter-chunk loop
    S = qf.new_zeros(B, H, K, V)
    o = torch.zeros_like(vf)
    for i in range(NT):
        q_i = qf[:, :, i]
        k_i = kf[:, :, i]
        u_i = u[:, :, i]
        g_i = gf[:, :, i]
        w_i = w[:, :, i]
        
        v_i = u_i - torch.matmul(w_i, S)
        qS = torch.matmul(q_i * g_i.exp(), S)
        Av = torch.matmul(Aqk[:, :, i], v_i)
        o[:, :, i] = qS + Av
        
        decay = g_i[:, :, -1].exp().unsqueeze(-1)
        S = S * decay
        
        kg_decay = (g_i[:, :, -1:].unsqueeze(-2) - g_i).exp() * k_i
        S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)
torch.cuda.synchronize()
print(f'Inter-chunk only: {(time.time()-start)/20*1000:.3f} ms')
"
tool
stdout (238 chars)
<system>ERROR: Command failed with exit code: 1.</system>
Traceback (most recent call last):
  File "<string>", line 43, in <module>
RuntimeError: The size of tensor a (64) must match the size of tensor b (8) at non-singleton dimension 3
assistant
reasoning (45 chars)
I had a shape error with beta. Let me fix it.
Shell
args
{
  "command": "<4556 chars \u2014 see below>",
  "timeout": 120
}
command (4556 chars — TRUNCATED)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import shapes

shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]
q, k, v, g, beta = inputs
scale = float(shape['K']) ** -0.5

B, T, H, K = q.shape
V = v.shape[-1]
BT = 64
NT = T // BT

qf = q.float() * scale
kf = k.float()
vf = v.float()
gf = g.float()
bf = beta.float()

# Reshape: B,T,H,K -> B,H,N,C,K
qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4)
gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2)  # B,H,N,C

gf = gf.cumsum(-2)

# Build A_kk using einsum
kg = kf * gf.exp()
kgn = kf * (-gf).exp()

# B,H,N,C,K @ B,H,N,C,K -> B,H,N,C,C
A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)

mask_upper = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=0)
A = A * bf.unsqueeze(-1)  # B,H,N,C,1
A = -A.masked_fill(mask_upper, 0)

# Forward substitution
for i in range(1, BT):
    A[:, :, :, i, :i] = A[:, :, :, i, :i] + (A[:, :, :, i, :, None] * A[:, :, :, :, :i]).sum(-2)

I = torch.eye(BT, device=q.device, dtype=torch.float32)
A = (A + I) * bf.unsqueeze(-2)  # B,H,N,1,C

w = torch.matmul(A, (gf.exp() * kf))  # B,H,N,C,K
u = torch.matmul(A, vf)  # B,H,N,C,V

# Aqk
qg = qf * gf.exp()
Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
mask_strict = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=1)
Aqk = Aqk.masked_fill(mask_strict, 0)

# Inter-chunk
S = qf.new_zeros(B, H, K, V)
o = torch.zeros_like(vf)
for i in range(NT):
    q_i = qf[:, :, i]  # B,H,C,K
    k_i = kf[:, :, i]
    u_i = u[:, :, i]
    g_i = gf[:, :, i]
    w_i = w[:, :, i]
    
    v_i = u_i - torch.matmul(w_i, S)  # B,H,C,V
    qS = torch.matmul(q_i * g_i.exp(), S)  # B,H,C,V
    Av = torch.matmul(Aqk[:, :, i], v_i)  # B,H,C,V
    o[:, :, i] = qS + Av
    
    decay = g_i[:, :, -1].exp().unsqueeze(-1)  # B,H,K,1
    S = S * decay
    
    kg_decay = (g_i[:, :, -1:].unsqueeze(-2) - g_i).exp() * k_i  # B,H,C,K
    S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)

o = o.permute(0, 2, 3, 1, 4).contiguous().view(B, T, H, V)

print('Output shape:', o.shape)

torch.cuda.synchronize()
import time
start = time.time()
for _ in range(20):
    S = qf.new_zeros(B, H, K, V)
    out = torch.zeros_like(vf)
    for i in range(NT):
        q_i = qf[:, :, i]
        k_i = kf[:, :, i]
        u_i = u[:, :, i]
        g_i = gf[:, :, i]
        w_i = w[:, :, i]
        
        v_i = u_i - torch.matmul(w_i, S)
        qS = torch.matmul(q_i * g_i.exp(), S)
        Av = torch.matmul(Aqk[:, :, i], v_i)
        out[:, :, i] = qS + Av
        
        decay = g_i[:, :, -1].exp().unsqueeze(-1)
        S = S * decay
        
        kg_decay = (g_i[:, :, -1:].unsqueeze(-2) - g_i).exp() * k_i
        S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)
torch.cuda.synchronize()
print(f'Inter-chunk only: {(time.time()-start)/20*1000:.3f} ms')

# Full timing
torch.cuda.synchronize()
start = time.time()
for _ in range(20):
    gf = g.float().view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).cumsum(-2)
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
    A = A * bf.unsqueeze(-1)
    A = -A.masked_fill(mask_upper, 0)
    for i in range(1, BT):
        A[:, :, :, i, :i] = A[:, :, :, i, :i] + (A[:, :, :, i, :, None] * A[:, :, :, :, :i]).sum(-2)
    A = (A + I) * bf.unsqueeze(-2)
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
    Aqk = Aqk.masked_fill(mask_strict, 0)
    
    S = qf.new_zeros(B, H, K, V)
    out = torch.zeros_like(vf)
    for i in range(NT):
        q_i = qf[:, :, i]
        k_i = kf[:, :, i]
   

... (556 more chars)
tool
stdout (237 chars)
<system>ERROR: Command failed with exit code: 1.</system>
Traceback (most recent call last):
  File "<string>", line 80, in <module>
RuntimeError: The size of tensor a (8) must match the size of tensor b (2) at non-singleton dimension 1
assistant
reasoning (596 chars)
There's a shape issue. Let me debug more carefully. The issue is with `bf.unsqueeze(-2)` and `bf.unsqueeze(-1)` having wrong shapes relative to A. `bf` has shape `(B, H, N, C)` = `(2, 8, 32, 64)` `A` has shape `(B, H, N, C, C)` = `(2, 8, 32, 64, 64)` `bf.unsqueeze(-1)` gives `(2, 8, 32, 64, 1)` - should broadcast with A `bf.unsqueeze(-2)` gives `(2, 8, 32, 1, 64)` - should broadcast with A Wait, but then `(A + I) * bf.unsqueeze(-2)` - `I` is `(64, 64)`. A is `(2, 8, 32, 64, 64)`. This should work. Let me look at where the error actually is. Line 80... Let me count lines more carefully.
Shell
args
{
  "command": "<3947 chars \u2014 see below>",
  "timeout": 120
}
command (3947 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import shapes

shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]
q, k, v, g, beta = inputs
scale = float(shape['K']) ** -0.5

B, T, H, K = q.shape
V = v.shape[-1]
BT = 64
NT = T // BT

qf = q.float() * scale
kf = k.float()
vf = v.float()
gf = g.float()
bf = beta.float()

# Reshape: B,T,H,K -> B,H,N,C,K
qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4)
gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2)  # B,H,N,C

print('bf shape:', bf.shape)
gf = gf.cumsum(-2)

# Build A_kk using einsum
kg = kf * gf.exp()
kgn = kf * (-gf).exp()

# B,H,N,C,K @ B,H,N,C,K -> B,H,N,C,C
A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
print('A shape:', A.shape)

mask_upper = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=0)
A = A * bf[..., None]  # B,H,N,C,1
print('After beta:', A.shape)
A = -A.masked_fill(mask_upper, 0)

# Forward substitution
for i in range(1, BT):
    A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)

I = torch.eye(BT, device=q.device, dtype=torch.float32)
A = (A + I) * bf[..., None, :]  # B,H,N,1,C
print('A final shape:', A.shape)

w = torch.matmul(A, (gf.exp() * kf))  # B,H,N,C,K
print('w shape:', w.shape)
u = torch.matmul(A, vf)  # B,H,N,C,V
print('u shape:', u.shape)

# Aqk
qg = qf * gf.exp()
Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
mask_strict = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=1)
Aqk = Aqk.masked_fill(mask_strict, 0)
print('Aqk shape:', Aqk.shape)

# Inter-chunk
S = qf.new_zeros(B, H, K, V)
o = torch.zeros_like(vf)
for i in range(NT):
    q_i = qf[:, :, i]  # B,H,C,K
    k_i = kf[:, :, i]
    u_i = u[:, :, i]
    g_i = gf[:, :, i]
    w_i = w[:, :, i]
    
    v_i = u_i - torch.matmul(w_i, S)  # B,H,C,V
    qS = torch.matmul(q_i * g_i.exp(), S)  # B,H,C,V
    Av = torch.matmul(Aqk[:, :, i], v_i)  # B,H,C,V
    o[:, :, i] = qS + Av
    
    decay = g_i[:, :, -1].exp().unsqueeze(-1)  # B,H,K,1
    S = S * decay
    
    kg_decay = (g_i[:, :, -1:].unsqueeze(-2) - g_i).exp() * k_i  # B,H,C,K
    S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)

o = o.permute(0, 2, 3, 1, 4).contiguous().view(B, T, H, V)
print('o shape:', o.shape)

# Timing
torch.cuda.synchronize()
import time
start = time.time()
for _ in range(50):
    gf = g.float().view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).cumsum(-2)
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    for i in range(1, BT):
        A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
    Aqk = Aqk.masked_fill(mask_strict, 0)
    
    S = qf.new_zeros(B, H, K, V)
    out = torch.zeros_like(vf)
    for i in range(NT):
        q_i = qf[:, :, i]
        k_i = kf[:, :, i]
        u_i = u[:, :, i]
        g_i = gf[:, :, i]
        w_i = w[:, :, i]
        
        v_i = u_i - torch.matmul(w_i, S)
        qS = torch.matmul(q_i * g_i.exp(), S)
        Av = torch.matmul(Aqk[:, :, i], v_i)
        out[:, :, i] = qS + Av
        
        decay = g_i[:, :, -1].exp().unsqueeze(-1)
        S = S * decay
        
        kg_decay = (g_i[:, :, -1:].unsqueeze(-2) - g_i).exp() * k_i
        S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)

torch.cuda.synchronize()
print(f'Full vectorized: {(time.time()-start)/50*1000:.3f} ms')
"
tool
stdout (527 chars)
<system>ERROR: Command failed with exit code: 1.</system>
Traceback (most recent call last):
  File "<string>", line 87, in <module>
RuntimeError: The size of tensor a (8) must match the size of tensor b (2) at non-singleton dimension 1
bf shape: torch.Size([2, 8, 32, 64])
A shape: torch.Size([2, 8, 32, 64, 64])
After beta: torch.Size([2, 8, 32, 64, 64])
A final shape: torch.Size([2, 8, 32, 64, 64])
w shape: torch.Size([2, 8, 32, 64, 128])
u shape: torch.Size([2, 8, 32, 64, 128])
Aqk shape: torch.Size([2, 8, 32, 64, 64])
assistant
reasoning (806 chars)
The error is at line 87, which is: ```python v_i = u_i - torch.matmul(w_i, S) ``` `w_i` has shape `(B, H, C, K)` = `(2, 8, 64, 128)` `S` has shape `(B, H, K, V)` = `(2, 8, 128, 128)` `torch.matmul(w_i, S)` should give `(2, 8, 64, 128)` which matches `u_i` = `(2, 8, 64, 128)`. Wait, but the error says "The size of tensor a (8) must match the size of tensor b (2) at non-singleton dimension 1". That's strange. Actually, `u_i = u[:, :, i]` gives shape `(2, 8, 64, 128)`. Let me check `w_i` and `S` shapes more carefully. Oh wait! `w_i = w[:, :, i]` gives `(2, 8, 64, 128)`. But what about `S`? `S = qf.new_zeros(B, H, K, V)` gives `(2, 8, 128, 128)`. Hmm, matmul of `(2,8,64,128)` and `(2,8,128,128)` should work... Let me check if the error is actually from a different line. Let me add more prints.
Shell
args
{
  "command": "<2403 chars \u2014 see below>",
  "timeout": 120
}
command (2403 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import shapes

shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]
q, k, v, g, beta = inputs
scale = float(shape['K']) ** -0.5

B, T, H, K = q.shape
V = v.shape[-1]
BT = 64
NT = T // BT

qf = q.float() * scale
kf = k.float()
vf = v.float()
gf = g.float()
bf = beta.float()

# Reshape: B,T,H,K -> B,H,N,C,K
qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4)
gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2)  # B,H,N,C

gf = gf.cumsum(-2)

kg = kf * gf.exp()
kgn = kf * (-gf).exp()
A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
mask_upper = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=0)
A = A * bf[..., None]
A = -A.masked_fill(mask_upper, 0)
for i in range(1, BT):
    A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
I = torch.eye(BT, device=q.device, dtype=torch.float32)
A = (A + I) * bf[..., None, :]

w = torch.matmul(A, (gf.exp() * kf))
u = torch.matmul(A, vf)

qg = qf * gf.exp()
Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
mask_strict = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=1)
Aqk = Aqk.masked_fill(mask_strict, 0)

S = qf.new_zeros(B, H, K, V)
print('S shape:', S.shape)
for i in range(NT):
    print(f'Chunk {i}')
    q_i = qf[:, :, i]
    k_i = kf[:, :, i]
    u_i = u[:, :, i]
    g_i = gf[:, :, i]
    w_i = w[:, :, i]
    print('q_i:', q_i.shape)
    print('k_i:', k_i.shape)
    print('u_i:', u_i.shape)
    print('g_i:', g_i.shape)
    print('w_i:', w_i.shape)
    
    v_i = u_i - torch.matmul(w_i, S)
    print('v_i:', v_i.shape)
    qS = torch.matmul(q_i * g_i.exp(), S)
    print('qS:', qS.shape)
    Av = torch.matmul(Aqk[:, :, i], v_i)
    print('Av:', Av.shape)
    
    decay = g_i[:, :, -1].exp().unsqueeze(-1)
    print('decay:', decay.shape)
    S = S * decay
    
    kg_decay = (g_i[:, :, -1:].unsqueeze(-2) - g_i).exp() * k_i
    print('kg_decay:', kg_decay.shape)
    S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)
    print('S:', S.shape)

print('Done')
"
tool
stdout (579 chars)
<system>ERROR: Command failed with exit code: 1.</system>
Traceback (most recent call last):
  File "<string>", line 80, in <module>
RuntimeError: The size of tensor a (8) must match the size of tensor b (2) at non-singleton dimension 1
S shape: torch.Size([2, 8, 128, 128])
Chunk 0
q_i: torch.Size([2, 8, 64, 128])
k_i: torch.Size([2, 8, 64, 128])
u_i: torch.Size([2, 8, 64, 128])
g_i: torch.Size([2, 8, 64, 128])
w_i: torch.Size([2, 8, 64, 128])
v_i: torch.Size([2, 8, 64, 128])
qS: torch.Size([2, 8, 64, 128])
Av: torch.Size([2, 8, 64, 128])
decay: torch.Size([2, 8, 128, 1])
assistant
reasoning (922 chars)
The error is at `kg_decay = (g_i[:, :, -1:].unsqueeze(-2) - g_i).exp() * k_i`. Let me check the shapes: `g_i[:, :, -1:]` has shape `(2, 8, 1, 128)` - wait, no. `g_i` is `(2, 8, 64, 128)`. `g_i[:, :, -1:]` gives `(2, 8, 1, 128)`. Then `.unsqueeze(-2)` gives `(2, 8, 1, 1, 128)`. Then `g_i[:, :, -1:].unsqueeze(-2) - g_i`: - `(2, 8, 1, 1, 128)` - `(2, 8, 64, 128)` - This broadcasts to `(2, 8, 1, 1, 128)` vs `(2, 8, 64, 128)` - mismatch at dim 3 (1 vs 64) Actually, the issue is that `unsqueeze(-2)` adds a dimension at the end, not where I want it. Let me fix: `g_i[:, :, -1:]` has shape `(2, 8, 1, 128)`. I want `(2, 8, 1, 128)` to broadcast with `g_i` of `(2, 8, 64, 128)` for subtraction. That should work without unsqueeze! Wait, `(2, 8, 1, 128) - (2, 8, 64, 128)` broadcasts to `(2, 8, 64, 128)`. That's correct! But I had `.unsqueeze(-2)` which makes it `(2, 8, 1, 1, 128)`. That's wrong. Let me fix the code.
Shell
args
{
  "command": "<3756 chars \u2014 see below>",
  "timeout": 120
}
command (3756 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import shapes

shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]
q, k, v, g, beta = inputs
scale = float(shape['K']) ** -0.5

B, T, H, K = q.shape
V = v.shape[-1]
BT = 64
NT = T // BT

qf = q.float() * scale
kf = k.float()
vf = v.float()
gf = g.float()
bf = beta.float()

# Reshape: B,T,H,K -> B,H,N,C,K
qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4)
gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2)  # B,H,N,C

gf = gf.cumsum(-2)

kg = kf * gf.exp()
kgn = kf * (-gf).exp()
A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
mask_upper = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=0)
A = A * bf[..., None]
A = -A.masked_fill(mask_upper, 0)
for i in range(1, BT):
    A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
I = torch.eye(BT, device=q.device, dtype=torch.float32)
A = (A + I) * bf[..., None, :]

w = torch.matmul(A, (gf.exp() * kf))
u = torch.matmul(A, vf)

qg = qf * gf.exp()
Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
mask_strict = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=1)
Aqk = Aqk.masked_fill(mask_strict, 0)

S = qf.new_zeros(B, H, K, V)
o = torch.zeros_like(vf)
for i in range(NT):
    q_i = qf[:, :, i]
    k_i = kf[:, :, i]
    u_i = u[:, :, i]
    g_i = gf[:, :, i]
    w_i = w[:, :, i]
    
    v_i = u_i - torch.matmul(w_i, S)
    qS = torch.matmul(q_i * g_i.exp(), S)
    Av = torch.matmul(Aqk[:, :, i], v_i)
    o[:, :, i] = qS + Av
    
    decay = g_i[:, :, -1].exp().unsqueeze(-1)  # B,H,K,1
    S = S * decay
    
    # g_i[:, :, -1:] is (B,H,1,128), g_i is (B,H,C,128)
    kg_decay = (g_i[:, :, -1:] - g_i).exp() * k_i  # B,H,C,K
    S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)

o = o.permute(0, 2, 3, 1, 4).contiguous().view(B, T, H, V)

# Check correctness
ref_model = reference.Model(B, T, H, K, V, BT).cuda()
with torch.no_grad():
    ref_out = ref_model(*inputs)

print('Max diff:', (ref_out.float() - o.to(ref_out.dtype).float()).abs().max().item())

# Timing
torch.cuda.synchronize()
import time
start = time.time()
for _ in range(50):
    gf = g.float().view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).cumsum(-2)
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    for i in range(1, BT):
        A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
    Aqk = Aqk.masked_fill(mask_strict, 0)
    
    S = qf.new_zeros(B, H, K, V)
    out = torch.zeros_like(vf)
    for i in range(NT):
        q_i = qf[:, :, i]
        k_i = kf[:, :, i]
        u_i = u[:, :, i]
        g_i = gf[:, :, i]
        w_i = w[:, :, i]
        
        v_i = u_i - torch.matmul(w_i, S)
        qS = torch.matmul(q_i * g_i.exp(), S)
        Av = torch.matmul(Aqk[:, :, i], v_i)
        out[:, :, i] = qS + Av
        
        decay = g_i[:, :, -1].exp().unsqueeze(-1)
        S = S * decay
        
        kg_decay = (g_i[:, :, -1:] - g_i).exp() * k_i
        S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)

torch.cuda.synchronize()
print(f'Full vectorized: {(time.time()-start)/50*1000:.3f} ms')
"
tool
stdout (101 chars)
<system>Command executed successfully.</system>
Max diff: 3.0517578125e-05
Full vectorized: 3.934 ms
assistant
reasoning (1904 chars)
Excellent! The vectorized PyTorch version gets 3.934 ms with a max diff of 3e-05, which is well within tolerance. The SOTA gets 0.202 ms, so I'm about 19x slower. But 3.9 ms might still be decent. Let me calculate the peak fraction: - FLOPs = 4 * 2 * 2048 * 8 * (128*128 + 64*128 + 64*128) ≈ 4.3B - Time = 3.934 ms - TFLOPS = 4.3 / 0.003934 ≈ 1093 GFLOPS = 1.09 TFLOPS - Peak = 200 TFLOPS - Peak fraction = 1.09 / 200 = 0.0055 = 0.55% That's very low. We need at least 10% to pass the benchmark's OK threshold. So I need to be about 18x faster. The main bottleneck in my vectorized version is probably the inter-chunk loop, which has many small kernel launches. Each iteration of the NT=32 loop launches several small GEMMs, and there's significant kernel launch overhead. To get to SOTA performance, I need to fuse the inter-chunk recurrence into a single kernel, similar to what FLA does. Let me think about what's achievable with Triton. I can write: 1. A Triton kernel for the intra-chunk A_kk computation and forward substitution 2. A Triton kernel for the inter-chunk recurrence that processes chunks sequentially within each thread block but parallelizes across B*H For the inter-chunk kernel, each thread block could handle one (B, H) pair and iterate through chunks sequentially. Within each chunk, it would: 1. Load q_i, k_i, v_i (actually u_i, w_i, Aqk are precomputed) 2. Compute v_i = u_i - w_i @ S 3. Compute o_i = (q_i * exp(g_i)) @ S + Aqk @ v_i 4. Update S The challenge is that w_i @ S is (C,K) @ (K,V), which for C=64, K=128, V=128 is a small matmul. Similarly for the others. In Triton, I can tile these operations. For example, with tile sizes of 32 or 64. Actually, let me think about this more carefully. The inter-chunk recurrence in FLA is done by `chunk_gated_delta_rule_fwd_h` and `chunk_gla_fwd_o_gk`. Let me look at these kernels to understand their tiling strategy.
ReadFile /home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/common/chunk_delta_h.py
args
{
  "path": "/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/common/chunk_delta_h.py"
}
tool
stdout (38328 chars) — TRUNCATED
<system>784 lines read from file starting from line 1. Total lines in file: 784. End of file reached.</system>
     1	# Copyright (c) 2023-2026, Songlin Yang, Yu Zhang, Zhiyuan Li
     2	#
     3	# This source code is licensed under the MIT license found in the
     4	# LICENSE file in the root directory of this source tree.
     5	# For a list of all contributors, visit:
     6	#   https://github.com/fla-org/flash-linear-attention/graphs/contributors
     7	
     8	import torch
     9	import triton
    10	import triton.language as tl
    11	
    12	from fla.ops.backends import dispatch
    13	from fla.ops.utils import prepare_chunk_indices, prepare_chunk_offsets
    14	from fla.ops.utils.op import exp, exp2
    15	from fla.utils import IS_NVIDIA_HOPPER, USE_CUDA_GRAPH, autotune_cache_kwargs, check_shared_mem
    16	
    17	NUM_WARPS = [2, 4] if IS_NVIDIA_HOPPER else [2, 4, 8, 16]
    18	
    19	
    20	@triton.heuristics({
    21	    'USE_G': lambda args: args['g'] is not None,
    22	    'USE_GK': lambda args: args['gk'] is not None,
    23	    'USE_INITIAL_STATE': lambda args: args['h0'] is not None,
    24	    'STORE_FINAL_STATE': lambda args: args['ht'] is not None,
    25	    'SAVE_NEW_VALUE': lambda args: args['v_new'] is not None,
    26	    'IS_VARLEN': lambda args: args['cu_seqlens'] is not None,
    27	})
    28	@triton.autotune(
    29	    configs=[
    30	        triton.Config({'BV': BV}, num_warps=num_warps, num_stages=num_stages)
    31	        for num_warps in

... (36828 more chars)
assistant
reasoning (3266 chars)
This FLA kernel is very sophisticated. It tiles the state S into 64×BV blocks and processes chunks sequentially within each thread block. The key insight is: - Each thread block handles one (batch, head) and one tile of V dimension - K is always handled in 64-wide tiles (since K=128, it's 2 tiles) - V is tiled by BV (32 or 64) For my implementation, I can take a simpler approach. Since K=V=128, and chunk_size=64, I can write a Triton kernel that: 1. Each thread block handles one (B, H) pair 2. Loads the entire K×V state (128×128 = 16K floats = 64KB) into shared memory 3. Iterates through chunks sequentially 4. Within each chunk, computes the required matmuls But 64KB of shared memory for the state is a lot. On SM120, shared memory is probably 228KB per SM, so 64KB is feasible but might limit occupancy. Alternatively, I can tile V into smaller chunks and have multiple thread blocks per (B, H) pair, similar to FLA. Actually, for a simpler kernel, I can just have each thread block handle one (B, H) and process all V channels. With K=V=128, the state is 128×128 floats = 64KB. If I use fp32 accumulators, that's fine. For the intermediate computations (v_i, o_i), I need C×V = 64×128 = 8K floats = 32KB. Total shared memory: 64KB (state) + 32KB (v_i) + some for loading q, k, w, etc. = ~100-120KB. This is reasonable. Actually, in Triton we don't explicitly manage shared memory - the compiler does it for us. But we can reason about register pressure. For K=128, V=128, C=64: - State S: 128×128 fp32 = 16K elements - Loading q_i: 64×128 = 8K elements - Loading k_i: 64×128 = 8K elements - Loading w_i: 64×128 = 8K elements - Loading u_i: 64×128 = 8K elements - Loading Aqk: 64×64 = 4K elements - v_i: 64×128 = 8K elements - o_i: 64×128 = 8K elements If each thread block has 128 threads (4 warps), each thread would need to hold ~500 fp32 values in registers if we loaded everything. That's too much. So we need to tile. Let's tile V into 64-wide chunks. Then: - State tile: 128×64 = 8K fp32 - v_i tile: 64×64 = 4K fp32 - o_i tile: 64×64 = 4K fp32 And we process K in 64-wide chunks too for the matmuls. This is similar to FLA's approach but simpler. Let me think about the kernel design: **Grid**: (V_tiles, B*H) where V_tiles = V // BV = 128 // 64 = 2 **Tile sizes**: BV=64 for V, BK=64 for K For each thread block (i_v, i_bh): - i_v = tile index in V dimension (0 or 1) - i_bh = batch*head index State S_tile = zeros(128, 64) fp32 For each chunk i in 0..NT-1: 1. Load u_i[:, i_v*BV:(i_v+1)*BV] -> (64, 64) 2. Load w_i in K tiles of 64: w_i1, w_i2 -> (64, 64) each 3. Compute v_i = u_i - w_i @ S_tile - w_i1 (64,64) @ S_tile1 (64,64) -> partial - w_i2 (64,64) @ S_tile2 (64,64) -> partial 4. Load q_i in K tiles, g_i in K tiles 5. Compute qS = (q_i * exp(g_i)) @ S_tile 6. Load Aqk (64,64) 7. Compute Aqk @ v_i 8. o_i = qS + Aqk @ v_i 9. Store o_i 10. Update S: - decay = exp(g_i[:, -1]) # (128,) - S_tile *= decay[:, None] - Load k_i in K tiles - Compute kg_decay = exp(g_i[-1:] - g_i) * k_i # (64, 128) - S_tile += kg_decay.T @ v_i This is getting complex. Let me look at how FLA's `chunk_gla_fwd_o_gk` works since it's similar to what I need for the output computation.
Shell
args
{
  "command": "find /home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla -name \"*.py\" | head -10"
}
tool
stdout (467 chars)
<system>Command executed successfully.</system>
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/fused_chunk.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/__init__.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/naive.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/fused_recurrent.py
/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/chunk.py
assistant
reasoning (90 chars)
Let me look at the chunk_gla_fwd_o_gk kernel to understand the output computation pattern.
Shell
args
{
  "command": "grep -n \"chunk_gla_fwd_o_gk\" /home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/chunk.py | head -10"
}
tool
stdout (109 chars)
<system>Command executed successfully.</system>
877:def chunk_gla_fwd_o_gk(
1127:    o = chunk_gla_fwd_o_gk(
assistant
reasoning (64 chars)
Let me read the chunk_gla_fwd_o_gk function from FLA's chunk.py.
ReadFile /home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/chunk.py
args
{
  "path": "/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/chunk.py",
  "line_offset": 877,
  "n_lines": 200
}
tool
stdout (6519 chars) — TRUNCATED
<system>200 lines read from file starting from line 877. Total lines in file: 1391.</system>
   877	def chunk_gla_fwd_o_gk(
   878	    q: torch.Tensor,
   879	    v: torch.Tensor,
   880	    g: torch.Tensor,
   881	    A: torch.Tensor,
   882	    h: torch.Tensor,
   883	    scale: float,
   884	    cu_seqlens: torch.LongTensor | None = None,
   885	    chunk_size: int = 64,
   886	    chunk_indices: torch.LongTensor | None = None,
   887	    use_exp2: bool = False,
   888	    transpose_state_layout: bool = False,
   889	):
   890	    B, T, H, K, HV, V = *q.shape, v.shape[2], v.shape[-1]
   891	    BT = chunk_size
   892	
   893	    if chunk_indices is None and cu_seqlens is not None:
   894	        chunk_indices = prepare_chunk_indices(cu_seqlens, chunk_size)
   895	    NT = triton.cdiv(T, BT) if cu_seqlens is None else len(chunk_indices)
   896	
   897	    # Please ensure zeros, since vllm will use padding v
   898	    o = torch.zeros_like(v)
   899	    def grid(meta): return (triton.cdiv(V, meta['BV']), NT, B * HV)
   900	    chunk_gla_fwd_kernel_o[grid](
   901	        q=q,
   902	        v=v,
   903	        g=g,
   904	        h=h,
   905	        o=o,
   906	        A=A,
   907	        cu_seqlens=cu_seqlens,
   908	        chunk_indices=chunk_indices,
   909	        scale=scale,
   910	        T=T,
   911	        H=H,
   912	        HV=HV,
   913	        K=K,
   914	        V=V,
   915	        BT=BT,
   916	        USE_EXP2=use_exp2,
   917	        TRANSPOSE_STATE=transpo

... (5019 more chars)
assistant
reasoning (106 chars)
Let me look at the `chunk_gla_fwd_kernel_o` Triton kernel to understand how FLA computes the final output.
Shell
args
{
  "command": "grep -n \"chunk_gla_fwd_kernel_o\" /home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/chunk.py | head -5"
}
tool
stdout (118 chars)
<system>Command executed successfully.</system>
313:def chunk_gla_fwd_kernel_o(
900:    chunk_gla_fwd_kernel_o[grid](
assistant
reasoning (46 chars)
Let me read the chunk_gla_fwd_kernel_o kernel.
ReadFile /home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/chunk.py
args
{
  "path": "/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/gla/chunk.py",
  "line_offset": 313,
  "n_lines": 200
}
tool
stdout (8970 chars) — TRUNCATED
<system>200 lines read from file starting from line 313. Total lines in file: 1391.</system>
   313	def chunk_gla_fwd_kernel_o(
   314	    q,
   315	    v,
   316	    g,
   317	    h,
   318	    o,
   319	    A,
   320	    cu_seqlens,
   321	    chunk_indices,
   322	    scale,
   323	    T,
   324	    H: tl.constexpr,
   325	    HV: tl.constexpr,
   326	    K: tl.constexpr,
   327	    V: tl.constexpr,
   328	    BT: tl.constexpr,
   329	    BK: tl.constexpr,
   330	    BV: tl.constexpr,
   331	    USE_EXP2: tl.constexpr,
   332	    TRANSPOSE_STATE: tl.constexpr,
   333	    IS_VARLEN: tl.constexpr,
   334	):
   335	    i_v, i_t, i_bh = tl.program_id(0), tl.program_id(1), tl.program_id(2)
   336	    i_b, i_hv = i_bh // HV, i_bh % HV
   337	    i_h = i_hv // (HV // H)
   338	    if IS_VARLEN:
   339	        i_tg = i_t.to(tl.int64)
   340	        i_n, i_t = tl.load(chunk_indices + i_t * 2).to(tl.int32), tl.load(chunk_indices + i_t * 2 + 1).to(tl.int32)
   341	        bos, eos = tl.load(cu_seqlens + i_n).to(tl.int64), tl.load(cu_seqlens + i_n + 1).to(tl.int64)
   342	        T = eos - bos
   343	        NT = tl.cdiv(T, BT)
   344	    else:
   345	        NT = tl.cdiv(T, BT)
   346	        i_tg = (i_b * NT + i_t).to(tl.int64)
   347	        bos, eos = (i_b * T).to(tl.int64), (i_b * T + T).to(tl.int64)
   348	
   349	    m_s = tl.arange(0, BT)[:, None] >= tl.arange(0, BT)[None, :]
   350	
   351	    q += (bos * H + i_h) * K
   352	    g += (bos * HV + i_hv) * K
   353	    v += (bos

... (7470 more chars)
assistant
reasoning (846 chars)
OK, now I have a good understanding of the FLA kernels. Let me think about a practical implementation strategy. The FLA implementation splits the work into multiple kernels: 1. Intra-chunk: computes A_kk and Aqk 2. Inter-chunk state: `chunk_gated_delta_rule_fwd_h` computes the recurrent state h and v_new 3. Output: `chunk_gla_fwd_o_gk` computes the final output using h, v_new, Aqk For my implementation, I can try a hybrid approach: 1. Use PyTorch for the intra-chunk A computation (it's small and fast when vectorized) 2. Write a custom Triton kernel for the inter-chunk recurrence that fuses everything Actually, looking at my vectorized PyTorch timing (3.9ms), the bottleneck is clearly the inter-chunk loop with many small kernel launches. The intra-chunk part is probably a small fraction. Let me measure the breakdown more carefully.
Shell
args
{
  "command": "<2962 chars \u2014 see below>",
  "timeout": 120
}
command (2962 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import shapes

shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]
q, k, v, g, beta = inputs
scale = float(shape['K']) ** -0.5

B, T, H, K = q.shape
V = v.shape[-1]
BT = 64
NT = T // BT

qf = q.float() * scale
kf = k.float()
vf = v.float()
gf = g.float()
bf = beta.float()

qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4)
gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2)

mask_upper = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=0)
mask_strict = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=1)
I = torch.eye(BT, device=q.device, dtype=torch.float32)

gf = gf.cumsum(-2)

# Time intra-chunk only
torch.cuda.synchronize()
import time
start = time.time()
for _ in range(100):
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    for i in range(1, BT):
        A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
    Aqk = Aqk.masked_fill(mask_strict, 0)
torch.cuda.synchronize()
print(f'Intra-chunk: {(time.time()-start)/100*1000:.3f} ms')

# Precompute for inter-chunk timing
kg = kf * gf.exp()
kgn = kf * (-gf).exp()
A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
A = A * bf[..., None]
A = -A.masked_fill(mask_upper, 0)
for i in range(1, BT):
    A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
A = (A + I) * bf[..., None, :]
w = torch.matmul(A, (gf.exp() * kf))
u = torch.matmul(A, vf)
qg = qf * gf.exp()
Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
Aqk = Aqk.masked_fill(mask_strict, 0)

torch.cuda.synchronize()
start = time.time()
for _ in range(100):
    S = qf.new_zeros(B, H, K, V)
    out = torch.zeros_like(vf)
    for i in range(NT):
        q_i = qf[:, :, i]
        k_i = kf[:, :, i]
        u_i = u[:, :, i]
        g_i = gf[:, :, i]
        w_i = w[:, :, i]
        
        v_i = u_i - torch.matmul(w_i, S)
        qS = torch.matmul(q_i * g_i.exp(), S)
        Av = torch.matmul(Aqk[:, :, i], v_i)
        out[:, :, i] = qS + Av
        
        decay = g_i[:, :, -1].exp().unsqueeze(-1)
        S = S * decay
        
        kg_decay = (g_i[:, :, -1:] - g_i).exp() * k_i
        S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)
torch.cuda.synchronize()
print(f'Inter-chunk: {(time.time()-start)/100*1000:.3f} ms')
"
tool
stdout (92 chars)
<system>Command executed successfully.</system>
Intra-chunk: 2.355 ms
Inter-chunk: 2.563 ms
assistant
reasoning (6239 chars)
So intra-chunk is 2.355ms and inter-chunk is 2.563ms, totaling about 4.9ms per forward pass (but my earlier measurement was 3.9ms - probably due to different number of iterations and caching). Anyway, both are significant. To get to SOTA-level performance (~0.2ms), I need to be about 10-20x faster. The main wins would come from: 1. Fusing the inter-chunk recurrence into a single Triton kernel 2. Optimizing the intra-chunk computation (especially the forward substitution) For the inter-chunk kernel, I can write a Triton kernel similar to FLA's `chunk_gated_delta_rule_fwd_kernel_h_blockdim64` but also computing the output o in the same pass, since we don't need to save intermediate states. Actually, looking more carefully at FLA's code: - `chunk_gated_delta_rule_fwd_h` computes `h` (states) and `v_new` (v_i in our notation) - `chunk_gla_fwd_o_gk` computes the final output using `h` and `v_new` These are two separate kernels. But for our case, we can potentially fuse them into one kernel that: 1. Processes chunks sequentially 2. Maintains state S in registers/shared memory 3. Computes v_i, o_i, and updates S all in one loop For K=V=128, if each thread block handles one (B,H) and tiles V by BV=64, we'd need 2 thread blocks per (B,H). With B=2, H=8, that's 32 thread blocks. For T=2048, each thread block processes 32 chunks. This is very manageable. Let me think about the kernel structure more concretely: ```python @triton.jit def kda_fwd_inter_kernel( q, k, v, w, u, g, Aqk, o, B, T, H, K, V, BT, BK: tl.constexpr, BV: tl.constexpr, ): i_v, i_bh = tl.program_id(0), tl.program_id(1) i_b, i_h = i_bh // H, i_bh % H # State S is (K, V) but we tile V # S_tile = zeros(K, BV) in fp32 # We'll process K in tiles of BK=64 # Pointers q_ptr = q + (i_b * T * H + i_h) * K k_ptr = k + (i_b * T * H + i_h) * K # ... similar for others NT = T // BT for i_t in range(NT): # Load u_i tile (BT, BV) # Load w_i in K tiles # Compute v_i = u_i - w_i @ S # Load q_i, g_i in K tiles # Compute qS = (q_i * exp(g_i)) @ S # Load Aqk (BT, BT) # Compute o_i = qS + Aqk @ v_i # Store o_i # Update S: # decay = exp(g_i[:, -1]) # S *= decay # kg = exp(g_last - g_i) * k_i # S += kg.T @ v_i ``` The main issue is that S is (K, V) = (128, 128). Tiled by BV=64, each tile is (128, 64) = 8K fp32 values. In Triton, if we use `tl.zeros([128, 64], dtype=tl.float32)`, that's 32KB of registers/shared memory. With 128 threads, each thread holds 64 fp32 values, which is reasonable. Actually, Triton might not handle a 128×64 accumulator well. FLA breaks K into 64-wide chunks: ```python b_h1 = tl.zeros([64, BV], dtype=tl.float32) b_h2 = tl.zeros([64, BV], dtype=tl.float32) # if K > 64 ``` For K=128, they use 2 tiles of 64×BV. For BV=64, each tile is 64×64 = 4K fp32 = 16KB. Two tiles = 32KB. This is very reasonable. Let me adapt this approach. For K=128, V=128, BV=64: - S1 = zeros(64, 64) fp32 - S2 = zeros(64, 64) fp32 For each chunk: 1. Load u_i[:, i_v*BV:(i_v+1)*BV] -> (64, 64) 2. Load w_i[:, 0:64] -> (64, 64) v_i = u_i - w_i @ S1 3. Load w_i[:, 64:128] -> (64, 64) v_i = v_i - w_i @ S2 4. Load q_i[:, 0:64], g_i[:, 0:64] qS1 = (q_i * exp(g_i)) @ S1 5. Load q_i[:, 64:128], g_i[:, 64:128] qS2 = (q_i * exp(g_i)) @ S2 qS = qS1 + qS2 6. Load Aqk -> (64, 64) o_i = qS + Aqk @ v_i 7. Store o_i 8. Update S: decay1 = exp(g_i[-1, 0:64]) S1 *= decay1[:, None] decay2 = exp(g_i[-1, 64:128]) S2 *= decay2[:, None] k_i1 = load k[:, 0:64] kg1 = exp(g_last1 - k_g1) * k_i1 # wait, need to be careful For the state update, we need exp(g_i[-1:] - g_i) * k_i: - For K tile 1: exp(g_last1 - g_i1) * k_i1 -> (64, 64) - v_i is (64, 64) - S1 += (kg1).T @ v_i = (64, 64) @ (64, 64) -> but kg1.T is (64, 64) and v_i is (64, 64), so dot gives (64, 64) ✓ This is very similar to FLA's kernel but we also compute o_i in the same pass. Wait, actually the `chunk_gated_delta_rule_fwd_kernel_h_blockdim64` already computes v_i (called b_v in their code) and updates the state. We just need to add the output computation. But we also need to apply `scale` to q. In FLA's output kernel, they multiply by scale at the end. We can do the same. Let me also think about the data layout. The inputs are (B, T, H, K) for q/k/g and (B, T, H, V) for v. But FLA uses a different layout for some tensors to support GVA (grouped value attention). For our case, H = HV (no GVA), so the layouts are simpler. Actually, looking at FLA's `chunk_gated_delta_rule_fwd_h`, `w` and `u` have shape (B, T, H, K) and (B, T, H, V) respectively, but with `HV` heads for values. Since H=HV in our case, it's straightforward. Wait, looking at the FLA code more carefully, `w` is per-value-head, but `k` is per-query-key-head. In our case H=HV so they're the same. Let me write a simplified Triton kernel that handles just our specific case (no GVA, fixed chunk size 64, K=V=128, no initial state, no final state). Actually, let me think about whether I can get away with a simpler approach. Since the intra-chunk part takes 2.3ms and the inter-chunk takes 2.5ms, maybe I can: 1. Keep the intra-chunk in PyTorch but optimize it further 2. Write a single Triton kernel for the inter-chunk recurrence + output For the intra-chunk, I could try using `torch.compile` on a custom function, or I could just accept the 2.3ms and focus on optimizing the inter-chunk. But 2.3ms + 0.5ms = 2.8ms, which is still 14x slower than SOTA. I need both parts to be faster. Actually, wait. Let me check if my timing includes some overhead. Let me run with CUDA graphs or just more iterations. Also, let me check if I can use `torch.bmm` instead of `einsum` for some operations. Actually, the einsum for A_kk can be rewritten as: ```python A = torch.matmul(kg.unsqueeze(-2), kgn.unsqueeze(-1)).squeeze(-1) ``` Wait no. `kg` is (B,H,N,C,K), `kgn` is (B,H,N,C,K). We want A[b,h,n,i,j] = sum_k kg[b,h,n,i,k] * kgn[b,h,n,j,k]. This is: reshape to (B*H*N, C, K), then A_flat = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1)), reshape back. Let me try this.
Shell
args
{
  "command": "<2645 chars \u2014 see below>",
  "timeout": 120
}
command (2645 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import shapes

shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]
q, k, v, g, beta = inputs
scale = float(shape['K']) ** -0.5

B, T, H, K = q.shape
V = v.shape[-1]
BT = 64
NT = T // BT

qf = q.float() * scale
kf = k.float()
vf = v.float()
gf = g.float()
bf = beta.float()

qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4)
gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2)

mask_upper = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=0)
mask_strict = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=1)
I = torch.eye(BT, device=q.device, dtype=torch.float32)

gf = gf.cumsum(-2)

# Precompute masks once

# Time with bmm instead of einsum
torch.cuda.synchronize()
import time
start = time.time()
for _ in range(200):
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    
    # Using bmm
    BHN = B * H * NT
    kg_flat = kg.reshape(BHN, BT, K)
    kgn_flat = kgn.reshape(BHN, BT, K)
    A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1)).view(B, H, NT, BT, BT)
    
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    for i in range(1, BT):
        A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    qg_flat = qg.reshape(BHN, BT, K)
    Aqk = torch.bmm(qg_flat, kgn_flat.transpose(-2, -1)).view(B, H, NT, BT, BT)
    Aqk = Aqk.masked_fill(mask_strict, 0)
torch.cuda.synchronize()
print(f'With bmm: {(time.time()-start)/200*1000:.3f} ms')

# Original einsum
torch.cuda.synchronize()
start = time.time()
for _ in range(200):
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    for i in range(1, BT):
        A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
    Aqk = Aqk.masked_fill(mask_strict, 0)
torch.cuda.synchronize()
print(f'With einsum: {(time.time()-start)/200*1000:.3f} ms')
"
tool
stdout (89 chars)
<system>Command executed successfully.</system>
With bmm: 1.808 ms
With einsum: 1.327 ms
assistant
reasoning (2137 chars)
Interesting! einsum is actually faster than bmm in this case. Probably because einsum can use a more optimized contraction path. Let me try to optimize the forward substitution loop, which might be a significant bottleneck. For the forward substitution, I'm doing: ```python for i in range(1, BT): A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2) ``` This involves a Python loop over 64 iterations. Each iteration does batched ops on tensors of shape (B*H*N, 1, i) and (B*H*N, C, i). For large i, this is a decent-sized matmul. But for small i, it's very small. Actually, I can vectorize this further. The operation is: For each matrix A of shape (C, C), we want to compute: for i in range(1, C): A[i, :i] = A[i, :i] + A[i, :] @ A[:, :i] But A[i, j] = 0 for j >= i, so A[i, :] @ A[:, :i] = A[i, :i] @ A[:i, :i] So the update is: A[i, :i] += A[i, :i] @ A[:i, :i] This is still sequential. But we can use the fact that this is essentially computing a matrix power series. Actually, this is computing (I + A)^{-1} through forward substitution. For a 64×64 matrix, a custom CUDA kernel would be ideal, but in PyTorch we might just accept the loop. Wait, there's actually a more efficient way. This is computing the inverse of (I - L) where L is strictly lower triangular. The inverse is I + L + L^2 + L^3 + ... + L^{C-1}. We can compute this by repeated squaring! Actually, (I - L)^{-1} = I + L + L^2 + ... . Since L is nilpotent (L^C = 0), we can compute it as: S = I for _ in range(log2(C)): S = S + S @ (L @ S) # or something similar Wait, that's not quite right either. Let me think... For forward substitution on (I - L)x = b, the solution is x = (I + L + L^2 + ...)b. The matrix inverse is (I - L)^{-1} = sum_{k=0}^{C-1} L^k. We can compute this by binary splitting: - Compute L^2, L^4, L^8, ... by repeated squaring - Then the sum is I + L + L^2 + L^3 + ... Actually, there's a well-known parallel algorithm for this. We can compute the prefix products. But in PyTorch, for C=64, the loop might just be fine. Let me profile the forward substitution to see how much time it takes.
Shell
args
{
  "command": "<720 chars \u2014 see below>",
  "timeout": 60
}
command (720 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import time

BHN = 512  # B*H*N for T=2048
C = 64
A = torch.randn(BHN, C, C, device='cuda')

# Time forward substitution
torch.cuda.synchronize()
start = time.time()
for _ in range(1000):
    A_copy = A.clone()
    for i in range(1, C):
        A_copy[:, i, :i] = A_copy[:, i, :i] + (A_copy[:, i, :, None] * A_copy[:, :, :i]).sum(-2)
torch.cuda.synchronize()
print(f'Forward substitution: {(time.time()-start)/1000*1000:.3f} ms')

# Compare to full matmul
torch.cuda.synchronize()
start = time.time()
for _ in range(1000):
    _ = torch.bmm(A, A)
torch.cuda.synchronize()
print(f'BMM: {(time.time()-start)/1000*1000:.3f} ms')
"
tool
stdout (93 chars)
<system>Command executed successfully.</system>
Forward substitution: 1.222 ms
BMM: 0.049 ms
assistant
reasoning (9006 chars)
The forward substitution loop takes 1.2ms, which is a huge bottleneck. A single BMM of the same size takes only 0.049ms, so the loop is ~25x slower than it should be. This is because the loop has 64 iterations, and each iteration launches a small kernel. The kernel launch overhead dominates. To fix this, I need to either: 1. Write a custom CUDA kernel for the forward substitution 2. Find a way to parallelize it 3. Use a different algorithm For option 2, there is actually a parallel prefix-based algorithm for matrix inversion of triangular matrices. We can use the "parallel cyclic reduction" or "divide and conquer" approach. For a lower triangular matrix L, the forward substitution for (I - L)^{-1} can be computed recursively: - Split L into blocks: L = [L11, 0; L21, L22] - Then (I - L)^{-1} = [(I-L11)^{-1}, 0; (I-L22)^{-1} @ L21 @ (I-L11)^{-1}, (I-L22)^{-1}] This is a divide-and-conquer approach that can be parallelized! For C=64, we can do: - Level 0: Split into 2×2 blocks of size 32 - Level 1: Each 32 block splits into 2×2 blocks of size 16 - etc. At the leaf level (size 1), the inverse is trivial (just 1). Then we merge level by level. This is much more parallel and can be done with batched matrix multiplications! Let me write this out for C=64: - Level 0 (leaf): blocks of size 1. There are 64 diagonal blocks, each is [1]. The strictly lower blocks are just 0. - Level 1: merge pairs of size-1 blocks into size-2 blocks. For a size-2 block [1, 0; l21, 1], the inverse is [1, 0; -l21, 1]. Wait, but in our case, the matrix is (I + A) where A is strictly lower triangular. Actually, we want to compute (I + A)^{-1} where A is the lower-triangular matrix after applying -A.masked_fill and the forward substitution. Wait, let me re-read the reference more carefully. In the reference: 1. A = einsum(k * exp(g - g_i), k_i) * beta 2. A = -A.masked_fill(upper, 0) # strictly lower triangular, negated 3. Forward substitution: for i: A[i, :i] += A[i, :] @ A[:, :i] 4. A = (A + I) * beta[..., None, :] So after step 3, A is (I - L)^{-1} for some strictly lower triangular L. Then step 4 multiplies by beta on the right. Actually wait. After step 2, A is -L where L is strictly lower triangular with the original values. Step 3 computes the forward substitution on -L. If we define M = I - (-L) = I + L, then step 3 computes M^{-1}. Wait no... Let's trace carefully. After step 2: A[i, j] = -L[i, j] for i > j, where L[i, j] = einsum(k_j * exp(g_j - g_i), k_i) * beta_i Wait, in the reference: ```python A[..., i] = torch.einsum("... c d, ... d -> ... c", k * (g - g_i).exp(), k_i) A = A * beta[..., None] A = -A.masked_fill(mask_diag_upper, 0) ``` So A[i, j] = -beta_i * sum_d k[j,d] * k[i,d] * exp(g[j,d] - g[i,d]) for j < i. Then the forward substitution: ```python for i in range(1, BT): A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2) ``` This is: new_A[i, j] = A[i, j] + sum_k A[i, k] * A[k, j] for j < i, k < i. Since A[i, k] = 0 for k >= i, and A[k, j] = 0 for k <= j, the sum is over j < k < i. This is computing: A = A + A^2 + A^3 + ... = A * (I + A + A^2 + ...) = A * (I - A)^{-1} Wait, if A is strictly lower triangular, then I - A is invertible, and (I - A)^{-1} = I + A + A^2 + A^3 + ... So after the loop, we have: A_final = A + A^2 + A^3 + ... = A * (I - A)^{-1} = (I - A)^{-1} - I Then: A = (A_final + I) * beta = (I - A)^{-1} * beta Ah! So the forward substitution computes (I - A)^{-1} where A is the original strictly lower triangular matrix (before the loop). And then we multiply by beta. So if I can compute (I - A)^{-1} efficiently, that's the key. For a strictly lower triangular matrix, there is indeed a divide-and-conquer approach: Given A of size C×C, strictly lower triangular. Split into 4 blocks of size C/2: A = [A11, 0; A21, A22] Then I - A = [I - A11, 0; -A21, I - A22] The inverse is: (I - A)^{-1} = [(I-A11)^{-1}, 0; (I-A22)^{-1} @ A21 @ (I-A11)^{-1}, (I-A22)^{-1}] This can be computed recursively! For C=64: - Base case: C=1, (I - A)^{-1} = [1] - Level 1: C=2, compute inverses of two 1×1 blocks, then the off-diagonal - Level 2: C=4, compute inverses of two 2×2 blocks, then the off-diagonal - ... - Level 6: C=64 At each level, for B*H*N = 512 matrices, we do: 1. Two inverses of size C/2 (computed recursively in parallel) 2. One matmul: (C/2, C/2) @ (C/2, C/2) @ (C/2, C/2) for the off-diagonal For C=64, at each level the total matmul size is 512 × (C/2)^3 FLOPs. Summing over levels: - Level 1 (C=2): 512 × 1^3 = 512 FLOPs - Level 2 (C=4): 512 × 2^3 = 4096 FLOPs - Level 3 (C=8): 512 × 4^3 = 32768 FLOPs - Level 4 (C=16): 512 × 8^3 = 262K FLOPs - Level 5 (C=32): 512 × 16^3 = 2M FLOPs - Level 6 (C=64): 512 × 32^3 = 16.7M FLOPs Total: ~19.3M FLOPs. At 200 TFLOPS, this is 0.0001 ms. Of course, the actual time is dominated by kernel launch overhead and memory movement, not compute. But even if each level takes 0.01ms, total is 0.06ms, which is 20x faster than the 1.2ms loop! Let me implement this divide-and-conquer approach in PyTorch. Actually, I realize there's an even simpler way. Since C=64 is a power of 2, I can implement the divide-and-conquer iteratively: ```python def tri_inverse(A): """A is (..., C, C) strictly lower triangular. Returns (I - A)^{-1}.""" C = A.shape[-1] result = torch.eye(C, device=A.device, dtype=A.dtype).expand_as(A).clone() # Work with block sizes: 1, 2, 4, 8, 16, 32 for block_size in [1, 2, 4, 8, 16, 32]: num_blocks = C // block_size # For each pair of diagonal blocks, compute the off-diagonal for i in range(0, num_blocks, 2): if i + 1 < num_blocks: # Top-left block of the pair: result[i*bs:(i+1)*bs, i*bs:(i+1)*bs] # Bottom-right block: result[(i+1)*bs:(i+2)*bs, (i+1)*bs:(i+2)*bs] # Off-diagonal A block: A[(i+1)*bs:(i+2)*bs, i*bs:(i+1)*bs] # New off-diagonal = bottom_right @ A_off @ top_left top = result[..., i*block_size:(i+1)*block_size, i*block_size:(i+1)*block_size] bot = result[..., (i+1)*block_size:(i+2)*block_size, (i+1)*block_size:(i+2)*block_size] off = A[..., (i+1)*block_size:(i+2)*block_size, i*block_size:(i+1)*block_size] result[..., (i+1)*block_size:(i+2)*block_size, i*block_size:(i+1)*block_size] = \ torch.matmul(torch.matmul(bot, off), top) return result ``` Wait, this is wrong. The divide-and-conquer needs to be bottom-up, not top-down. Let me think more carefully. At the base case, each diagonal block is just I. Then we merge adjacent blocks. For merging two adjacent blocks of size s: - Top-left is T (s×s) - Bottom-right is B (s×s) - Off-diagonal in A is O (s×s) - The merged block's inverse has off-diagonal = B @ O @ T But T and B themselves are inverses of (I - A_top) and (I - A_bot), which we computed at the previous level. So the algorithm is: 1. Initialize result = I 2. For level in 0, 1, 2, 3, 4, 5 (block sizes 1, 2, 4, 8, 16, 32): - For each pair of blocks at this level: - off = A[..., bottom_block, top_block] - top = result[..., top_block, top_block] - bot = result[..., bottom_block, bottom_block] - result[..., bottom_block, top_block] = bot @ off @ top This is correct! Let me verify. For C=4: - Start: result = I (4×4) - Level 0 (block_size=1): - Pair (0,1): off=A[1,0], top=I[0,0]=1, bot=I[1,1]=1. result[1,0] = 1*A[1,0]*1 = A[1,0] - Pair (2,3): off=A[3,2], top=I[2,2]=1, bot=I[3,3]=1. result[3,2] = A[3,2] - Level 1 (block_size=2): - Pair (0,1): blocks [0:2] and [2:4] - off=A[2:4, 0:2] - top=result[0:2, 0:2] - bot=result[2:4, 2:4] - result[2:4, 0:2] = bot @ off @ top At level 0, top and bot are I, so result[0:2, 0:2] = (I - A[0:2, 0:2])^{-1} and result[2:4, 2:4] = (I - A[2:4, 2:4])^{-1}. At level 1, we compute the off-diagonal using the formula. This gives us the full inverse of the 4×4 block. Yes! This works. And each level can be parallelized as a single batched matmul over all pairs. For C=64, there are 6 levels. At level k (block_size = 2^k), there are 64 / 2^(k+1) pairs. Each pair requires a matmul of size (2^k, 2^k) @ (2^k, 2^k) @ (2^k, 2^k). For B*H*N = 512 matrices: - Level 0 (bs=1): 32 pairs, each matmul is (512, 1, 1) @ (512, 1, 1) = trivial - Level 1 (bs=2): 16 pairs, each matmul is (512, 2, 2) @ (512, 2, 2) - Level 2 (bs=4): 8 pairs, matmul (512, 4, 4) @ (512, 4, 4) - Level 3 (bs=8): 4 pairs, matmul (512, 8, 8) @ (512, 8, 8) - Level 4 (bs=16): 2 pairs, matmul (512, 16, 16) @ (512, 16, 16) - Level 5 (bs=32): 1 pair, matmul (512, 32, 32) @ (512, 32, 32) We can batch all pairs within a level together into a single bmm. For example, at level 2: - Stack all 8 pairs into a batch of 512*8 = 4096 matrices of size 4×4 - Do bmm in one call Actually, even better: for each level, we can reshape the tensors to do all pairs in parallel. Let me implement and test this.
Shell
args
{
  "command": "<1941 chars \u2014 see below>",
  "timeout": 60
}
command (1941 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import time

def tri_inv_dc(A):
    '''A is (..., C, C) strictly lower triangular. Returns (I - A)^{-1}.'''
    C = A.shape[-1]
    result = torch.eye(C, device=A.device, dtype=A.dtype).expand_as(A).clone()
    
    bs = 1
    while bs < C:
        num_pairs = C // (2 * bs)
        for p in range(num_pairs):
            top_start = p * 2 * bs
            top_end = top_start + bs
            bot_start = top_end
            bot_end = bot_start + bs
            
            top = result[..., top_start:top_end, top_start:top_end]
            bot = result[..., bot_start:bot_end, bot_start:bot_end]
            off = A[..., bot_start:bot_end, top_start:top_end]
            
            result[..., bot_start:bot_end, top_start:top_end] = torch.matmul(torch.matmul(bot, off), top)
        bs *= 2
    
    return result

# Test correctness
C = 64
BHN = 512
A = torch.randn(BHN, C, C, device='cuda') * 0.1
mask = torch.tril(torch.ones(C, C, device='cuda'), diagonal=-1)
A = A * mask

# Reference: sequential forward substitution
ref = torch.eye(C, device='cuda').expand_as(A).clone()
ref[:, 0, 0] = 1
for i in range(1, C):
    ref[:, i, :i] = A[:, i, :i] + (A[:, i, :, None] * ref[:, :, :i]).sum(-2)
    ref[:, i, i] = 1

# DC approach
dc = tri_inv_dc(A)

print('Max diff:', (ref - dc).abs().max().item())

# Time
torch.cuda.synchronize()
start = time.time()
for _ in range(1000):
    _ = tri_inv_dc(A)
torch.cuda.synchronize()
print(f'DC time: {(time.time()-start)/1000*1000:.3f} ms')

# Time reference
torch.cuda.synchronize()
start = time.time()
for _ in range(1000):
    ref = torch.eye(C, device='cuda').expand_as(A).clone()
    for i in range(1, C):
        ref[:, i, :i] = A[:, i, :i] + (A[:, i, :, None] * ref[:, :, :i]).sum(-2)
        ref[:, i, i] = 1
torch.cuda.synchronize()
print(f'Loop time: {(time.time()-start)/1000*1000:.3f} ms')
"
tool
stdout (115 chars)
<system>Command executed successfully.</system>
Max diff: 0.5737575888633728
DC time: 1.347 ms
Loop time: 1.471 ms
assistant
reasoning (9392 chars)
The DC approach has a large numerical error. Let me debug the algorithm. The issue is probably in my understanding of the forward substitution. Let me re-derive. After step 2 in the reference: A[i, j] = -L[i, j] for i > j, where L[i,j] = sum_d k[j,d] * k[i,d] * exp(g[j,d] - g[i,d]) * beta_i Wait, actually let me re-read the reference: ```python A[..., i] = torch.einsum("... c d, ... d -> ... c", k * (g - g_i).exp(), k_i) A = A * beta[..., None] A = -A.masked_fill(mask_diag_upper, 0) ``` For a fixed i, A[..., i, j] = -beta_i * sum_d k[j,d] * k[i,d] * exp(g[j,d] - g[i,d]) for j < i. Then the forward substitution: ```python for i in range(1, BT): A[..., i, :i] = A[..., i, :i].clone() + (A[..., i, :, None].clone() * A[..., :, :i].clone()).sum(-2) ``` This is: new_A[i, j] = old_A[i, j] + sum_k old_A[i, k] * old_A[k, j] for j < i. Wait, but k ranges over ALL positions, not just < i. However, old_A[i, k] = 0 for k >= i (since it's strictly lower triangular). And old_A[k, j] = 0 for k <= j (since it's strictly lower triangular). So the sum is over j < k < i. But in the reference, the second term is `(A[..., i, :, None] * A[..., :, :i]).sum(-2)`. - A[..., i, :, None] has shape (..., C, 1) - A[..., :, :i] has shape (..., C, i) - Elementwise product: (..., C, i) - sum over dim -2: sum over the C dimension So this computes: sum_k A[i, k] * A[k, j] for j in [0, i). Since A[i, k] = 0 for k >= i, and A[k, j] might be non-zero for k > j. But since j < i, and A[k, j] = 0 for k <= j, the non-zero terms are for max(0, j+1) <= k < i. But the key insight is: this computes (A @ A)[:, i, :i] where A is strictly lower triangular. Actually, it's more general. Let me define A^(t) as the matrix after t iterations. A^(0) = -L (strictly lower triangular) A^(1)[1, :] = A^(0)[1, :] + A^(0)[1, :] @ A^(0)[:, :] But A^(0)[1, 0] = -L[1, 0]. And A^(0)[1, :] @ A^(0)[:, :] = sum_k A^(0)[1,k] * A^(0)[k,0] = A^(0)[1,0] * A^(0)[0,0] = 0 since A^(0)[0,0] = 0. Wait, A^(0) has zeros on the diagonal. So A^(0)[0,0] = 0. For i=1: A[1,0] += A[1,0] * A[0,0] = 0. So A[1,0] doesn't change! For i=2: A[2,0] += A[2,0]*A[0,0] + A[2,1]*A[1,0] = A[2,1]*A[1,0] A[2,1] += A[2,0]*A[0,1] + A[2,1]*A[1,1] = 0 Hmm, so A[2,0] gets updated with A[2,1]*A[1,0], but A[2,1] doesn't change. For i=3: A[3,0] += A[3,1]*A[1,0] + A[3,2]*A[2,0] A[3,1] += A[3,2]*A[2,1] A[3,2] += 0 So the pattern is that A[i, j] gets updated with sum_{k=j+1}^{i-1} A[i, k] * A[k, j]. This is computing the (i, j) entry of A^2 + A^3 + A^4 + ... where A is strictly lower triangular with zeros on diagonal. Wait, A^2[i, j] = sum_k A[i, k] * A[k, j]. Since A[i, k] = 0 for k >= i and A[k, j] = 0 for k <= j, this is sum_{k=j+1}^{i-1} A[i, k] * A[k, j]. A^3[i, j] = sum_k A[i, k] * A^2[k, j]. For this to be non-zero, we need i > k > j, and then A^2[k, j] involves sum_{m=j+1}^{k-1} A[k, m] * A[m, j]. But in our forward substitution, when we process i=3, A[2,0] has already been updated. So A[3,0] gets A[3,1]*A[1,0] + A[3,2]*A[2,0]. But A[2,0] at this point includes A[2,1]*A[1,0] from the i=2 step. So A[3,0] = A[3,0] + A[3,1]*A[1,0] + A[3,2]*(A[2,0] + A[2,1]*A[1,0]) = A[3,0] + A[3,1]*A[1,0] + A[3,2]*A[2,0] + A[3,2]*A[2,1]*A[1,0] This is A[3,0] + A^2[3,0] + A^3[3,0]! Similarly, A[3,1] = A[3,1] + A[3,2]*A[2,1] = A[3,1] + A^2[3,1]. So after the full loop, A[i, j] = A[i, j] + A^2[i, j] + A^3[i, j] + ... + A^{i-j}[i, j]. Then the final result is A + I + A^2 + A^3 + ... = I + A + A^2 + A^3 + ... = (I - A)^{-1}. Wait no. After the loop, we have A_loop[i, j] = A_orig[i, j] + A_orig^2[i, j] + ... for i > j. Then A_final = A_loop + I = I + A_orig + A_orig^2 + ... = (I - A_orig)^{-1}. Yes! So the forward substitution computes (I - A_orig)^{-1} where A_orig is the original strictly lower triangular matrix. Now let me verify my DC algorithm. The formula for the inverse of a block triangular matrix: If M = [A, 0; C, B], then M^{-1} = [A^{-1}, 0; -B^{-1} @ C @ A^{-1}, B^{-1}]. Wait, that's for lower triangular, but with the off-diagonal in the bottom-left. In our case, I - A_orig is unit lower triangular (1s on diagonal, non-zero below). We can write: I - A_orig = [T, 0; O, B] where T and B are unit lower triangular. Then (I - A_orig)^{-1} = [T^{-1}, 0; -B^{-1} @ O @ T^{-1}, B^{-1}]. Wait, the sign is wrong. Let me re-derive: M = [T, 0; O, B] M @ M^{-1} = I [T, 0; O, B] @ [X, Y; Z, W] = [TX, TY; OX+BZ, OY+BW] = [I, 0; 0, I] TX = I => X = T^{-1} TY = 0 => Y = 0 (since T is invertible) OX + BZ = 0 => Z = -B^{-1} @ O @ X = -B^{-1} @ O @ T^{-1} OY + BW = I => W = B^{-1} So M^{-1} = [T^{-1}, 0; -B^{-1} @ O @ T^{-1}, B^{-1}]. But wait, in our case O is in the bottom-left, and it's -A_orig[bot, top]. So the off-diagonal of the inverse is: -B^{-1} @ (-A_orig[bot, top]) @ T^{-1} = B^{-1} @ A_orig[bot, top] @ T^{-1}. Hmm, but in my DC code, I used `bot @ off @ top` where `off = A[..., bot, top]`. So that's `B^{-1} @ A_orig[bot, top] @ T^{-1}`. But according to the formula, it should be `-B^{-1} @ O @ T^{-1}` where O is the original off-diagonal of I - A_orig, which is `-A_orig[bot, top]`. So: `-B^{-1} @ (-A_orig[bot, top]) @ T^{-1} = B^{-1} @ A_orig[bot, top] @ T^{-1}`. That matches my code! So my DC algorithm should be correct. But the test showed a large error. Let me re-check. Wait, in my test, I initialized A as random strictly lower triangular, then: - Reference: `ref[:, i, :i] = A[:, i, :i] + (A[:, i, :, None] * ref[:, :, :i]).sum(-2)` with ref starting as I. - But this is NOT the standard forward substitution for (I - A)^{-1}! Let me re-read the reference code: ```python for i in range(1, BT): A[..., i, :i] = A[..., i, :i].clone() + (A[..., i, :, None].clone() * A[..., :, :i].clone()).sum(-2) A = (A + torch.eye(BT, ...)) * beta[..., None, :] ``` Wait! The reference does the forward substitution IN PLACE on A, not on a separate result matrix. And A starts as the negated strictly lower triangular matrix. So during the loop, the updated values of A are used in subsequent iterations. This is important. In my test, I did: ```python ref = torch.eye(C, device='cuda').expand_as(A).clone() for i in range(1, C): ref[:, i, :i] = A[:, i, :i] + (A[:, i, :, None] * ref[:, :, :i]).sum(-2) ref[:, i, i] = 1 ``` This computes forward substitution on a COPY (ref), using the ORIGINAL A. But the reference code uses the IN-PLACE updated A! Let me re-derive. In the reference: ```python A_in = -L # strictly lower triangular, zeros on diagonal for i in range(1, C): A_in[i, :i] = A_in[i, :i] + (A_in[i, :] * A_in[:, :i]).sum(axis=-2) ``` Here, A_in[i, :] uses the UPDATED values for indices < i and the ORIGINAL zeros for indices >= i. And A_in[:, :i] uses the UPDATED values for all rows < i. So this is different from my test! In my test, I used the original A for both terms. Let me fix the test. Actually, looking more carefully: ```python A[..., i, :i] = A[..., i, :i].clone() + (A[..., i, :, None].clone() * A[..., :, :i].clone()).sum(-2) ``` Wait, the `.clone()` here means it uses the CURRENT values of A. But since we're only updating row i, and the terms A[..., i, :] and A[..., :, :i] only depend on rows <= i and columns < i, which might have been updated in previous iterations. Specifically: - A[..., i, :] = [A[i,0], A[i,1], ..., A[i,i-1], 0, 0, ...] where A[i,j] for j < i are the ORIGINAL values (since we haven't modified row i yet). - A[..., :, :i] = [A[0,0:i]; A[1,0:i]; ...; A[i-1,0:i]; A[i,0:i]; ...] But wait, for rows < i, these have been UPDATED in previous iterations. For rows >= i, these are still original. But since A[i, k] = 0 for k >= i, the sum only involves k < i. And for k < i, A[k, j] for j < i: if k < i, then row k was updated in iteration k. So we use the UPDATED A[k, j]. So the reference computes: new_A[i, j] = orig_A[i, j] + sum_{k=0}^{i-1} orig_A[i, k] * updated_A[k, j] Where updated_A[k, j] for k < i is the value after iteration k. This is NOT the same as computing (I - A)^{-1} using standard forward substitution. The standard approach would be: new_A[i, j] = orig_A[i, j] + sum_{k=0}^{i-1} updated_A[i, k] * updated_A[k, j] Wait, in the reference, the first term is orig_A[i, j] and the second term uses orig_A[i, k]. In standard forward substitution for (I - L)^{-1}, we would use updated_A[i, k]. Hmm, let me trace through small examples. For C=2: - A[0, :] = [0, 0] - A[1, :] = [a, 0] - Iteration i=1: A[1, 0] = a + A[1, :] @ A[:, 0] = a + a*0 + 0*0 = a - Result: A = [[0, 0], [a, 0]] - Then A + I = [[1, 0], [a, 1]] - This should be (I - A_orig)^{-1} = [[1, 0], [a, 1]]. Yes! For C=3: - A[0, :] = [0, 0, 0] - A[1, :] = [a10, 0, 0] - A[2, :] = [a20, a21, 0] - i=1: A[1, 0] = a10 + A[1, :] @ A[:, 0] = a10 + a10*0 = a10 - i=2: A[2, 0] = a20 + A[2, :] @ A[:, 0] = a20 + a20*0 + a21*A[1,0] + 0*0 = a20 + a21*a10 A[2, 1] = a21 + A[2, :] @ A[:, 1] = a21 + a20*0 + a21*0 + 0*0 = a21 - Result: A + I = [[1, 0, 0], [a10, 1, 0], [a20+a21*a10, a21, 1]] Now let's compute (I - A_orig)^{-1}: I - A_orig = [[1, 0, 0], [-a10, 1, 0], [-a20, -a21, 1]] The inverse should be: [[1, 0, 0], [a10, 1, 0], [a20 + a21*a10, a21, 1]] Yes! It matches. So the algorithm does compute (I - A_orig)^{-1}. Now let's check my DC test again. I was comparing against the wrong reference! Let me fix it. Actually, let me just test with the actual reference implementation from reference.py for a small case.
Shell
args
{
  "command": "<1382 chars \u2014 see below>",
  "timeout": 60
}
command (1382 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch

def reference_fwd_subst(A):
    C = A.shape[-1]
    for i in range(1, C):
        A[..., i, :i] = A[..., i, :i].clone() + (A[..., i, :, None].clone() * A[..., :, :i].clone()).sum(-2)
    return A

def tri_inv_dc(A):
    C = A.shape[-1]
    result = torch.eye(C, device=A.device, dtype=A.dtype).expand_as(A).clone()
    
    bs = 1
    while bs < C:
        num_pairs = C // (2 * bs)
        for p in range(num_pairs):
            top_start = p * 2 * bs
            top_end = top_start + bs
            bot_start = top_end
            bot_end = bot_start + bs
            
            top = result[..., top_start:top_end, top_start:top_end]
            bot = result[..., bot_start:bot_end, bot_start:bot_end]
            off = A[..., bot_start:bot_end, top_start:top_end]
            
            result[..., bot_start:bot_end, top_start:top_end] = torch.matmul(torch.matmul(bot, off), top)
        bs *= 2
    
    return result

# Test with small C
for C in [2, 4, 8, 16, 32, 64]:
    A = torch.randn(4, C, C, device='cuda') * 0.1
    mask = torch.tril(torch.ones(C, C, device='cuda'), diagonal=-1)
    A = A * mask
    
    ref = reference_fwd_subst(A.clone()) + torch.eye(C, device='cuda')
    dc = tri_inv_dc(A)
    
    print(f'C={C}: max_diff={(ref - dc).abs().max().item():.6f}')
"
tool
stdout (189 chars)
<system>Command executed successfully.</system>
C=2: max_diff=0.000000
C=4: max_diff=0.000000
C=8: max_diff=0.000000
C=16: max_diff=0.000000
C=32: max_diff=0.000000
C=64: max_diff=0.000000
assistant
reasoning (164 chars)
The DC approach is correct and matches the reference exactly. My earlier test had a bug in the reference implementation. Now let me test performance more carefully.
Shell
args
{
  "command": "<2517 chars \u2014 see below>",
  "timeout": 60
}
command (2517 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import time

def tri_inv_dc(A):
    C = A.shape[-1]
    result = torch.eye(C, device=A.device, dtype=A.dtype).expand_as(A).clone()
    
    bs = 1
    while bs < C:
        num_pairs = C // (2 * bs)
        # Batch all pairs into a single bmm
        top_list = []
        bot_list = []
        off_list = []
        for p in range(num_pairs):
            top_start = p * 2 * bs
            top_end = top_start + bs
            bot_start = top_end
            bot_end = bot_start + bs
            top_list.append(result[..., top_start:top_end, top_start:top_end])
            bot_list.append(result[..., bot_start:bot_end, bot_start:bot_end])
            off_list.append(A[..., bot_start:bot_end, top_start:top_end])
        
        if num_pairs > 0:
            # Stack and bmm
            tops = torch.stack(top_list, dim=-4)  # (num_pairs, ..., bs, bs)
            bots = torch.stack(bot_list, dim=-4)
            offs = torch.stack(off_list, dim=-4)
            
            # Reshape to merge batch dims
            batch_shape = A.shape[:-2]
            tops_flat = tops.view(num_pairs, -1, bs, bs)
            bots_flat = bots.view(num_pairs, -1, bs, bs)
            offs_flat = offs.view(num_pairs, -1, bs, bs)
            
            # bot @ off
            tmp = torch.bmm(bots_flat, offs_flat)
            # tmp @ top
            out = torch.bmm(tmp, tops_flat)
            
            # Unstack back
            out = out.view(num_pairs, *batch_shape, bs, bs)
            for p in range(num_pairs):
                top_start = p * 2 * bs
                top_end = top_start + bs
                bot_start = top_end
                bot_end = bot_start + bs
                result[..., bot_start:bot_end, top_start:top_end] = out[p]
        
        bs *= 2
    
    return result

# Performance test
C = 64
BHN = 512
A = torch.randn(BHN, C, C, device='cuda') * 0.1
mask = torch.tril(torch.ones(C, C, device='cuda'), diagonal=-1)
A = A * mask

torch.cuda.synchronize()
start = time.time()
for _ in range(1000):
    _ = tri_inv_dc(A)
torch.cuda.synchronize()
print(f'Batched DC: {(time.time()-start)/1000*1000:.3f} ms')

# Reference
torch.cuda.synchronize()
start = time.time()
for _ in range(1000):
    ref = A.clone()
    for i in range(1, C):
        ref[:, i, :i] = ref[:, i, :i] + (ref[:, i, :, None] * ref[:, :, :i]).sum(-2)
torch.cuda.synchronize()
print(f'Loop: {(time.time()-start)/1000*1000:.3f} ms')
"
tool
stdout (216 chars)
<system>ERROR: Command failed with exit code: 1.</system>
Traceback (most recent call last):
  File "<string>", line 65, in <module>
  File "<string>", line 38, in tri_inv_dc
RuntimeError: batch1 must be a 3D tensor
assistant
reasoning (51 chars)
The bmm needs 3D tensors. Let me fix the reshaping.
Shell
args
{
  "command": "<2350 chars \u2014 see below>",
  "timeout": 60
}
command (2350 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import time

def tri_inv_dc(A):
    C = A.shape[-1]
    result = torch.eye(C, device=A.device, dtype=A.dtype).expand_as(A).clone()
    batch_shape = A.shape[:-2]
    batch_numel = batch_shape.numel()
    
    bs = 1
    while bs < C:
        num_pairs = C // (2 * bs)
        if num_pairs > 0:
            # Stack all pairs
            tops = []
            bots = []
            offs = []
            for p in range(num_pairs):
                top_start = p * 2 * bs
                top_end = top_start + bs
                bot_start = top_end
                bot_end = bot_start + bs
                tops.append(result[..., top_start:top_end, top_start:top_end])
                bots.append(result[..., bot_start:bot_end, bot_start:bot_end])
                offs.append(A[..., bot_start:bot_end, top_start:top_end])
            
            # Shape: (num_pairs, batch_numel, bs, bs)
            tops_t = torch.stack(tops, dim=0).view(num_pairs * batch_numel, bs, bs)
            bots_t = torch.stack(bots, dim=0).view(num_pairs * batch_numel, bs, bs)
            offs_t = torch.stack(offs, dim=0).view(num_pairs * batch_numel, bs, bs)
            
            tmp = torch.bmm(bots_t, offs_t)
            out = torch.bmm(tmp, tops_t)
            out = out.view(num_pairs, *batch_shape, bs, bs)
            
            for p in range(num_pairs):
                top_start = p * 2 * bs
                top_end = top_start + bs
                bot_start = top_end
                bot_end = bot_start + bs
                result[..., bot_start:bot_end, top_start:top_end] = out[p]
        
        bs *= 2
    
    return result

# Performance test
C = 64
BHN = 512
A = torch.randn(BHN, C, C, device='cuda') * 0.1
mask = torch.tril(torch.ones(C, C, device='cuda'), diagonal=-1)
A = A * mask

torch.cuda.synchronize()
start = time.time()
for _ in range(1000):
    _ = tri_inv_dc(A)
torch.cuda.synchronize()
print(f'Batched DC: {(time.time()-start)/1000*1000:.3f} ms')

# Reference
torch.cuda.synchronize()
start = time.time()
for _ in range(1000):
    ref = A.clone()
    for i in range(1, C):
        ref[:, i, :i] = ref[:, i, :i] + (ref[:, i, :, None] * ref[:, :, :i]).sum(-2)
torch.cuda.synchronize()
print(f'Loop: {(time.time()-start)/1000*1000:.3f} ms')
"
tool
stdout (84 chars)
<system>Command executed successfully.</system>
Batched DC: 0.874 ms
Loop: 1.221 ms
assistant
reasoning (4118 chars)
The batched DC approach is 0.874ms vs 1.221ms for the loop - only about 1.4x faster, not the dramatic improvement I was hoping for. The issue is that even with batched bmm, the matrices are very small (up to 32×32), and bmm has significant overhead for small matrices. For C=64, at bs=32, we're doing a bmm of (512, 32, 32) @ (512, 32, 32) @ (512, 32, 32). Actually we're doing two bmms: first (512, 32, 32) @ (512, 32, 32), then the result @ (512, 32, 32). A 32×32 bmm for batch 512 is still quite small. Let me try a different approach: write a custom CUDA kernel for the forward substitution using `torch.utils.cpp_extension.load_inline`. For a 64×64 strictly lower triangular matrix, a single thread block can handle one matrix, with each thread handling one element. Actually, for 512 matrices and 64×64=4096 elements each, we could use 512 thread blocks with 64 threads each, where each thread computes one row. The row computation is sequential, but with only 64 steps, and 512 thread blocks, this would be very fast. Let me think about writing a simple CUDA kernel: ```cuda __global__ void forward_subst_kernel(float* A, int C, int batch) { int b = blockIdx.x; int tid = threadIdx.x; if (b >= batch) return; float* mat = A + b * C * C; // Each thread handles one row i for (int i = tid + 1; i < C; i += blockDim.x) { for (int j = 0; j < i; j++) { float sum = 0; for (int k = 0; k < i; k++) { sum += mat[i * C + k] * mat[k * C + j]; } mat[i * C + j] += sum; } } } ``` Wait, but in the reference, the sum uses the IN-PLACE updated values. For row i, when computing the sum over k, A[i, k] uses the ORIGINAL value (since row i hasn't been updated yet), but A[k, j] uses the UPDATED value if k < i. So for a thread computing row i: ```python for j in range(i): sum = 0 for k in range(i): sum += orig_A[i, k] * updated_A[k, j] new_A[i, j] = orig_A[i, j] + sum ``` But `orig_A[i, k]` is just the current value before updating row i. And `updated_A[k, j]` is the current value of the matrix at [k, j]. So each thread for row i can read the entire original row i once, then compute the updated row i using the current matrix values. Actually, there's a race condition if multiple threads in the same block try to update different rows simultaneously. Thread for row i needs to read updated_A[k, j] for k < i, which might be written by other threads. We can synchronize between rows using __syncthreads(), but that means we process rows sequentially within a block, which defeats the purpose of multiple threads. Better approach: one thread block per matrix, but only one thread active (or all threads computing the same row in parallel, then syncing). Actually, for a 64×64 matrix, we can have one warp (32 threads) compute each row. Two warps = 64 threads. For each row i: 1. Load orig_A[i, 0:i] into registers 2. Compute updated_A[i, j] for j in [0, i) using parallel reduction across threads - Each thread computes a partial sum over k - Then accumulate Wait, the operation is: new_A[i, j] = orig_A[i, j] + sum_k orig_A[i, k] * A[k, j] For fixed i and j, this is a dot product of orig_A[i, 0:i] and A[0:i, j]. We can compute all j simultaneously using matrix-vector multiplication: new_A[i, 0:i] = orig_A[i, 0:i] + orig_A[i, 0:i] @ A[0:i, 0:i] This is a vector-matrix product! For each row i, we do: 1. Load v = orig_A[i, 0:i] 2. Compute v @ A[0:i, 0:i] 3. new_A[i, 0:i] = orig_A[i, 0:i] + result This can be done as a matmul of (1, i) @ (i, i) -> (1, i). For i=64, this is a 1×64 @ 64×64 matmul. Still tiny. Hmm, maybe the simplest approach is to just use a single thread per matrix and do the loop. With 512 matrices and 512 thread blocks, each doing a 64-iteration loop, this should be very fast. A single thread can do ~10 GFLOPS in fp32, so 512 threads doing ~64^3/3 ≈ 87K FLOPs each = 45M FLOPs total. At 10 GFLOPS per thread, that's 0.0045 ms. With memory bandwidth, maybe 0.05ms. That's much better than 0.87ms! Let me write this CUDA kernel.
Shell
args
{
  "command": "<1590 chars \u2014 see below>",
  "timeout": 120
}
command (1590 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
from torch.utils.cpp_extension import load_inline

cuda_source = '''
__global__ void fwd_subst_kernel(float* __restrict__ A, int C, int batch) {
    int b = blockIdx.x;
    if (b >= batch) return;
    
    float* mat = A + b * C * C;
    
    for (int i = 1; i < C; i++) {
        for (int j = 0; j < i; j++) {
            float sum = 0.0f;
            for (int k = 0; k < i; k++) {
                sum += mat[i * C + k] * mat[k * C + j];
            }
            mat[i * C + j] += sum;
        }
    }
}

torch::Tensor fwd_subst(torch::Tensor A) {
    int batch = A.size(0);
    int C = A.size(1);
    fwd_subst_kernel<<<batch, 1>>>(A.data_ptr<float>(), C, batch);
    return A;
}
'''

module = load_inline(
    name='fwd_subst',
    cpp_sources='torch::Tensor fwd_subst(torch::Tensor A);',
    cuda_sources=cuda_source,
    functions=['fwd_subst'],
    extra_cuda_cflags=['-O3'],
    verbose=False,
)

C = 64
BHN = 512
A = torch.randn(BHN, C, C, device='cuda') * 0.1
mask = torch.tril(torch.ones(C, C, device='cuda'), diagonal=-1)
A = (A * mask).contiguous()

# Correctness
ref = A.clone()
for i in range(1, C):
    ref[:, i, :i] = ref[:, i, :i] + (ref[:, i, :, None] * ref[:, :, :i]).sum(-2)

out = module.fwd_subst(A.clone())
print('Max diff:', (ref - out).abs().max().item())

# Timing
torch.cuda.synchronize()
import time
start = time.time()
for _ in range(10000):
    _ = module.fwd_subst(A.clone())
torch.cuda.synchronize()
print(f'CUDA kernel: {(time.time()-start)/10000*1000:.3f} ms')
"
tool
stdout (103 chars)
<system>Command executed successfully.</system>
Max diff: 1.1920928955078125e-07
CUDA kernel: 0.979 ms
assistant
reasoning (1837 chars)
The single-thread-per-matrix CUDA kernel is 0.979ms, which is actually slightly slower than the batched DC approach (0.874ms). This is because a single thread per block is very inefficient on the GPU - most of the warp is idle. Let me try a better CUDA kernel where each block handles one matrix but all 64 threads cooperate. We can process rows sequentially but compute each row's update in parallel across threads. For row i, we need to compute: new_A[i, j] = orig_A[i, j] + sum_{k=0}^{i-1} orig_A[i, k] * A[k, j] for j in [0, i) This is: new_A[i, 0:i] = orig_A[i, 0:i] + orig_A[i, 0:i] @ A[0:i, 0:i] We can store A[0:i, 0:i] in shared memory (it's at most 64×64 = 16KB), and have each thread compute one or more j values. For j from 0 to i-1: dot_product of orig_A[i, 0:i] and A[0:i, j] With 64 threads, each thread handles one j. The dot product can be computed with a parallel reduction in shared memory. Actually, let me think about this differently. With 64 threads and 64×64 matrices: - Load the entire matrix into shared memory: 64×64 floats = 16KB. This fits easily in shared memory. - For each row i from 1 to 63: - Thread j computes dot(orig_A[i, 0:i], A[0:i, j]) for j < i - Thread j >= i does nothing - __syncthreads() - Update A[i, j] for j < i - __syncthreads() The dot product of length i can be computed by each thread independently in a loop. For i=64, each thread does 64 multiplies and adds. With 64 threads active for i=64, that's 4096 FLOPs. At ~10 TFLOPS for fp32, this is 0.4 microseconds per row, or ~25 microseconds for all 64 rows. With 512 blocks, total time would be ~0.013 ms. That's 75x faster than the loop! But wait, we need to read orig_A[i, 0:i] which is 64 floats. We can store this in a shared memory array or have each thread read from shared memory. Let me write this kernel.
Shell
args
{
  "command": "<2230 chars \u2014 see below>",
  "timeout": 120
}
command (2230 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
from torch.utils.cpp_extension import load_inline

cuda_source = '''
__global__ void fwd_subst_kernel(float* __restrict__ A, int C, int batch) {
    int b = blockIdx.x;
    if (b >= batch) return;
    
    int tid = threadIdx.x;
    
    __shared__ float s_A[64][64];
    
    float* mat = A + b * C * C;
    
    // Load matrix into shared memory
    for (int idx = tid; idx < C * C; idx += blockDim.x) {
        s_A[idx / C][idx % C] = mat[idx];
    }
    __syncthreads();
    
    // Save original row i in a shared buffer
    __shared__ float s_row[64];
    
    for (int i = 1; i < C; i++) {
        // Save original row i
        if (tid < i) {
            s_row[tid] = s_A[i][tid];
        }
        __syncthreads();
        
        // Each thread computes one j
        if (tid < i) {
            float sum = 0.0f;
            for (int k = 0; k < i; k++) {
                sum += s_row[k] * s_A[k][tid];
            }
            s_A[i][tid] += sum;
        }
        __syncthreads();
    }
    
    // Store back
    for (int idx = tid; idx < C * C; idx += blockDim.x) {
        mat[idx] = s_A[idx / C][idx % C];
    }
}

torch::Tensor fwd_subst(torch::Tensor A) {
    int batch = A.size(0);
    int C = A.size(1);
    fwd_subst_kernel<<<batch, 64>>>(A.data_ptr<float>(), C, batch);
    return A;
}
'''

module = load_inline(
    name='fwd_subst2',
    cpp_sources='torch::Tensor fwd_subst(torch::Tensor A);',
    cuda_sources=cuda_source,
    functions=['fwd_subst'],
    extra_cuda_cflags=['-O3'],
    verbose=False,
)

C = 64
BHN = 512
A = torch.randn(BHN, C, C, device='cuda') * 0.1
mask = torch.tril(torch.ones(C, C, device='cuda'), diagonal=-1)
A = (A * mask).contiguous()

# Correctness
ref = A.clone()
for i in range(1, C):
    ref[:, i, :i] = ref[:, i, :i] + (ref[:, i, :, None] * ref[:, :, :i]).sum(-2)

out = module.fwd_subst(A.clone())
print('Max diff:', (ref - out).abs().max().item())

# Timing
torch.cuda.synchronize()
import time
start = time.time()
for _ in range(10000):
    _ = module.fwd_subst(A.clone())
torch.cuda.synchronize()
print(f'CUDA kernel (64 threads): {(time.time()-start)/10000*1000:.3f} ms')
"
tool
stdout (116 chars)
<system>Command executed successfully.</system>
Max diff: 1.1920928955078125e-07
CUDA kernel (64 threads): 0.034 ms
assistant
reasoning (17257 chars)
Excellent! The CUDA kernel with 64 threads per block gets 0.034 ms, which is 36x faster than the loop! This is a huge win. Now let me put together an optimized solution: 1. Vectorized PyTorch for the einsum/bmm operations 2. Custom CUDA kernel for forward substitution 3. Custom Triton kernel for the inter-chunk recurrence (to avoid the Python loop overhead) Actually, let me first see how much time the inter-chunk recurrence takes if I write a Triton kernel for it. But first, let me see what the overall timing would be with just the optimized forward substitution. Actually, let me reconsider the overall strategy. I have: - Intra-chunk einsum/bmm: ~1.3ms - Forward substitution: ~0.03ms (with CUDA kernel) - Inter-chunk loop: ~2.5ms Total: ~3.8ms. The inter-chunk loop is still the biggest bottleneck. For the inter-chunk loop, let me write a Triton kernel. Actually, let me first check if there's a simpler optimization. The inter-chunk loop does: 1. v_i = u_i - w_i @ S 2. o_i = (q_i * exp(g_i)) @ S + Aqk @ v_i 3. S = S * decay + k_decay.T @ v_i If I could batch this across chunks somehow... But it's inherently sequential because S is updated. However, I can write a Triton kernel that processes all chunks sequentially within one kernel launch per (B, H, V_tile). This would eliminate the Python loop and kernel launch overhead. Let me write a simple Triton kernel for the inter-chunk recurrence. I'll follow FLA's pattern but simplify for our specific case. Actually, looking at my vectorized PyTorch inter-chunk timing of 2.5ms for 32 chunks, that's ~78 microseconds per chunk. The main operations per chunk are: 1. w_i @ S: (64, 128) @ (128, 128) = 2M FLOPs 2. q_i @ S: (64, 128) @ (128, 128) = 2M FLOPs 3. Aqk @ v_i: (64, 64) @ (64, 128) = 1M FLOPs 4. k_decay.T @ v_i: (128, 64) @ (64, 128) = 2M FLOPs Total: ~7M FLOPs per chunk. At 200 TFLOPS, this is 0.035 microseconds. The actual time of 78 microseconds is dominated by kernel launch overhead and memory bandwidth, not compute. A fused Triton kernel that does all of this in one launch would be much faster because: 1. The state S stays in registers/shared memory across chunks 2. No kernel launch overhead between chunks 3. Better memory coalescing Let me write a Triton kernel for this. Given K=V=128, I can use BV=64 and process V in 2 tiles. Actually, I realize I can also write a CUDA kernel for the inter-chunk recurrence, similar to the forward substitution kernel. Each thread block handles one (B, H, V_tile) and iterates through chunks. For V_tile=64, the state is (128, 64) = 8K fp32 = 32KB. With 64 threads, that's 512 bytes per thread in registers, which is a lot but manageable if some spills to shared memory. Let me try a CUDA kernel first since I'm already using load_inline. ```cuda __global__ void inter_chunk_kernel( const float* __restrict__ q, const float* __restrict__ k, const float* __restrict__ u, const float* __restrict__ w, const float* __restrict__ g, const float* __restrict__ Aqk, float* __restrict__ o, int B, int T, int H, int K, int V, int BT, int NT ) { int i_v = blockIdx.x; // V tile index int i_bh = blockIdx.y; // B*H index int i_b = i_bh / H; int i_h = i_bh % H; // State S: (K, V_tile) in shared memory or registers __shared__ float s_S[128][64]; // Initialize S to zero for (int idx = threadIdx.x; idx < K * 64; idx += blockDim.x) { s_S[idx / 64][idx % 64] = 0.0f; } __syncthreads(); for (int i_t = 0; i_t < NT; i_t++) { int base_t = i_b * T * H + i_t * BT; // Load u_i tile: (BT, V_tile) float u_local[64]; // too many registers! ... } } ``` Actually, with 64 threads and V_tile=64, if each thread stores 64 floats for v_i and o_i, that's 128 floats per thread = 512 bytes. The state S is 128×64 = 8192 floats = 32KB shared memory. This is manageable. But loading q_i, k_i, w_i of size (64, 128) each from global memory every chunk is 24K floats = 96KB per chunk. For 32 chunks, that's 3MB of reads per thread block. At 1.8TB/s, this is ~1.7 microseconds. The compute is negligible. Wait, but the actual memory bandwidth per SM is much lower. And with many thread blocks, we might be memory-bound. Actually, let me think about this more carefully. For B=2, H=8, V_tiles=2, we have 32 thread blocks. Each processes 32 chunks. Total global memory reads: - q: B*T*H*K = 2*2048*8*128 = 4M floats = 16MB - k: 16MB - u: B*T*H*V = 2*2048*8*128 = 4M floats = 16MB - w: 16MB - g: B*T*H*K = 4M floats = 16MB (but fp32, so 32MB) - Aqk: B*T*H*BT = 2*2048*8*64 = 2M floats = 8MB - o: 16MB Total reads: ~16+16+16+16+32+8 = 104MB. At 1.8TB/s = 1800GB/s, this is 0.058ms. So theoretically, a perfectly fused kernel could achieve ~0.06ms for the inter-chunk part! That's 40x faster than the 2.5ms PyTorch loop. But in practice, there will be inefficiencies. Still, even 0.5ms would be a 5x improvement. Let me write a CUDA kernel for the inter-chunk recurrence. I'll use shared memory for the state and process chunks sequentially. Actually, let me try a different approach first. Let me see if I can get significant speedup by just using `torch.cuda.Stream` and overlapping operations, or by compiling the inter-chunk loop with `torch.compile`. Actually, `torch.compile` on a loop with 32 iterations might not help much because the loop has data dependencies. Let me try writing the Triton kernel instead. It's more portable and easier to write than inline CUDA. For the Triton kernel, I'll follow this structure: - Grid: (V_tiles, B*H) - Each block processes all chunks sequentially - State S is kept in registers, tiled by K=64 and V=64 For K=128, V=64: - S1 = zeros(64, 64) fp32 - S2 = zeros(64, 64) fp32 For each chunk i_t: 1. Load u_i[:, i_v*64:(i_v+1)*64] -> (64, 64) in shared memory 2. Compute v_i = u_i - Load w_i[:, 0:64] -> (64, 64) - v_i -= w_i @ S1 - Load w_i[:, 64:128] -> (64, 64) - v_i -= w_i @ S2 3. Compute o_i - Load q_i[:, 0:64], g_i[:, 0:64] - o_partial = (q_i * exp(g_i)) @ S1 - Load q_i[:, 64:128], g_i[:, 64:128] - o_partial += (q_i * exp(g_i)) @ S2 - Load Aqk (64, 64) - o_i = o_partial + Aqk @ v_i - Store o_i 4. Update state - Load g_last[0:64], g_last[64:128] - S1 *= exp(g_last1)[:, None] - S2 *= exp(g_last2)[:, None] - Load k_i[:, 0:64], g_i[:, 0:64] - kg1 = exp(g_last1[None, :] - g_i) * k_i - S1 += kg1.T @ v_i - Load k_i[:, 64:128], g_i[:, 64:128] - kg2 = exp(g_last2[None, :] - g_i) * k_i - S2 += kg2.T @ v_i Wait, there's a subtlety. The state update uses `g_i[:, :, -1:]` which is the last row of g_i. So g_last is a vector of length K=128. And `exp(g_i[:, :, -1:] - g_i)` subtracts the last element from each row. For K tile 1 (0:64): kg1 = exp(g_last[0:64][None, :] - g_i[:, 0:64]) * k_i[:, 0:64] This is correct. Let me write this in Triton. I'll need to be careful about memory layout. The inputs q, k, w, u, g are in the standard (B, T, H, K/V) layout. Aqk is (B, T, H, BT). Actually, for the intra-chunk part, I should also think about fusing everything into Triton kernels. But the intra-chunk A_kk construction is already reasonably fast (1.3ms). Let me focus on the inter-chunk first. Wait, let me reconsider. If I can get the inter-chunk down to ~0.5ms and keep intra-chunk at ~1.3ms, total is still ~1.8ms. That's 9x slower than SOTA. To get under 0.5ms total, I need both parts to be much faster. Maybe I should try to write a more comprehensive solution. Let me look at what FLA actually does for the full forward pass and try to replicate the key kernels. FLA's full forward pass: 1. `chunk_kda_fwd_intra`: Computes Aqk, Akk (intra-chunk) 2. `recompute_w_u_fwd`: Computes w, u from Akk, k, v, beta 3. `chunk_gated_delta_rule_fwd_h`: Computes states h and v_new (inter-chunk) 4. `chunk_gla_fwd_o_gk`: Computes final output from h, v_new, Aqk, q, g These are 4 kernel launches. For T=2048, B=2, H=8, each kernel handles the entire problem. The total time is ~0.2ms. If I can write similar Triton kernels, I might get close. But writing 4 kernels from scratch is a lot of work. Actually, wait. Can I import and use FLA's lower-level utilities? The problem says I can't use `fla.ops.kda.chunk_kda` or similar, but what about the individual Triton kernels? Looking at the forbidden list: - "fla.ops.kda" - "fla.ops.chunk_kda" - "chunk_kda" - "fused_recurrent_kda" - "naive_chunk_kda" - "naive_recurrent_kda" The check.py does a simple text search: ```python for forbidden in meta.get("forbidden", []): pat = re.escape(forbidden) if re.search(pat, sol_src): print(f"FAIL: forbidden op used: {forbidden}") sys.exit(1) ``` So if I import `fla.ops.kda.chunk_intra` or `fla.ops.common.chunk_delta_h`, that would contain "fla.ops.kda" and "chunk_kda" in the source code, which would fail the check. What about importing `fla.ops.gla.chunk` for `chunk_gla_fwd_o_gk`? That doesn't contain any forbidden strings. But it's against the spirit of the problem. Actually, the problem explicitly says: "The whole point of the problem is to write the chunk-parallel attention yourself, not call FLA's existing implementation." So I should write my own kernels. But I can take inspiration from FLA's structure. Let me think about a pragmatic approach: 1. Write a Triton kernel for the intra-chunk A computation and forward substitution 2. Write a Triton kernel for computing w and u 3. Write a Triton kernel for the inter-chunk recurrence and output Or, since I'm already using load_inline for CUDA, I could write CUDA kernels for all three parts. Actually, for the inter-chunk part, let me try writing a CUDA kernel first and see how much speedup I can get. For the CUDA kernel, I need to handle the memory layout carefully. Let me define: - q: (B, T, H, K) - k: (B, T, H, K) - v: (B, T, H, V) - actually u is computed from v - g: (B, T, H, K) - beta: (B, T, H) - w: (B, T, H, K) - u: (B, T, H, V) - Aqk: (B, T, H, BT) - o: (B, T, H, V) Wait, in the reference, after reshaping, the layout is (B, H, N, C, K/V). But for the CUDA kernel, I can work with either layout. Let me use the (B, T, H, K) layout to avoid extra reshuffles. For q at position (b, t, h, k): q[b * T * H * K + t * H * K + h * K + k] For Aqk at position (b, t, h, j): Aqk[b * T * H * BT + t * H * BT + h * BT + j] For w at position (b, t, h, k): same as q. OK, let me write a CUDA kernel for the inter-chunk recurrence. Actually, let me take a step back. Writing multiple complex CUDA kernels from scratch might take a very long time. Let me see if there's a middle ground. What if I write the inter-chunk recurrence as a single Triton kernel, and keep the intra-chunk in PyTorch but with the CUDA forward substitution kernel? That might get me to ~1.5ms total, which is still 7.5x slower than SOTA but maybe acceptable for passing the benchmark? Wait, the benchmark says: ``` peak_fraction: <gmean> RESULT: OK if gmean >= 0.1 else LOW ``` So I need peak_fraction >= 0.1. For the headline shape (B=2,T=2048): - FLOPs = 4.3B - Peak = 200 TFLOPS - For peak_fraction = 0.1: Time = 4.3B / (200T * 0.1) = 4.3B / 20T = 0.215 ms The SOTA gets 0.202ms, which is about 0.107 peak fraction. So I need to be at most ~0.215ms for this shape to get OK. At 1.5ms, peak fraction = 4.3B / (200T * 0.0015) = 4.3 / 300 = 0.014 = 1.4%. That's way below 10%. For smaller shapes, the peak fraction will be even worse because there's more overhead relative to compute. So I really need to get close to SOTA performance. This means writing proper fused Triton kernels. Let me think about what the minimal set of kernels is: 1. One kernel for intra-chunk A_kk, forward substitution, w, u, Aqk 2. One kernel for inter-chunk recurrence + output Or even better: one mega-kernel for everything? Probably too complex. For kernel 1, the main operations are: - Compute A_kk = einsum(k*exp(g), k*exp(-g)) with masking - Forward substitution on A_kk - Compute w = A_kk @ (k*exp(g)) and u = A_kk @ v - Compute Aqk = einsum(q*exp(g), k*exp(-g)) with masking The einsum operations can be written as matmuls by transposing. For a chunk of 64 tokens: - k*exp(g) is (64, K) - k*exp(-g) is (64, K) - A_kk = (k*exp(g)) @ (k*exp(-g)).T -> (64, 64) This is just a standard matmul! With K=128, it's (64, 128) @ (128, 64) = (64, 64). Similarly for Aqk: (64, 128) @ (128, 64) = (64, 64). And w = A_kk @ (k*exp(g)): (64, 64) @ (64, 128) = (64, 128) u = A_kk @ v: (64, 64) @ (64, 128) = (64, 128) These are all standard matmuls! The only custom part is: 1. Applying the exp(g) and exp(-g) scaling 2. The forward substitution on the 64×64 matrix 3. The masking (lower triangular) For the forward substitution, we already have a fast CUDA kernel. But we could also write it in Triton. Actually, since all these operations are on 64×64 or 64×128 matrices, maybe I can write a single Triton kernel per chunk that does everything. Wait, with Triton, we can have each thread block handle one (B, H, chunk) and process the entire chunk. For 512 chunks, we'd have 512 thread blocks. Each thread block does: 1. Load k, g, beta, v, q for its 64 tokens 2. Compute A_kk using a 64×64 matmul 3. Do forward substitution (in shared memory or registers) 4. Compute w and u using matmuls 5. Compute Aqk using a matmul 6. Store w, u, Aqk The issue is that Triton's `tl.dot` uses Tensor Cores, which are great for large matmuls but might have high overhead for 64×64. However, with K=128, the matmul is 64×128 @ 128×64, which is reasonably sized for Tensor Cores. Actually, in Triton, for a single thread block doing a 64×128 @ 128×64 matmul, we'd need to tile it. With BK=64, we'd do 2 iterations of loading 64×64 tiles and accumulating. Let me look at how FLA's `chunk_kda_fwd_kernel_intra_sub_chunk` does it. They use sub-chunks of BC=16 within BT=64. This is because a 64×64 matmul doesn't fill the Tensor Cores well on some architectures, but 16×16 or 16×64 does. For Blackwell (SM120), Tensor Cores might handle 64×64 better, but I'm not sure. Let me try a different approach. Instead of writing everything from scratch, let me see if I can write a solution that: 1. Uses PyTorch for the matmuls and einsums 2. Uses my custom CUDA kernel for forward substitution 3. Uses `torch.compile` on the inter-chunk loop with some optimizations Actually, `torch.compile` might not help with the sequential loop. What if I rewrite the inter-chunk loop using `torch.scan` or associative scan? For linear recurrences, there are parallel scan algorithms. But KDA's recurrence is not a simple associative scan because it involves matrix multiplications. Actually, let me re-examine the inter-chunk recurrence. For each chunk: 1. v_i = u_i - w_i @ S 2. o_i = (q_i * exp(g_i)) @ S + Aqk @ v_i 3. S = S * decay + k_decay.T @ v_i This can be written as: ``` S_{i+1} = S_i * decay_i + k_decay_i.T @ (u_i - w_i @ S_i) = S_i * decay_i + k_decay_i.T @ u_i - k_decay_i.T @ w_i @ S_i = (decay_i - k_decay_i.T @ w_i) @ S_i + k_decay_i.T @ u_i ``` Wait, `decay_i` is a diagonal matrix (or elementwise multiplication). And `k_decay_i.T @ w_i` is (K, C) @ (C, K) = (K, K). So: ``` S_{i+1} = diag(decay_i) @ S_i - (k_decay_i.T @ w_i) @ S_i + k_decay_i.T @ u_i = (diag(decay_i) - k_decay_i.T @ w_i) @ S_i + k_decay_i.T @ u_i ``` This is a linear recurrence! And it CAN be parallelized using associative scan if we express it as: ``` S_{i+1} = M_i @ S_i + B_i ``` Where M_i = diag(decay_i) - k_decay_i.T @ w_i is (K, K), and B_i = k_decay_i.T @ u_i is (K, V). For a linear recurrence S_{i+1} = M_i S_i + B_i, there's a parallel scan algorithm: - We can write it as an affine transformation: [S_{i+1}; I] = [M_i, B_i; 0, I] @ [S_i; I] - Then the scan is just a matrix product scan over the 2K×2K matrices... wait, that's (K+V)×(K+V) which is 256×256. For 32 chunks, scanning 256×256 matrices is expensive. But there is a more efficient approach using the parallel prefix algorithm for linear recurrences. However, implementing this in PyTorch/Triton is complex. For simplicity, let me just write a Triton kernel for the sequential inter-chunk recurrence. With proper tiling, it should be much faster than the PyTorch loop. Let me write a focused Triton kernel. I'll base it on FLA's `chunk_gated_delta_rule_fwd_kernel_h_blockdim64` but add the output computation. Actually, looking at FLA's code more carefully, they have two separate kernels: 1. `chunk_gated_delta_rule_fwd_kernel_h_blockdim64` computes h (states) and v_new 2. `chunk_gla_fwd_kernel_o` computes o from h, v_new, q, g, A The reason they split is because h has shape (B, NT, H, K, V), which is large: for B=2, NT=32, H=8, K=128, V=128, h is 2*32*8*128*128 = 8M floats = 32MB. They save h for the backward pass. For inference (our case, since we only need forward), we could fuse these two kernels. But writing a fused kernel is more complex. Let me try to write just the inter-chunk state kernel in Triton, similar to FLA's, and then do the output computation either in the same kernel or in a separate one. Actually, let me look at what `recompute_w_u_fwd` does in FLA. It's in `wy_fast.py`.
ReadFile /home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/wy_fast.py
args
{
  "path": "/home/infatoshi/.cache/uv/archive-v0/rnS-5wxCI5ghhBOYKv7Tc/fla/ops/kda/wy_fast.py"
}
tool
stdout (14531 chars) — TRUNCATED
<system>352 lines read from file starting from line 1. Total lines in file: 352. End of file reached.</system>
     1	# Copyright (c) 2023-2026, Songlin Yang, Yu Zhang, Zhiyuan Li
     2	#
     3	# This source code is licensed under the MIT license found in the
     4	# LICENSE file in the root directory of this source tree.
     5	# For a list of all contributors, visit:
     6	#   https://github.com/fla-org/flash-linear-attention/graphs/contributors
     7	
     8	import torch
     9	import triton
    10	import triton.language as tl
    11	
    12	from fla.ops.utils import prepare_chunk_indices
    13	from fla.ops.utils.op import exp2
    14	from fla.utils import autotune_cache_kwargs, check_shared_mem
    15	
    16	
    17	@triton.heuristics({
    18	    'STORE_QG': lambda args: args['qg'] is not None,
    19	    'STORE_KG': lambda args: args['kg'] is not None,
    20	    'IS_VARLEN': lambda args: args['cu_seqlens'] is not None,
    21	})
    22	@triton.autotune(
    23	    configs=[
    24	        triton.Config({}, num_warps=num_warps, num_stages=num_stages)
    25	        for num_warps in [2, 4, 8]
    26	        for num_stages in [2, 3, 4]
    27	    ],
    28	    key=['H', 'HV', 'K', 'V', 'BT', 'BK', 'BV', 'IS_VARLEN'],
    29	    **autotune_cache_kwargs,
    30	)
    31	@triton.jit(do_not_specialize=['T'])
    32	def recompute_w_u_fwd_kda_kernel(
    33	    q,
    34	    k,
    35	    qg,
    36	    kg,
    37	    v,
    38	    beta,
    39	    w,
    40	    u,
    4

... (13031 more chars)
assistant
reasoning (2865 chars)
OK, I now have a very good understanding of the FLA implementation. Let me plan my approach: Given the time constraints and the complexity, I'll write a solution that uses: 1. PyTorch for the initial reshaping and cumsum 2. A custom Triton kernel for the intra-chunk A_kk computation (replacing the einsum + loop with a fused kernel) 3. My custom CUDA kernel for the forward substitution 4. A custom Triton kernel for computing w and u 5. A custom Triton kernel for the inter-chunk recurrence and output Actually, let me simplify. I'll write: 1. PyTorch for data prep (reshape, cumsum) 2. Triton kernel for computing A_kk and Aqk (the einsum parts) 3. CUDA kernel for forward substitution 4. Triton kernel for w and u from A_kk 5. Triton kernel for inter-chunk recurrence + output Wait, step 2 and 4 are basically what FLA's `recompute_w_u_fwd` does. And step 5 is what FLA's `chunk_gated_delta_rule_fwd_h` + `chunk_gla_fwd_o_gk` do. Let me try writing these kernels, but simplified for our specific case (no GVA, fixed K=V=128, chunk_size=64). Actually, I realize that for the intra-chunk part, I can just keep using PyTorch vectorized ops but replace the forward substitution with my CUDA kernel. The einsum/bmm takes 1.3ms, and the forward substitution takes 0.03ms with CUDA. Then w/u computation is another 0.3ms or so with batched matmul. So intra-chunk total is ~1.6ms. For the inter-chunk, I need a Triton kernel. Let me write one now. Let me think about the Triton kernel for the inter-chunk + output more carefully. Grid: (V_tiles, B*H) where V_tiles = V // BV = 2 for BV=64. Each block iterates over all chunks. For K=128, I'll use BK=64. So K is split into 2 tiles. State: S1 = zeros(64, BV), S2 = zeros(64, BV) in fp32. (These fit in registers if BV=64, since 2 * 64 * 64 = 8192 fp32 values. With 128 threads, that's 64 per thread, which is OK.) Wait, actually in Triton, `tl.zeros([64, 64], dtype=tl.float32)` creates a tensor that the compiler manages. It might spill to shared memory or local memory. For 128 threads (4 warps), 64×64 fp32 = 16KB per block. With shared memory of ~100KB, we could put it there. But Triton handles this automatically. Actually, looking at FLA's kernel, they use `b_h1 = tl.zeros([64, BV], dtype=tl.float32)` directly and the compiler manages it. For BV=64, this is 64×64 = 4096 fp32 = 16KB. Two such tiles = 32KB. This fits in shared memory if needed. Let me write the inter-chunk Triton kernel. One important detail: FLA uses `exp2` (base-2 exponential) because they scale g by RCP_LN2. In our reference, we use `exp` (base-e). So I need to use `tl.exp` not `tl.exp2`. Wait, let me re-check the reference. The reference uses `.exp()` which is base-e. And the input g is already in the correct scale. So I should use `tl.exp` in my kernel. Actually, let me check if `tl.exp` is available in Triton 3.6.
Shell
args
{
  "command": "<132 chars \u2014 see below>"
}
command (132 chars)
python -c "
import triton.language as tl
print('exp available:', hasattr(tl, 'exp'))
print('exp2 available:', hasattr(tl, 'exp2'))
"
tool
stdout (89 chars)
<system>Command executed successfully.</system>
exp available: True
exp2 available: True
assistant
reasoning (3645 chars)
Good. Let me now write a comprehensive solution. I'll create the following structure: 1. `solution.py` with the Model class 2. A Triton kernel for the inter-chunk recurrence + output computation 3. Use PyTorch for intra-chunk but with optimized ops and the CUDA forward substitution kernel Actually, let me think about whether I can get good enough performance with just: 1. Optimized PyTorch for intra-chunk (einsum/bmm + CUDA fwd subst) 2. A single Triton kernel for inter-chunk + output The intra-chunk timing was ~1.3ms for einsum + 0.03ms for fwd subst + ~0.3ms for w/u + ~0.3ms for Aqk = ~1.9ms. But wait, that was with Python loops for Aqk too. Let me measure the actual breakdown more carefully. Actually, in my earlier timing, the "intra-chunk" was 1.3ms which INCLUDED Aqk, w, u, and the einsums. And the forward substitution loop was measured separately at 1.2ms. So with the CUDA fwd subst, total intra-chunk would be ~1.3ms + 0.03ms = ~1.3ms. Wait no, let me re-check. In my timing, "With einsum" was 1.327 ms for the full intra-chunk (including A build, w, u, Aqk). The forward substitution loop was 1.221ms in a separate test. But in the einsum test, I included the forward substitution loop. So the einsum timing of 1.327ms already includes the forward substitution. Actually, looking at my code more carefully: ```python for _ in range(200): gf = g.float().view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).cumsum(-2) kg = kf * gf.exp() kgn = kf * (-gf).exp() A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn) A = A * bf[..., None] A = -A.masked_fill(mask_upper, 0) for i in range(1, BT): A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2) A = (A + I) * bf[..., None, :] w = torch.matmul(A, (gf.exp() * kf)) u = torch.matmul(A, vf) qg = qf * gf.exp() Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn) Aqk = Aqk.masked_fill(mask_strict, 0) ``` So the 1.327ms includes everything. And the forward substitution loop alone was 1.221ms. So the rest (einsums, matmuls, masking) takes only ~0.1ms! Wait, that can't be right. Let me re-check. If the full loop with forward substitution takes 1.327ms, and the forward substitution alone takes 1.221ms, then the einsums + matmuls take ~0.1ms. That's plausible because batched matmuls on large batches are very efficient on GPU. So replacing the forward substitution with my CUDA kernel (0.03ms) would bring the intra-chunk time down to ~1.327 - 1.221 + 0.03 = ~0.14ms! That's a huge win! The total would then be ~0.14ms (intra) + ~2.5ms (inter) = ~2.64ms. Wait, no. The 1.327ms was for 200 iterations, so 0.0066ms per iteration. But that was the full forward pass of just the intra-chunk part. For one actual forward pass: - Intra-chunk: ~0.0066ms? That seems way too fast. Oh wait! I see the issue. In my timing loop, I'm doing `gf = g.float().view(...).cumsum(-2)` which creates a NEW tensor every iteration. But the actual compute inside might be very fast because the tensors are cached in GPU memory. And 200 iterations of the same computation might be heavily pipelined. Let me run the timing with just 1 iteration or use CUDA events for accurate measurement. Actually, the 1.327ms / 200 = 0.0066ms = 6.6 microseconds. For 512 chunks doing 64×64 and 64×128 matmuls, that's extremely fast. This suggests the GPU is heavily pipelining the operations. But in the actual model forward pass, there will be more overhead because we also need to do the inter-chunk part, which has sequential dependencies. Let me measure the intra-chunk with CUDA events to get a more accurate single-call time.
Shell
args
{
  "command": "<3170 chars \u2014 see below>",
  "timeout": 120
}
command (3170 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import shapes

shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]
q, k, v, g, beta = inputs
scale = float(shape['K']) ** -0.5

B, T, H, K = q.shape
V = v.shape[-1]
BT = 64
NT = T // BT

qf = q.float() * scale
kf = k.float()
vf = v.float()
gf = g.float()
bf = beta.float()

qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4)
gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2)

mask_upper = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=0)
mask_strict = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=1)
I = torch.eye(BT, device=q.device, dtype=torch.float32)

gf = gf.cumsum(-2)

# Measure with cuda events
start_event = torch.cuda.Event(enable_timing=True)
end_event = torch.cuda.Event(enable_timing=True)

# Warmup
for _ in range(10):
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    for i in range(1, BT):
        A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
    Aqk = Aqk.masked_fill(mask_strict, 0)

torch.cuda.synchronize()
start_event.record()
for _ in range(100):
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    for i in range(1, BT):
        A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
    Aqk = Aqk.masked_fill(mask_strict, 0)
end_event.record()
torch.cuda.synchronize()
print(f'Intra-chunk (100 iters): {start_event.elapsed_time(end_event):.3f} ms')
print(f'Intra-chunk per iter: {start_event.elapsed_time(end_event)/100:.3f} ms')

# Measure just einsum + matmul without fwd subst
start_event.record()
for _ in range(100):
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
    Aqk = Aqk.masked_fill(mask_strict, 0)
end_event.record()
torch.cuda.synchronize()
print(f'Without fwd subst (100 iters): {start_event.elapsed_time(end_event):.3f} ms')
print(f'Without fwd subst per iter: {start_event.elapsed_time(end_event)/100:.3f} ms')
"
tool
stdout (193 chars)
<system>Command executed successfully.</system>
Intra-chunk (100 iters): 136.076 ms
Intra-chunk per iter: 1.361 ms
Without fwd subst (100 iters): 21.846 ms
Without fwd subst per iter: 0.218 ms
assistant
reasoning (753 chars)
So the intra-chunk without forward substitution takes 0.218ms, and the forward substitution adds ~1.14ms. With my CUDA kernel (0.034ms for 512 matrices), the total intra-chunk would be ~0.218 + 0.034 = ~0.25ms. The inter-chunk takes ~2.5ms. So total with optimized intra-chunk is ~2.75ms. To get to SOTA level (~0.2ms), I need to reduce the inter-chunk from 2.5ms to ~0.05ms or less. That's a 50x speedup, which requires a fused kernel. Let me write a Triton kernel for the inter-chunk recurrence. I'll model it after FLA's approach but simplified. Actually, let me try a different approach first. Can I use `torch.jit.script` or `torch.compile` on the inter-chunk loop to fuse operations? Let me test `torch.compile` on the inter-chunk recurrence.
Shell
args
{
  "command": "<3009 chars \u2014 see below>",
  "timeout": 180
}
command (3009 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import shapes

shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

torch.manual_seed(2026)
inputs = [t.cuda() if hasattr(t, 'cuda') else t for t in reference.get_inputs()]
q, k, v, g, beta = inputs
scale = float(shape['K']) ** -0.5

B, T, H, K = q.shape
V = v.shape[-1]
BT = 64
NT = T // BT

qf = q.float() * scale
kf = k.float()
vf = v.float()
gf = g.float()
bf = beta.float()

qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4)
gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2)

mask_upper = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=0)
mask_strict = torch.triu(torch.ones(BT, BT, device=q.device, dtype=torch.bool), diagonal=1)
I = torch.eye(BT, device=q.device, dtype=torch.float32)

gf = gf.cumsum(-2)

kg = kf * gf.exp()
kgn = kf * (-gf).exp()
A = torch.einsum('bhnik,bhnjk->bhnij', kg, kgn)
A = A * bf[..., None]
A = -A.masked_fill(mask_upper, 0)
for i in range(1, BT):
    A[..., i, :i] = A[..., i, :i] + (A[..., i, :, None] * A[..., :, :i]).sum(-2)
A = (A + I) * bf[..., None, :]
w = torch.matmul(A, (gf.exp() * kf))
u = torch.matmul(A, vf)
qg = qf * gf.exp()
Aqk = torch.einsum('bhnik,bhnjk->bhnij', qg, kgn)
Aqk = Aqk.masked_fill(mask_strict, 0)

def inter_chunk(qf, kf, gf, w, u, Aqk):
    S = qf.new_zeros(B, H, K, V)
    o = torch.zeros_like(vf)
    for i in range(NT):
        q_i = qf[:, :, i]
        k_i = kf[:, :, i]
        u_i = u[:, :, i]
        g_i = gf[:, :, i]
        w_i = w[:, :, i]
        
        v_i = u_i - torch.matmul(w_i, S)
        qS = torch.matmul(q_i * g_i.exp(), S)
        Av = torch.matmul(Aqk[:, :, i], v_i)
        o[:, :, i] = qS + Av
        
        decay = g_i[:, :, -1].exp().unsqueeze(-1)
        S = S * decay
        
        kg_decay = (g_i[:, :, -1:] - g_i).exp() * k_i
        S = S + torch.matmul(kg_decay.transpose(-2, -1), v_i)
    return o

compiled_inter = torch.compile(inter_chunk, mode='max-autotune')

# Warmup compiled
for _ in range(5):
    _ = compiled_inter(qf, kf, gf, w, u, Aqk)

start_event = torch.cuda.Event(enable_timing=True)
end_event = torch.cuda.Event(enable_timing=True)
start_event.record()
for _ in range(100):
    _ = compiled_inter(qf, kf, gf, w, u, Aqk)
end_event.record()
torch.cuda.synchronize()
print(f'Compiled inter-chunk (100 iters): {start_event.elapsed_time(end_event):.3f} ms')
print(f'Compiled inter-chunk per iter: {start_event.elapsed_time(end_event)/100:.3f} ms')

# Baseline
start_event.record()
for _ in range(100):
    _ = inter_chunk(qf, kf, gf, w, u, Aqk)
end_event.record()
torch.cuda.synchronize()
print(f'Eager inter-chunk (100 iters): {start_event.elapsed_time(end_event):.3f} ms')
print(f'Eager inter-chunk per iter: {start_event.elapsed_time(end_event)/100:.3f} ms')
"
tool
stdout (50091 chars) — TRUNCATED
<system>Command executed successfully. Output is truncated to fit in the message.</system>
/home/infatoshi/.local/lib/python3.12/site-packages/torch/_inductor/compile_fx.py:322: UserWarning: TensorFloat32 tensor cores for float32 matrix multiplication available but not enabled. Consider setting `torch.set_float32_matmul_precision('high')` for better performance.
  warnings.warn(
/home/infatoshi/.local/lib/python3.12/site-packages/torch/_inductor/select_algorithm.py:3686: UserWarning: TypedStorage is deprecated. It will be removed in the future and UntypedStorage will be the only storage class. This should only matter to you if you are using storages directly.  To access UntypedStorage directly, use tensor.untyped_storage() instead of tensor.storage()
  current_out_size = out_base.storage().size()
E0428 10:21:41.698000 370917 torch/_inductor/select_algorithm.py:3924] [0/0] Runtime error during autotuning: 
E0428 10:21:41.698000 370917 torch/_inductor/select_algorithm.py:3924] [0/0] No valid triton configs. OutOfMemoryError: out of resource: triton_bmm Required: 196608 Hardware limit:101376 Reducing block sizes or `num_stages` may help.. 
E0428 10:21:41.698000 370917 torch/_inductor/select_algorithm.py:3924] [0/0] Ignoring this choice.
Autotune Choices Stats:
{"num_choices": 19, "num_triton_choices": 18, "best_kernel": "triton_bmm_2", "best_kernel_desc": "ACC_TYPE='tl.float32', ALLOW_TF32=False, BLOCK_K=32, BLOCK_M=32, BLOCK_N=64, EVEN_K=True, GROUP_M=8, USE_FAST_ACCUM=False, n

... (48591 more chars)
assistant
reasoning (3342 chars)
The `torch.compile` is taking a very long time due to autotuning and seems to have some issues with out-of-resource errors on Blackwell. Let me kill this and take a different approach. I need to write custom Triton kernels. Let me focus on writing a solution with: 1. PyTorch for the initial reshape and cumsum 2. A custom Triton kernel for the inter-chunk recurrence and output 3. The intra-chunk can stay in optimized PyTorch + my CUDA forward substitution kernel Actually, let me reconsider. The SOTA gets 0.2ms. To get even close to 0.2ms, I need highly optimized kernels for ALL parts. But writing multiple complex Triton kernels from scratch is extremely time-consuming. Let me look at this from a different angle. What if I write a single CUDA kernel for the ENTIRE KDA forward pass? For each (B, H, chunk), I need to: 1. Load q, k, v, g, beta for 64 tokens 2. Compute A_kk and Aqk 3. Do forward substitution on A_kk 4. Compute w and u 5. For the inter-chunk part, I need state from previous chunks The inter-chunk dependency means I can't parallelize across chunks within a single (B, H). But I CAN process chunks sequentially within a thread block. A single mega-kernel per (B, H) would: - Initialize S = zeros(K, V) - For each chunk i from 0 to NT-1: - Load inputs for chunk i - Compute A_kk, Aqk intra-chunk - Forward substitution on A_kk - Compute w, u - Compute v_i = u_i - w_i @ S - Compute o_i = (q_i * exp(g_i)) @ S + Aqk @ v_i - Store o_i - Update S This is a LOT of code for one kernel, but it eliminates all intermediate kernel launches and memory traffic. For K=V=128, S is 128×128 = 16K fp32 = 64KB. With shared memory limit of ~228KB, this fits easily. The inputs per chunk are: - q: 64×128 = 8K - k: 64×128 = 8K - v: 64×128 = 8K - g: 64×128 = 8K (fp32 = 16K) - beta: 64 - A_kk: 64×64 = 4K - Aqk: 64×64 = 4K Total shared memory: 64KB (S) + 8+8+8+16+0.25+4+4 = 112KB. This is within limits. But writing this entire kernel in CUDA is complex. In Triton, we can't easily do the sequential forward substitution on a 64×64 matrix within the same kernel because Triton doesn't have good support for sequential loops with complex control flow. Wait, actually we CAN do it in Triton. Let me think... In Triton, within a kernel, we can have a `for` loop over chunks. For each chunk: 1. Load q, k, v, g, beta tiles 2. Compute A_kk using `tl.dot` 3. Do forward substitution using a sequential loop with `tl.dot` for matrix updates 4. Compute w, u, v_i, o_i 5. Update S The issue is that the forward substitution on a 64×64 matrix requires sequential row updates. In Triton, if each thread block handles one chunk, we can do this in registers/shared memory. But Triton is designed for parallelizing over large dimensions, not for sequential algorithms on small matrices. A CUDA kernel might be more appropriate here. Actually, let me try a pragmatic approach. I'll write: 1. A CUDA kernel for the forward substitution (already done, 0.034ms) 2. A Triton kernel for the inter-chunk recurrence 3. Optimized PyTorch for everything else For the inter-chunk Triton kernel, I'll write it as a single kernel that processes all chunks sequentially per (B, H, V_tile). Let me write this kernel now. I'll base it heavily on FLA's `chunk_gated_delta_rule_fwd_kernel_h_blockdim64` and `chunk_gla_fwd_kernel_o`.
WriteFile /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
diff (369 lines — TRUNCATED)
--- a//home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
+++ b//home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
@@ -1,11 +1,216 @@
-"""Initial naive solution based on reference.py for baseline."""
+"""KDA forward solution with custom CUDA and Triton kernels."""
 from __future__ import annotations
+
+import math
 
 import torch
 import torch.nn as nn
-from einops import rearrange
-
-
+import triton
+import triton.language as tl
+
+# ---------------------------------------------------------------------------
+# CUDA forward substitution kernel (loaded inline)
+# ---------------------------------------------------------------------------
+_CUDA_FWD_SUBST_SRC = """
+__global__ void fwd_subst_kernel(float* __restrict__ A, int C, int batch) {
+    int b = blockIdx.x;
+    if (b >= batch) return;
+    int tid = threadIdx.x;
+    __shared__ float s_A[64][64];
+    __shared__ float s_row[64];
+    float* mat = A + b * C * C;
+    for (int idx = tid; idx < C * C; idx += blockDim.x) {
+        s_A[idx / C][idx % C] = mat[idx];
+    }
+    __syncthreads();
+    for (int i = 1; i < C; i++) {
+        if (tid < i) s_row[tid] = s_A[i][tid];
+        __syncthreads();
+        if (tid < i) {
+            float sum = 0.0f;
+            for (int k = 0; k < i; k++) {
+                sum += s_row[k] * s_A[k][tid];
+            }
+            s_A[i][tid] += sum;
+        }
+        __syncthreads();
+    }
+    for (int idx = tid; idx < C * C; idx += blockDim.x) {
+        mat[idx] = s_A[idx / C][idx % C];
+    }
+}
+torch::Tensor fwd_subst(torch::Tensor A) {
+    int batch = A.size(0);
+    int C = A.size(1);
+    fwd_subst_kernel<<<batch, 64>>>(A.data_ptr<float>(), C, batch);
+    return A;
+}
+"""
+
+_fwd_subst_mod = torch.utils.cpp_extension.load_inline(
+    name="kda_fwd_subst",
+    cpp_sources="torch::Tensor fwd_subst(torch::Tensor A);",
+    cuda_sources=_CUDA_FWD_SUBST_SRC,
+    functions=["fwd_subst"],
+    extra_cuda_cflags=["-O3"],
+    verbose=False,
+)
+
+
+# ---------------------------------------------------------------------------
+# Triton kernel: inter-chunk recurrence + output
+# ---------------------------------------------------------------------------
+@triton.jit
+def kda_inter_chunk_kernel(
+    q_ptr,
+    k_ptr,
+    u_ptr,
+    w_ptr,
+    g_ptr,
+    Aqk_ptr,
+    o_ptr,
+    B: tl.constexpr,
+    T: tl.constexpr,
+    H: tl.constexpr,
+    K: tl.constexpr,
+    V: tl.constexpr,
+    BT: tl.constexpr,
+    BV: tl.constexpr,
+    scale: tl.constexpr,
+):
+    i_v = tl.program_id(0)
+    i_bh = tl.program_id(1)
+    i_b = i_bh // H
+    i_h = i_bh % H
+
+    NT = T // BT
+
+    # State tiles: K is fixed at 128, split into two 64-wide tiles
+    # S1: (64, BV), S2: (64, BV)
+    b_S1 = tl.zeros((64, BV), dtype=tl.float32)
+    b_S2 = tl.zeros((64, BV), dtype=tl.float32)
+
+    # Pointers base
+    q_base = q_ptr + (i_b * T * H + i_h) * K
+    k_base = k_ptr + (i_b * T * H + i_h) * K
+    u_base = u_ptr + (i_b * T * H + i_h) * V
+    w_base = w_ptr + (i_b * T * H + i_h) * K
+    g_base = g_ptr + (i_b * T * H + i_h) * K
+    Aqk_base = Aqk_ptr + (i_b * T * H + i_h) * BT
+    o_base = o_ptr + (i_b * T * H + i_h) * V
+
+    for i_t in range(NT):
+        t0 = i_t * BT
+
+        # Load u_i tile (BT, BV)
+        p_u = tl.make_block_ptr(
+            u_base, (T, V), (H * V, 1), (t0, i_v * BV), (BT, BV), (1, 0)
+        )
+        b_v = tl.load(p_u, boundary_check=(0, 1)).to(tl.float32)
+
+        # v_i = u_i - w_i @ S
+        # First K tile (0:64)
+        p_w = tl.make_block_ptr(
+            w_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
+        )
+        b_w = tl.load(p_w, boundary_check=(0, 1))
+        b_v -= tl.dot(b_w, b_S1.to(b_w.dtype))
+
+        # Second K tile (64:128)
+        p_w = tl.make_block_ptr(
+            w_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
+        )
+        b_w = tl.load(p_w, boundary_check=(0, 1))
+        b_v -= tl.dot(b_w, b_S2.to(b_w.dtype))
+
+        # Compute o_i = (q_i * exp(g_i)) @ S + Aqk @ v_i
+        b_o = tl.zeros((BT, BV), dtype=tl.float32)
+
+        # qS from first K tile
+        p_q = tl.make_block_ptr(
+            q_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
+        )
+        p_g = tl.make_block_ptr(
+            g_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
+        )
+        b_q = tl.load(p_q, boundary_check=(0, 1))
+        b_g = tl.load(p_g, boundary_check=(0, 1)).to(tl.float32)
+        b_qg = (b_q * tl.exp(b_g)).to(b_q.dtype)
+        b_o += tl.dot(b_qg, b_S1.to(b_qg.dtype))
+
+        # qS from second K tile
+        p_q = tl.make_block_ptr(
+            q_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
+        )
+        p_g = tl.make_block_ptr(
+            g_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
+        )
+        b_q = tl.load(p_q, boundary_check=(0, 1))
+        b_g = tl.load(p_g, boundary_check=(0, 1)).to(tl.float32)
+        b_qg = (b_q * tl.exp(b_g)).to(b_q.dtype)
+        b_o += tl.dot(b_qg, b_S2.to(b_qg.dtype))
+
+        b_o *= scale
+
+        # Aqk @ v_i
+        p_Aqk = tl.make_block_ptr(
+            Aqk_base, (T, BT), (H * BT, 1), (t0, 0), (BT, BT), (1, 0)
+        )
+        b_Aqk = tl.load(p_Aqk, boundary_check=(0, 1))
+        # Mask to strict lower triangular
+        o_i = tl.arange(0, BT)
+        m_s = o_i[:, None] >= o_i[None, :]
+        b_Aqk = tl.where(m_s, b_Aqk, 0.0).to(b_v.dtype)
+        b_o += tl.dot(b_Aqk, b_v.to(b_Aqk.dtype))
+
+        # Store o_i
+        p_o = tl.make_block_ptr(
+            o_base, (T, V), (H * V, 1), (t0, i_v * BV), (BT, BV), (1, 0)
+        )
+        tl.store(p_o, b_o.to(o_ptr.dtype.element_ty), boundary_check=(0, 1))
+
+        # Update state S
+        # decay = exp(g_i[:, -1])
+        last_idx = t0 + BT - 1
+        p_glast1 = g_base + last_idx * H * K + tl.arange(0, 64)
+        p_glast2 = g_base + last_idx * H * K + 64 + tl.arange(0, 64)
+        b_glast1 

... (7153 more chars)
args
{
  "path": "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py",
  "content": "<11019 chars \u2014 see diff>"
}
tool
stdout (74 chars)
<system>File successfully overwritten. Current size: 11019 bytes.</system>
assistant
reasoning (60 chars)
Let me run check.py to see if this passes correctness first.
Shell
args
{
  "command": "cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python check.py",
  "timeout": 120
}
tool
stdout (132 chars)
<system>ERROR: Command failed with exit code: 1.</system>
FAIL: import error: module 'torch.utils' has no attribute 'cpp_extension'
assistant
reasoning (101 chars)
`torch.utils.cpp_extension` might not be available. Let me check what's available and fix the import.
Shell
args
{
  "command": "python -c \"import torch.utils.cpp_extension; print('available')\" 2>&1 || echo \"not available\""
}
tool
stdout (58 chars)
<system>Command executed successfully.</system>
available
assistant
reasoning (179 chars)
The import works in a standalone script but not when imported as part of check.py. Maybe it's an issue with the import path or uv environment. Let me try importing it differently.
Shell
args
{
  "command": "<156 chars \u2014 see below>"
}
command (156 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
from torch.utils.cpp_extension import load_inline
print('OK')
"
tool
stdout (51 chars)
<system>Command executed successfully.</system>
OK
assistant
reasoning (123 chars)
The import works fine. Maybe the issue is with how check.py imports solution.py. Let me try importing solution.py directly.
Shell
args
{
  "command": "cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c \"import solution; print('OK')\" 2>&1"
}
tool
stdout (414 chars)
<system>ERROR: Command failed with exit code: 1.</system>
Traceback (most recent call last):
  File "<string>", line 1, in <module>
  File "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py", line 50, in <module>
    _fwd_subst_mod = torch.utils.cpp_extension.load_inline(
                     ^^^^^^^^^^^^^^^^^^^^^^^^^
AttributeError: module 'torch.utils' has no attribute 'cpp_extension'
assistant
reasoning (249 chars)
This is strange. `torch.utils.cpp_extension` exists but `torch.utils` doesn't have the `cpp_extension` attribute when imported from solution.py. This might be a lazy import issue. Let me explicitly import `torch.utils.cpp_extension` before using it.
StrReplaceFile /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
args
{
  "path": "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py",
  "edit": {
    "old": "import torch\nimport torch.nn as nn\nimport triton\nimport triton.language as tl",
    "new": "import torch\nimport torch.nn as nn\nfrom torch.utils.cpp_extension import load_inline\nimport triton\nimport triton.language as tl"
  }
}
tool
stdout (89 chars)
<system>File successfully edited. Applied 1 edit(s) with 1 total replacement(s).</system>
assistant
reasoning (80 chars)
I also need to update the load_inline call to not use torch.utils.cpp_extension.
StrReplaceFile /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
args
{
  "path": "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py",
  "edit": {
    "old": "_fwd_subst_mod = torch.utils.cpp_extension.load_inline(",
    "new": "_fwd_subst_mod = load_inline("
  }
}
tool
stdout (89 chars)
<system>File successfully edited. Applied 1 edit(s) with 1 total replacement(s).</system>
assistant
reasoning (26 chars)
Let me run check.py again.
Shell
args
{
  "command": "cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python check.py",
  "timeout": 180
}
tool
stdout (2079 chars) — TRUNCATED
<system>ERROR: Command failed with exit code: 1.</system>
Traceback (most recent call last):
  File "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/check.py", line 113, in <module>
    main()
  File "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/check.py", line 74, in main
    sol_out = sol_model(*inputs)
              ^^^^^^^^^^^^^^^^^^
  File "/home/infatoshi/.local/lib/python3.12/site-packages/torch/nn/modules/module.py", line 1779, in _wrapped_call_impl
    return self._call_impl(*args, **kwargs)
           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "/home/infatoshi/.local/lib/python3.12/site-packages/torch/nn/modules/module.py", line 1790, in _call_impl
    return forward_call(*args, **kwargs)
           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py", line 298, in forward
    kda_inter_chunk_kernel[grid](
  File "/home/infatoshi/.local/lib/python3.12/site-packages/triton/runtime/jit.py", line 370, in <lambda>
    return lambda *args, **kwargs: self.run(grid=grid, warmup=False, *args, **kwargs)
                                   ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "/home/infatoshi/.local/lib/python3.12/site-packages/triton/runtime/jit.py", line 743, in run
    launch_metadata = kernel.launch_metadata(grid, stream, *bound_args.values())
                      ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "/home/infatoshi/.local/lib/python3.

... (579 more chars)
assistant
reasoning (3238 chars)
The Triton kernel is using too much shared memory. The compiler is allocating 427KB of shared memory, which exceeds the 101KB limit. This is because Triton is trying to optimize the matmuls and using too much shared memory for the tiles. I need to reduce the shared memory usage. The main issue is probably that Triton is trying to tile the 64×64 and 64×128 matmuls with large tiles. I can add `num_stages=1` to reduce shared memory, or I can reduce the block sizes. Actually, looking at the kernel, I have `BV=64` and I'm doing matmuls with shapes like `(64, 64) @ (64, 64)` and `(64, 64) @ (64, 64)`. Triton might be using large tiles for these. Wait, the issue might be that Triton sees K=128 and tries to tile both K and V dimensions aggressively. With BV=64 and the K tiles of 64, Triton might use BK=64 for the reduction dimension. The shared memory limit of 101KB is strange for SM120 Blackwell. Blackwell should have 228KB shared memory per SM. But Triton is reporting 101KB, which suggests it's using a conservative limit or the consumer Blackwell has less shared memory. Actually, looking at the Triton 3.6 release notes, Blackwell support might still be evolving. The shared memory limit of 101KB is typical for Ampere/Ada. For Blackwell, it should be higher, but maybe Triton hasn't been updated yet. Let me try reducing the shared memory usage by: 1. Using smaller tiles (BV=32 instead of 64) 2. Adding `num_stages=1` to the kernel launch Actually, `num_stages` is a launch parameter, not a kernel parameter. I can pass it when launching the kernel. Wait, in Triton, `num_stages` is a compile-time parameter for the autotuner. For manual kernels, I can pass it as a launch config option. Actually, looking at the error, it says "out of resource: shared memory, Required: 427008". That's a huge amount. Let me check if the issue is from the `tl.dot` operations. Triton might be using very large tiles for the dot products. For the matmul `(BT, 64) @ (64, BV)` where BT=64 and BV=64, Triton might tile with something like 64×64 for both inputs, requiring 64×64 + 64×64 = 8K elements per tile, but with pipelining (num_stages), it doubles or triples this. For 427KB, that's way more than expected. Maybe Triton is trying to do the entire 64×64 @ 64×64 in shared memory without tiling? Actually, I think the issue is that Triton is autotuning and trying different tile sizes, some of which use too much shared memory. But since I'm not using autotune, Triton should use default tiles. Wait, in Triton 3.6, the default tile size for `tl.dot` might be large. Let me explicitly specify smaller tiles by using a `num_warps` and `num_stages` in the kernel launch. Actually, for Triton kernels without autotune, the launch config can specify `num_warps` and `num_stages`: ```python kda_inter_chunk_kernel[grid](..., num_warps=4, num_stages=1) ``` Let me try this. Also, I can try using `BV=32` to reduce the tile size. Wait, another issue: in my kernel, I'm loading `b_S1` and `b_S2` which are 64×64 fp32 tensors. That's 32KB total. The compiler might keep these in shared memory or registers. But combined with the matmul tiles, it could exceed the limit. Let me try launching with `num_warps=4, num_stages=1` first.
StrReplaceFile /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
args
{
  "path": "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py",
  "edit": {
    "old": "        grid = (triton.cdiv(V, BV), B * H)\n        kda_inter_chunk_kernel[grid](\n            q_flat,\n            k_flat,\n            u_flat,\n            w_flat,\n            g_flat,\n            Aqk_flat,\n            o,\n            B=B,\n            T=T,\n            H=H,\n            K=K,\n            V=V,\n            BT=BT,\n            BV=BV,\n            scale=self.scale,\n        )",
    "new": "        grid = (triton.cdiv(V, BV), B * H)\n        kda_inter_chunk_kernel[

... (382 more chars)
tool
stdout (89 chars)
<system>File successfully edited. Applied 1 edit(s) with 1 total replacement(s).</system>
assistant
reasoning (26 chars)
Let me run check.py again.
Shell
args
{
  "command": "cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python check.py",
  "timeout": 180
}
tool
stdout (53 chars)
<system>Command executed successfully.</system>
PASS
assistant
reasoning (82 chars)
Great! The correctness passes. Now let me run benchmark.py to see the performance.
Shell
args
{
  "command": "cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python benchmark.py",
  "timeout": 180
}
tool
stdout (56 chars)
<system>ERROR: Command killed by timeout (180s)</system>
assistant
reasoning (204 chars)
The benchmark timed out. This is likely because benchmark.py runs the eager reference, compiled reference, and SOTA, which are all slow. Let me run just the solution timing directly to see how fast it is.
Shell
args
{
  "command": "<1395 chars \u2014 see below>",
  "timeout": 120
}
command (1395 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import solution
import shapes

device = torch.device('cuda:0')
for shape_idx, shape in enumerate(shapes.SHAPES):
    for k, v in shape.items():
        setattr(reference, k, v)
    
    init_args = reference.get_init_inputs()
    ref_model = reference.Model(*init_args).to(device).eval()
    sol_model = solution.Model(*init_args).to(device).eval()
    
    torch.manual_seed(2026)
    inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]
    
    # Warmup
    with torch.no_grad():
        for _ in range(5):
            _ = sol_model(*inputs)
    torch.cuda.synchronize()
    
    # Time
    start = torch.cuda.Event(enable_timing=True)
    end = torch.cuda.Event(enable_timing=True)
    start.record()
    with torch.no_grad():
        for _ in range(50):
            _ = sol_model(*inputs)
    end.record()
    torch.cuda.synchronize()
    ms = start.elapsed_time(end) / 50
    
    # FLOPs
    B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
    CHUNK_SIZE = shape['CHUNK_SIZE']
    flops = 4 * B * T * H * (K * V + CHUNK_SIZE * K + CHUNK_SIZE * V)
    tflops = flops / (ms * 1e-3) / 1e12
    peak_frac = tflops / 200.0
    
    print(f'Shape {shape_idx}: {ms:.3f} ms, {tflops:.2f} TFLOPS, peak_fraction={peak_frac:.4f}')
"
tool
stdout (260 chars)
<system>Command executed successfully.</system>
Shape 0: 0.452 ms, 4.75 TFLOPS, peak_fraction=0.0238
Shape 1: 0.900 ms, 4.77 TFLOPS, peak_fraction=0.0239
Shape 2: 1.391 ms, 3.09 TFLOPS, peak_fraction=0.0154
Shape 3: 0.583 ms, 1.84 TFLOPS, peak_fraction=0.0092
assistant
reasoning (447 chars)
The performance is about 0.45-1.4ms depending on shape, which gives peak fractions of 0.9% to 2.4%. This is well below the 10% threshold needed for "OK". I need to optimize much more aggressively. The main bottlenecks are: 1. Intra-chunk einsum/bmm: ~0.2ms (from earlier profiling) 2. Forward substitution CUDA kernel: ~0.03ms 3. Inter-chunk Triton kernel: probably the rest Wait, let me profile the solution to see where time is actually spent.
Shell
args
{
  "command": "<846 chars \u2014 see below>",
  "timeout": 120
}
command (846 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import solution
import shapes

device = torch.device('cuda:0')
shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
sol_model = solution.Model(*init_args).to(device).eval()

torch.manual_seed(2026)
inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]

# Profile with torch.profiler
from torch.profiler import profile, ProfilerActivity
with profile(activities=[ProfilerActivity.CPU, ProfilerActivity.CUDA], record_shapes=True) as prof:
    with torch.no_grad():
        for _ in range(10):
            _ = sol_model(*inputs)
            torch.cuda.synchronize()

print(prof.key_averages().table(sort_by='cuda_time_total', row_limit=20))
"
tool
stdout (5134 chars) — TRUNCATED
<system>Command executed successfully.</system>
/home/infatoshi/.local/lib/python3.12/site-packages/torch/profiler/profiler.py:224: UserWarning: Warning: Profiler clears events at the end of each cycle.Only events from the current cycle will be reported.To keep events across cycles, set acc_events=True.
  _warn_once(
-------------------------------------------------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  
                                                   Name    Self CPU %      Self CPU   CPU total %     CPU total  CPU time avg     Self CUDA   Self CUDA %    CUDA total  CUDA time avg    # of Calls  
-------------------------------------------------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  
                                 kda_inter_chunk_kernel         0.00%       0.000us         0.00%       0.000us       0.000us       4.808ms        53.89%       4.808ms     480.761us            10  
                                            aten::copy_         3.57%       4.716ms         7.42%       9.802ms      57.660us       1.990ms        22.30%       2.015ms      11.855us           170  
                                            aten::clone         0.40%     527.595us         1.66%       2.194ms      16.874us       0.000us         0.00%       1.555ms      11.963us         

... (3634 more chars)
assistant
reasoning (4935 chars)
Interesting! The profiler shows: - `kda_inter_chunk_kernel`: 4.808ms for 10 calls = 0.48ms per call - `aten::copy_`: 1.990ms - `aten::clone`: 1.555ms - `aten::bmm`: 0.57ms - `fwd_subst_kernel`: 0.311ms - Various other PyTorch ops So the inter-chunk Triton kernel takes ~0.48ms, which is about half the total time. But there are also many copy/clone operations that add up. Wait, but I measured ~0.9ms total earlier. The profiler shows 8.92ms for 10 iterations = 0.892ms per iteration. That matches. The Triton kernel takes 0.48ms per call, which is still quite slow. It should be much faster. Let me see if I can optimize it. Looking at the kernel, I have `num_warps=4, num_stages=1`. But the kernel might still be using too many registers or not saturating the GPU. Let me think about why the Triton kernel is slow. For B=2, H=8, V_tiles=2, we have 32 thread blocks. Each block processes 32 chunks (for T=2048). With 4 warps per block = 128 threads, that's 32 * 128 = 4096 threads total. For each chunk, the kernel does: 1. Load u_i (64×64) = 4096 floats 2. Load w_i (64×64) twice = 8192 floats 3. Two matmuls for v_i: each is (64,64) @ (64,64) = 2 × 262K FLOPs 4. Load q_i, g_i twice = 8192 floats 5. Two matmuls for qS = 2 × 262K FLOPs 6. Load Aqk (64×64) = 4096 floats 7. Matmul Aqk @ v_i = (64,64) @ (64,64) = 262K FLOPs 8. Store o_i (64×64) = 4096 floats 9. Load k_i, g_i twice = 8192 floats 10. Two matmuls for state update = 2 × 262K FLOPs Total per chunk: ~40K floats loaded/stored + ~1.3M FLOPs For 32 chunks: ~1.3M floats + ~42M FLOPs At 1.8TB/s, 1.3M floats (5.2MB) takes ~2.9 microseconds At 200 TFLOPS, 42M FLOPs takes ~0.2 microseconds So the theoretical minimum is ~3 microseconds per block, or ~0.003ms total for all 32 blocks. But we're getting 0.48ms, which is 160x slower! This suggests the kernel is not well-optimized. The issue might be: 1. Small number of thread blocks (32) doesn't saturate the GPU 2. Register spilling or poor instruction scheduling 3. Memory access patterns With only 32 thread blocks on a GPU with many SMs (RTX PRO 6000 has ~120 SMs?), most SMs are idle. Each thread block processes 32 chunks sequentially, but there are only 32 thread blocks total. Wait, for B=2, H=8, V_tiles=2: grid = (2, 16). Yes, only 32 thread blocks. That's very few for a GPU with 120+ SMs. The solution is to increase parallelism. Instead of having each thread block process all chunks sequentially, we can have more thread blocks by processing chunks in parallel or using smaller V tiles. But the inter-chunk recurrence is sequential, so we can't parallelize across chunks. However, we can increase the number of thread blocks by using smaller V tiles. With BV=32, we'd have 64 thread blocks. With BV=16, we'd have 128 thread blocks. Let me try BV=32. Actually, there's another issue. With only 4 warps per block (128 threads), and each block doing 32 chunks, the GPU might not have enough occupancy. Let me also try increasing num_warps to 8. Another optimization: in the kernel, I'm doing `b_S1 = tl.zeros((64, BV), dtype=tl.float32)`. For BV=64, this is 4096 fp32 values. The compiler might put these in shared memory or registers. With 128 threads, if each thread holds 32 fp32 values, that's manageable. Let me try different configurations. Actually, let me also check if the slow performance is because Triton is compiling the kernel slowly. The first call might take longer. Let me measure with more warmup iterations. Wait, looking at the profiler again: `kda_inter_chunk_kernel` shows 480.761us per call. For 32 blocks, that's 480us / 32 = 15us per block. With 32 chunks per block, that's 15us / 32 = 0.47us per chunk. Actually, the kernel time is the total time across all blocks. Since blocks run in parallel, 480us is the wall-clock time for all 32 blocks to finish. With 32 blocks on a 120-SM GPU, most blocks run immediately without queuing. So the wall-clock time per block is roughly 480us. With 32 chunks per block, each chunk takes 480us / 32 = 15us. That's still very slow for what should be ~3us of memory traffic per chunk. The issue might be that with num_warps=4 and num_stages=1, Triton is not using Tensor Cores efficiently for the small matmuls. The 64×64 @ 64×64 matmuls might be falling back to SIMT (CUDA cores) instead of Tensor Cores, which is much slower. On Blackwell, the Tensor Cores might need larger tile sizes to be efficient. Or Triton might not be generating optimal code for SM120 yet. Let me try using `num_warps=8` to give Triton more threads to work with. Actually, another thought: in the kernel, I'm doing many `tl.dot` operations with shapes (64, 64) @ (64, BV). Triton might tile these as (64, 64) @ (64, 64) which is a standard matmul size. But with BV=64, the output is 64×64. Let me check if Triton is using Tensor Cores by looking at the generated PTX or by using ncu. Actually, let me first try to see if changing num_warps helps.
Shell
args
{
  "command": "<4892 chars \u2014 see below>",
  "timeout": 120
}
command (4892 chars — TRUNCATED)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import solution
import shapes

device = torch.device('cuda:0')
shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
sol_model = solution.Model(*init_args).to(device).eval()

torch.manual_seed(2026)
inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]

# Warmup
with torch.no_grad():
    for _ in range(10):
        _ = sol_model(*inputs)

torch.cuda.synchronize()

# Time with different num_warps by modifying the kernel launch
# Actually, let's just test num_warps=8 directly
from solution import kda_inter_chunk_kernel

B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
BT = shape['CHUNK_SIZE']
BV = 64

# Get the intermediate tensors
with torch.no_grad():
    # Run forward once to get tensors
    qf = inputs[0].float() * (float(K) ** -0.5)
    kf = inputs[1].float()
    vf = inputs[2].float()
    gf = inputs[3].float()
    bf = inputs[4].float()
    
    B_, T_, H_, K_ = qf.shape
    V_ = vf.shape[-1]
    NT_ = T_ // BT
    
    qf = qf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4)
    kf = kf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4)
    vf = vf.view(B_, NT_, BT, H_, V_).permute(0, 3, 1, 2, 4)
    gf = gf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4)
    bf = bf.view(B_, NT_, BT, H_).permute(0, 3, 1, 2)
    
    gf = gf.cumsum(-2)
    
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    BHN = B_ * H_ * NT_
    kg_flat = kg.reshape(BHN, BT, K_)
    kgn_flat = kgn.reshape(BHN, BT, K_)
    A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_upper = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=0)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    A_flat = A.view(BHN, BT, BT).contiguous()
    A_flat = solution._fwd_subst_mod.fwd_subst(A_flat)
    A = A_flat.view(B_, H_, NT_, BT, BT)
    I = torch.eye(BT, device=device, dtype=torch.float32)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    qg_flat = qg.reshape(BHN, BT, K_)
    Aqk = torch.bmm(qg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_strict = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=1)
    Aqk = Aqk.masked_fill(mask_strict, 0)
    
    q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    k_flat = kf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    u_flat = u.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, V_)
    w_flat = w.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    g_flat = gf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    Aqk_flat = Aqk.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, BT)
    o = torch.empty_like(inputs[2])
    
    scale = float(K_) ** -0.5
    
    # Test with num_warps=8
    grid = (triton.cdiv(V_, BV), B_ * H_)
    kda_inter_chunk_kernel[grid](
        q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o,
        B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV, scale=scale,
        num_warps=8, num_stages=1,
    )
    torch.cuda.synchronize()
    
    start = torch.cuda.Event(enable_timing=True)
    end = torch.cuda.Event(enable_timing=True)
    start.record()
    for _ in range(100):
        kda_inter_chunk_kernel[grid](
            q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o,
            B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV, scale=scale,
            num_warps=8, num_stages=1,
        )
    end.record()
    torch.cuda.synchronize()
    print(f'num_warps=8: {start.elapsed_time(end)/100:.4f} ms')
    
    # Test with num_warps=4, BV=32
    BV2 = 32
    o2 = torch.empty_like(inputs[2])
    grid2 = (triton.cdiv(V_, BV2), B_ * H_)
    kda_inter_chunk_kernel[grid2](
        q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o2,
        B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV2, scale=s

... (892 more chars)
tool
stdout (173 chars)
<system>ERROR: Command failed with exit code: 1.</system>
Traceback (most recent call last):
  File "<string>", line 87, in <module>
NameError: name 'triton' is not defined
assistant
reasoning (43 chars)
I need to import triton in the test script.
Shell
args
{
  "command": "<4708 chars \u2014 see below>",
  "timeout": 120
}
command (4708 chars — TRUNCATED)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import triton
import reference
import solution
import shapes

device = torch.device('cuda:0')
shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
sol_model = solution.Model(*init_args).to(device).eval()

torch.manual_seed(2026)
inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]

# Warmup
with torch.no_grad():
    for _ in range(10):
        _ = sol_model(*inputs)

torch.cuda.synchronize()

from solution import kda_inter_chunk_kernel

B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
BT = shape['CHUNK_SIZE']
BV = 64

# Get the intermediate tensors
with torch.no_grad():
    qf = inputs[0].float() * (float(K) ** -0.5)
    kf = inputs[1].float()
    vf = inputs[2].float()
    gf = inputs[3].float()
    bf = inputs[4].float()
    
    B_, T_, H_, K_ = qf.shape
    V_ = vf.shape[-1]
    NT_ = T_ // BT
    
    qf = qf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4)
    kf = kf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4)
    vf = vf.view(B_, NT_, BT, H_, V_).permute(0, 3, 1, 2, 4)
    gf = gf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4)
    bf = bf.view(B_, NT_, BT, H_).permute(0, 3, 1, 2)
    
    gf = gf.cumsum(-2)
    
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    BHN = B_ * H_ * NT_
    kg_flat = kg.reshape(BHN, BT, K_)
    kgn_flat = kgn.reshape(BHN, BT, K_)
    A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_upper = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=0)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    A_flat = A.view(BHN, BT, BT).contiguous()
    A_flat = solution._fwd_subst_mod.fwd_subst(A_flat)
    A = A_flat.view(B_, H_, NT_, BT, BT)
    I = torch.eye(BT, device=device, dtype=torch.float32)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    qg_flat = qg.reshape(BHN, BT, K_)
    Aqk = torch.bmm(qg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_strict = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=1)
    Aqk = Aqk.masked_fill(mask_strict, 0)
    
    q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    k_flat = kf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    u_flat = u.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, V_)
    w_flat = w.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    g_flat = gf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    Aqk_flat = Aqk.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, BT)
    o = torch.empty_like(inputs[2])
    
    scale = float(K_) ** -0.5
    
    # Test with num_warps=8
    grid = (triton.cdiv(V_, BV), B_ * H_)
    kda_inter_chunk_kernel[grid](
        q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o,
        B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV, scale=scale,
        num_warps=8, num_stages=1,
    )
    torch.cuda.synchronize()
    
    start = torch.cuda.Event(enable_timing=True)
    end = torch.cuda.Event(enable_timing=True)
    start.record()
    for _ in range(100):
        kda_inter_chunk_kernel[grid](
            q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o,
            B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV, scale=scale,
            num_warps=8, num_stages=1,
        )
    end.record()
    torch.cuda.synchronize()
    print(f'num_warps=8: {start.elapsed_time(end)/100:.4f} ms')
    
    # Test with BV=32
    BV2 = 32
    o2 = torch.empty_like(inputs[2])
    grid2 = (triton.cdiv(V_, BV2), B_ * H_)
    kda_inter_chunk_kernel[grid2](
        q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o2,
        B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV2, scale=scale,
        num_warps=4, num_stages=1,
    )
    torch.cuda.synchronize()
    
    start.record()
    for _ in range(100):
        kda_inter_chunk_

... (708 more chars)
tool
stdout (131 chars)
<system>Command executed successfully.</system>
num_warps=8: 0.5711 ms
BV=32, num_warps=4: 0.2474 ms
BV=32, num_warps=8: 4.2533 ms
assistant
reasoning (4177 chars)
BV=32 with num_warps=4 gives 0.247ms, which is much better than BV=64 with num_warps=4 (0.48ms). But BV=32 with num_warps=8 is terrible (4.25ms), probably due to register spilling. So BV=32, num_warps=4 is the sweet spot for the inter-chunk kernel. That's about 2x faster than before. Now let me update the solution to use BV=32 and num_warps=4, and see what the overall performance looks like. Also, I notice that the inter-chunk kernel still dominates. The total with BV=32 would be roughly: - Intra-chunk: ~0.2ms - Inter-chunk: ~0.25ms - Total: ~0.45ms For the headline shape, that's 0.45ms. FLOPs = 4.3B. TFLOPS = 4.3 / 0.00045 = 9.6 TFLOPS. Peak fraction = 9.6 / 200 = 4.8%. Still below 10%. For smaller shapes, it will be worse. Let me measure the actual total. But first, let me check if there are other optimizations I can make. Looking at the profiler output from earlier, there were many `aten::copy_` and `aten::clone` operations taking significant time. I should eliminate unnecessary copies. Let me also think about whether I can optimize the intra-chunk part further. The einsum/bmm takes ~0.2ms. Can I write a Triton kernel for this too? Actually, looking at FLA's performance (0.2ms total), my intra-chunk alone is about the same as their total! So there must be something fundamentally more efficient about their approach. Let me look at how FLA structures their intra-chunk computation. They have `chunk_kda_fwd_intra` which calls two kernels: 1. `chunk_kda_fwd_intra_token_parallel` - computes diagonal blocks 2. `chunk_kda_fwd_kernel_inter_solve_fused` - computes off-diagonal blocks + forward substitution These kernels operate on sub-chunks of size 16 within the chunk of 64. This allows better parallelism and Tensor Core utilization. For my solution, the main issue with the intra-chunk einsum is that I'm computing the FULL 64×64 matrix and then masking. A lot of compute is wasted on the upper triangular part. FLA's approach: 1. Compute diagonal 16×16 blocks directly 2. Compute off-diagonal blocks between sub-chunks 3. Do forward substitution on the diagonal blocks 4. Merge everything This is much more efficient because: - The diagonal blocks are computed with precise masking - The off-diagonal blocks are computed with block-wise matmuls - No wasted compute on the upper triangular But implementing this from scratch is very complex. Another approach: instead of computing A with einsum over the full 64×64, I can use a more efficient PyTorch operation. For example, `torch.tril` with `diagonal=-1` can be applied AFTER the matmul, but the matmul still computes all elements. Wait, I already do this. The issue is that for a 64×64 matmul with batch 512, even computing all elements is fast (0.2ms). The actual problem might be elsewhere. Let me look at the profiler output again. For the full solution, there were many `aten::copy_` operations. Let me trace where these come from. In my solution: ```python qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4) ``` This creates a non-contiguous tensor. Then when I do: ```python kg_flat = kg.reshape(BHN, BT, K) ``` `reshape` might need to copy if the tensor is not contiguous in that dimension. Let me make the tensors contiguous after permutation. Also, in the Triton kernel, I flatten back: ```python q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B, T, H, K) ``` This is also non-contiguous. But the Triton kernel reads with block pointers, so it might not matter much. Let me optimize the PyTorch part by using `contiguous()` after permutations. Actually, the bigger issue is that for each forward pass, I'm doing many operations: 1. `qf.view().permute()` 2. `gf.cumsum(-2)` 3. `kf * gf.exp()` - elementwise 4. `torch.bmm()` for A 5. `masked_fill` 6. `fwd_subst` 7. `matmul` for w and u 8. More `bmm` for Aqk 9. `permute().reshape()` for Triton kernel inputs 10. Triton kernel Many of these create intermediate tensors and do memory copies. For better performance, I should try to fuse more operations. But fusing everything into one kernel is hard. Let me first update the solution with BV=32 and see the overall performance. Then I'll look for more optimizations.
StrReplaceFile /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
args
{
  "path": "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py",
  "edit": {
    "old": "        BV = 64\n        grid = (triton.cdiv(V, BV), B * H)\n        kda_inter_chunk_kernel[grid](\n            q_flat,\n            k_flat,\n            u_flat,\n            w_flat,\n            g_flat,\n            Aqk_flat,\n            o,\n            B=B,\n            T=T,\n            H=H,\n            K=K,\n            V=V,\n            BT=BT,\n            BV=BV,\n            scale=self.scale,\n            num_warps=4,\n            num_stages=1,\n        )",
    "new": "     

... (469 more chars)
tool
stdout (89 chars)
<system>File successfully edited. Applied 1 edit(s) with 1 total replacement(s).</system>
assistant
reasoning (64 chars)
Let me run the timing test again to see the updated performance.
Shell
args
{
  "command": "<1334 chars \u2014 see below>",
  "timeout": 120
}
command (1334 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import solution
import shapes

device = torch.device('cuda:0')
for shape_idx, shape in enumerate(shapes.SHAPES):
    for k, v in shape.items():
        setattr(reference, k, v)
    
    init_args = reference.get_init_inputs()
    sol_model = solution.Model(*init_args).to(device).eval()
    
    torch.manual_seed(2026)
    inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]
    
    # Warmup
    with torch.no_grad():
        for _ in range(10):
            _ = sol_model(*inputs)
    torch.cuda.synchronize()
    
    # Time
    start = torch.cuda.Event(enable_timing=True)
    end = torch.cuda.Event(enable_timing=True)
    start.record()
    with torch.no_grad():
        for _ in range(50):
            _ = sol_model(*inputs)
    end.record()
    torch.cuda.synchronize()
    ms = start.elapsed_time(end) / 50
    
    # FLOPs
    B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
    CHUNK_SIZE = shape['CHUNK_SIZE']
    flops = 4 * B * T * H * (K * V + CHUNK_SIZE * K + CHUNK_SIZE * V)
    tflops = flops / (ms * 1e-3) / 1e12
    peak_frac = tflops / 200.0
    
    print(f'Shape {shape_idx}: {ms:.3f} ms, {tflops:.2f} TFLOPS, peak_fraction={peak_frac:.4f}')
"
tool
stdout (260 chars)
<system>Command executed successfully.</system>
Shape 0: 0.377 ms, 5.70 TFLOPS, peak_fraction=0.0285
Shape 1: 0.709 ms, 6.06 TFLOPS, peak_fraction=0.0303
Shape 2: 0.976 ms, 4.40 TFLOPS, peak_fraction=0.0220
Shape 3: 0.396 ms, 2.71 TFLOPS, peak_fraction=0.0136
assistant
reasoning (245 chars)
Performance improved from 2.4% to 3.0% peak fraction for the headline shape. But we're still far from the 10% target. Let me think about what's taking time. The full forward pass is ~0.7ms for shape 1. Let me profile again to see the breakdown.
Shell
args
{
  "command": "<816 chars \u2014 see below>",
  "timeout": 120
}
command (816 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import solution
import shapes

device = torch.device('cuda:0')
shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
sol_model = solution.Model(*init_args).to(device).eval()

torch.manual_seed(2026)
inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]

from torch.profiler import profile, ProfilerActivity
with profile(activities=[ProfilerActivity.CPU, ProfilerActivity.CUDA], record_shapes=True) as prof:
    with torch.no_grad():
        for _ in range(10):
            _ = sol_model(*inputs)
            torch.cuda.synchronize()

print(prof.key_averages().table(sort_by='cuda_time_total', row_limit=25))
"
tool
stdout (6124 chars) — TRUNCATED
<system>Command executed successfully.</system>
/home/infatoshi/.local/lib/python3.12/site-packages/torch/profiler/profiler.py:224: UserWarning: Warning: Profiler clears events at the end of each cycle.Only events from the current cycle will be reported.To keep events across cycles, set acc_events=True.
  _warn_once(
-------------------------------------------------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  
                                                   Name    Self CPU %      Self CPU   CPU total %     CPU total  CPU time avg     Self CUDA   Self CUDA %    CUDA total  CUDA time avg    # of Calls  
-------------------------------------------------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  ------------  
                                 kda_inter_chunk_kernel         0.00%       0.000us         0.00%       0.000us       0.000us       2.814ms        40.63%       2.814ms     281.415us            10  
                                            aten::copy_         3.30%       4.172ms         7.98%      10.084ms      59.318us       1.993ms        28.77%       2.019ms      11.875us           170  
                                            aten::clone         0.17%     209.729us         1.35%       1.710ms      13.154us       0.000us         0.00%       1.561ms      12.007us         

... (4624 more chars)
assistant
reasoning (19459 chars)
The profiler shows: - `kda_inter_chunk_kernel`: 2.814ms for 10 calls = 0.281ms per call - `aten::copy_`: 1.993ms - `aten::clone`: 1.490ms (indirect) - Various elementwise kernels: 1.490ms - `aten::bmm`: 0.571ms - `fwd_subst_kernel`: 0.312ms - `aten::matmul`: 0.338ms - `aten::cumsum`: 0.104ms Wait, the total CUDA time is 6.927ms for 10 iterations = 0.693ms per iteration. This is higher than my direct timing of 0.709ms... wait no, 6.927/10 = 0.6927ms, which is close to the 0.709ms I measured. The inter-chunk kernel is 0.281ms, which is about 40% of the total time. But there are also many copy and clone operations. Let me trace where these come from. Looking at my forward method: 1. `qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)` - creates non-contiguous tensor 2. `gf.cumsum(-2)` - creates new tensor 3. `kg = kf * gf.exp()` - elementwise, non-contiguous inputs 4. `kg_flat = kg.reshape(BHN, BT, K)` - might copy if not contiguous 5. `A = torch.bmm(...).view(...)` - bmm output is contiguous, but view is fine 6. `A = -A.masked_fill(mask_diag_upper, 0)` - masked_fill might copy 7. `A_flat = A.view(BHN, BT, BT).contiguous()` - explicit copy 8. `A_flat = _fwd_subst_mod.fwd_subst(A_flat)` - in-place, but needs contiguous 9. `A = A_flat.view(B, H, NT, BT, BT)` - view, fine 10. `A = (A + I) * bf[..., None, :]` - elementwise 11. `w = torch.matmul(A, (gf.exp() * kf))` - matmul 12. `u = torch.matmul(A, vf)` - matmul 13. Various permute/reshape for Triton inputs The copies are coming from: - `contiguous()` calls - `masked_fill` on non-contiguous tensors - `reshape` on non-contiguous tensors - `permute` + `reshape` combinations Let me optimize by making tensors contiguous earlier and avoiding unnecessary copies. Actually, a bigger optimization: can I avoid the `permute`/`reshape` dance entirely by working in the original (B, T, H, K) layout for the PyTorch operations? For the einsums, I can operate directly on (B, T, H, K) without chunking: ```python # q: (B, T, H, K) # We want Aqk[b, h, i, j] where i, j are within the same chunk # This is tricky without chunking ``` Actually, the chunking is necessary for the forward substitution, which operates on 64×64 blocks. So we do need the chunk layout. But we can make the chunk layout contiguous: ```python qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).contiguous() ``` This adds one copy but makes all subsequent operations faster. Similarly, after the intra-chunk computations, instead of doing: ```python q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B, T, H, K) ``` I can just use the original q tensor! The Triton kernel reads q, k, g from the original (B, T, H, K) layout. I don't need to flatten the chunked tensors. Wait, in my Triton kernel, I assume the inputs are in (B, T, H, K) layout with strides (T*H*K, H*K, K, 1). But when I do `permute` and `reshape`, the strides might be different. Let me check. `qf` is `q.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)`. - Original q has shape (B, T, H, K) and stride (T*H*K, H*K, K, 1) - After view: (B, NT, BT, H, K) with stride (T*H*K, BT*H*K, H*K, K, 1) - After permute(0, 3, 1, 2, 4): (B, H, NT, BT, K) with stride (T*H*K, K, BT*H*K, H*K, 1) Then `q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B, T, H, K)`: - After permute: (B, NT, BT, K, H) with stride (T*H*K, BT*H*K, H*K, 1, K) - After reshape: (B, T, H, K). But the stride is (T*H*K, H*K, 1, K), which is NOT the standard layout! The H and K dimensions are transposed in the stride. This means my Triton kernel is reading with incorrect strides! Let me check if the kernel still produces correct results... Wait, the kernel DID pass check.py, so the output is correct. How? Let me re-examine the Triton kernel pointer calculations: ```python q_base = q_ptr + (i_b * T * H + i_h) * K p_q = tl.make_block_ptr(q_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)) ``` This assumes the stride for the T dimension is `H * K` and for K is `1`. But if `q_flat` has stride `(T*H*K, H*K, 1, K)`, then: - Moving by 1 in T should be `H * K` (correct for standard layout) - Moving by 1 in K should be `1` (but it's `K` for the H dimension and `1` for the K dimension) Wait, `q_flat` is reshaped from `(B, NT, BT, K, H)` with permute. Let me trace more carefully. Original q: (B, T, H, K), stride = (T*H*K, H*K, K, 1) qf = q.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4) - view: shape=(B, NT, BT, H, K), stride=(T*H*K, BT*H*K, H*K, K, 1) - permute(0,3,1,2,4): shape=(B, H, NT, BT, K), stride=(T*H*K, K, BT*H*K, H*K, 1) q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B, T, H, K) - permute(0,2,3,4,1): shape=(B, NT, BT, K, H), stride=(T*H*K, BT*H*K, H*K, 1, K) - reshape(B, T, H, K): The last two dimensions K and H have strides 1 and K. But standard layout would have strides K and 1 for H and K. Wait, after reshape, the tensor is NOT contiguous and NOT in standard layout. But the values are correct because reshape preserves the total ordering. For the Triton kernel, I use: ```python q_base = q_ptr + (i_b * T * H + i_h) * K p_q = tl.make_block_ptr(q_base, (T, K), (H * K, 1), ...) ``` With `q_flat` having stride `(T*H*K, H*K, 1, K)` for dimensions `(B, T, H, K)`: - For a fixed (b, h), the base offset is `(b * T * H + h) * K`? No, the offset should be `b * T * H * K + t * H * K + h * K + k` for standard layout. - But with stride `(T*H*K, H*K, 1, K)`, the offset is `b * T*H*K + t * H*K + h * 1 + k * K`. - This is WRONG! It reads `q[b, t, h, k]` as `q[b, t, k, h]` from the original tensor! But the kernel passed check.py... How? Oh wait, when I do `q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B, T, H, K)`, the reshape might return a VIEW, not a copy. And since the original tensor `qf` has the values arranged as `(B, H, NT, BT, K)`, after permute to `(B, NT, BT, K, H)`, the reshape to `(B, T, H, K)` gives: - For position (b, t, h, k): t = chunk * 64 + pos, so t maps to (chunk, pos) - The value at `qf[b, h, chunk, pos, k]` becomes `q_flat[b, t, h, k]` But the stride of `q_flat` is `(T*H*K, H*K, 1, K)`, which means: - `q_flat[b, t, h, k]` is at `b*T*H*K + t*H*K + h*1 + k*K` And `qf[b, h, chunk, pos, k]` is at `b*T*H*K + h*K + chunk*BT*H*K + pos*H*K + k*1` After permute and reshape, `q_flat[b, t, h, k] = qf[b, h, chunk, pos, k]` where t = chunk*64 + pos. The memory address is: `b*T*H*K + chunk*BT*H*K + pos*H*K + h*1 + k*K`? No wait. Actually, `qf.permute(0,2,3,4,1)` gives shape `(B, NT, BT, K, H)` with stride `(T*H*K, BT*H*K, H*K, 1, K)`. So `q_perm[b, chunk, pos, k, h]` is at `b*T*H*K + chunk*BT*H*K + pos*H*K + k*1 + h*K`. After reshape to `(B, T, H, K)`, this becomes: `q_flat[b, t, h, k]` is at `b*T*H*K + chunk*BT*H*K + pos*H*K + k*1 + h*K` where t = chunk*BT + pos. But in standard layout, `q[b, t, h, k]` would be at `b*T*H*K + t*H*K + h*K + k*1`. So `q_flat` has: - T stride = H*K ✓ - H stride = K ✗ (it's 1) - K stride = 1 ✗ (it's K) So the H and K dimensions are SWAPPED in the memory layout! But my Triton kernel assumes standard layout with strides (H*K, 1). So when I read `q[b, t, h, k]` in the kernel, I actually get `q_flat[b, t, h, k]`, which corresponds to `qf[b, h, chunk, pos, k]` = `q[b, chunk*64+pos, h, k]`. Wait, but `q_flat` has H stride = 1 and K stride = K. So: `q_flat[b, t, h, k] = q_flat[b, t, 0, 0] + h*1 + k*K` = `q_perm[b, chunk, pos, 0, 0] + h*1 + k*K` = `qf[b, 0, chunk, pos, 0] + h*1 + k*K` = `q[b, chunk*64+pos, 0, 0] + h*1 + k*K` But `q[b, chunk*64+pos, h, k]` in standard layout is at `q[b, chunk*64+pos, 0, 0] + h*K + k*1`. So the kernel is reading `q[b, t, k, h]` instead of `q[b, t, h, k]`! Wait, but the check.py passed! How is that possible? Oh, I see. In the Triton kernel, I compute `qS` and `o_i`. If q's H and K are swapped, then `q_i` has shape (BT, K) but the memory is actually (K, BT) transposed. So `tl.dot(qg, S)` would compute `(K, BT) @ (K, V)` which is invalid. Actually, `tl.make_block_ptr` with shape `(T, K)` and strides `(H*K, 1)` loads a tile of shape `(BT, 64)`. The values loaded would be: For row i in [0, BT) and col j in [0, 64): `offset = (t0 + i) * H*K + j * 1` But `q_flat` at this offset contains `q_flat[b, t0+i, j, 0]` (since K stride is 1, H stride is K... wait, the overall stride is `(T*H*K, H*K, 1, K)` for dims `(B, T, H, K)`). So `q_flat[b, t, h, k]` is at `b*T*H*K + t*H*K + h*1 + k*K`. For `i` in row and `j` in col: `offset = b*T*H*K + (t0+i)*H*K + 0*1 + j*K`? No, the block_ptr uses strides `(H*K, 1)`, so: `offset = base + i * (H*K) + j * 1` `base = (b * T * H + h) * K`? Wait, I compute base as: `q_base = q_ptr + (i_b * T * H + i_h) * K` But `q_ptr` points to the start of the `q_flat` tensor. So: `q_base = q_flat[0, 0, i_h, 0]`... no, `q_ptr` is the data pointer. The base offset is `(i_b * T * H + i_h) * K` from the start of the tensor. For `q_flat` with stride `(T*H*K, H*K, 1, K)`: `offset = (i_b * T * H + i_h) * K + i * H*K + j * 1` = `i_b * T*H*K + i_h * K + i * H*K + j` = `i_b * T*H*K + (t0 + i) * H*K + i_h * K + j`? No, `i_h * K` is not the same as `i_h * 1`. Wait, `q_flat[b, t, h, k]` = `b*T*H*K + t*H*K + h*1 + k*K`. The block_ptr offset is `b*T*H*K*K + ...` No, let me be more careful. `base = (i_b * T * H + i_h) * K` = `i_b * T * H * K + i_h * K` For position (i, j) in the block: `offset = base + i * (H*K) + j * 1` = `i_b * T * H * K + i_h * K + i * H * K + j` But `q_flat[i_b, t0+i, h, k]` should be at: `i_b * T*H*K + (t0+i) * H*K + h * 1 + k * K` For these to be equal: `i_h * K + j = h * 1 + k * K` If `i_h = h` and `j = k*K`... that's impossible for j in [0, K). So the block_ptr is reading the WRONG memory locations! But the check passed... Wait, maybe `q_flat` is actually contiguous? Let me check. When I do `reshape`, if the tensor is contiguous in the reshaped dimensions, PyTorch might return a contiguous view. But if not, it returns a non-contiguous view. Actually, `qf` has shape `(B, H, NT, BT, K)` and stride `(T*H*K, K, BT*H*K, H*K, 1)`. Then `qf.permute(0, 2, 3, 4, 1)` has shape `(B, NT, BT, K, H)` and stride `(T*H*K, BT*H*K, H*K, 1, K)`. For this to be reshaped to `(B, T, H, K)` where T = NT*BT: The first dimension B has stride T*H*K. The second dimension T = NT*BT should have stride H*K. For t = chunk*BT + pos, the offset should be chunk*BT*H*K + pos*H*K. But from the permuted tensor, chunk has stride BT*H*K and pos has stride H*K. So yes, t has effective stride H*K. The third dimension H should have stride K. But in the permuted tensor, H has stride K. So yes, h has stride K. The fourth dimension K should have stride 1. But in the permuted tensor, K has stride 1. So yes, k has stride 1. Wait! I miscalculated the stride earlier. Let me recalculate: - `qf` shape: (B, H, NT, BT, K), stride: (T*H*K, K, BT*H*K, H*K, 1) - `permute(0, 2, 3, 4, 1)` -> dims [0, 2, 3, 4, 1] - New shape: (B, NT, BT, K, H) - New stride: (stride[0], stride[2], stride[3], stride[4], stride[1]) = (T*H*K, BT*H*K, H*K, 1, K) Now reshape to (B, T, H, K) where T = NT*BT: - Dim 0 (B): stride = T*H*K ✓ - Dim 1 (T): Since T = NT*BT and the inner dimensions NT and BT have strides BT*H*K and H*K, combining them gives stride H*K ✓ - Dim 2 (H): stride = K ✓ - Dim 3 (K): stride = 1 ✓ So `q_flat` IS in standard layout with stride (T*H*K, H*K, K, 1)! My earlier calculation was wrong because I got confused about which dimension maps to which. The permute(0,2,3,4,1) swaps H to the last position, and then reshape collapses NT,BT into T. So the final layout is indeed standard. OK so the strides are correct. That's why check.py passes. Now back to performance. The copies in the profiler are coming from: 1. `A_flat = A.view(BHN, BT, BT).contiguous()` - explicit copy 2. Various `to(torch.float32)` conversions on inputs 3. `masked_fill` creating copies 4. `permute` + `view` creating non-contiguous tensors that need to be copied for some operations Let me see if I can reduce copies by: 1. Making all reshaped tensors contiguous at the start 2. Using in-place operations where possible 3. Avoiding the explicit `.contiguous()` on A_flat by ensuring A is contiguous before the view For (1), I can do: ```python qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).contiguous() ``` For (3), `masked_fill` on a non-contiguous tensor might copy. If A is contiguous after the bmm, this should be fine. For (4), if A is contiguous, then `A.view(BHN, BT, BT)` should not need a copy. Let me ensure A is contiguous after the bmm. Actually, `torch.bmm` returns a contiguous tensor. So `A = torch.bmm(...).view(B, H, NT, BT, BT)` is contiguous. Then `A = A * bf[..., None]` is also contiguous (elementwise). Then `A = -A.masked_fill(...)`... `masked_fill` might return a copy if the tensor is not contiguous, but A is contiguous here. Wait, `masked_fill` on a contiguous tensor might still copy if it needs to change the memory layout. Actually, `masked_fill` on a contiguous tensor should be in-place or return a new contiguous tensor. Actually, looking at PyTorch docs, `masked_fill` returns a new tensor. So it always copies. We can use `masked_fill_` for in-place operation. Similarly, `cumsum` returns a new tensor. We can try to avoid this by using in-place operations where possible. Let me optimize the PyTorch code: 1. Use `.contiguous()` after permute 2. Use `masked_fill_` instead of `masked_fill` 3. Use in-place operations where possible But these are micro-optimizations. The real bottleneck is probably the Triton kernel and the matmul operations. Let me think about a more radical optimization. What if I write a single Triton kernel for the ENTIRE forward pass? For each thread block handling one (B, H, V_tile), I would: 1. Initialize state S = zeros(K, V_tile) 2. For each chunk: a. Load q, k, v, g, beta for the chunk b. Compute A_kk intra-chunk c. Forward substitution on A_kk d. Compute w, u e. Compute output and update state The issue is that steps b and c (intra-chunk) are complex to implement in Triton. But for K=128, C=64, it's manageable. Actually, looking at FLA's code, they have a separate kernel for intra-chunk because it's parallelizable across chunks. The inter-chunk is sequential. So fusing everything into one kernel would lose the parallelism of intra-chunk computations. But for our problem, with B*H*N = 512 chunks, the intra-chunk parallelism is decent. The inter-chunk has only 32 thread blocks (for B=2, H=8, V_tile=2). Wait, what if I process the intra-chunk computations in the SAME kernel but launch more thread blocks? Actually, for the inter-chunk kernel, each thread block processes all chunks sequentially. But the intra-chunk computations for different chunks are independent. So I can't easily parallelize them within a single thread block. What if I launch one thread block per (B, H, chunk, V_tile)? Then I'd have 512*2 = 1024 thread blocks for T=2048. But then the state S would need to be passed between thread blocks, which requires global memory. Actually, FLA's approach is: 1. Intra-chunk kernel: one block per chunk, computes A, w, u 2. Inter-chunk kernel: one block per (B, H, V_tile), sequential over chunks, computes output This is the optimal approach for parallelism. FLA just has much more optimized kernels. For my solution, the inter-chunk kernel is the bottleneck at 0.28ms. Can I optimize it further? Let me look at what the kernel is actually doing and see if I can reduce the number of matmuls or improve the tiling. In the kernel, for each chunk, I do: 1. `tl.dot(b_w, b_S1)` - (64, 64) @ (64, 32) 2. `tl.dot(b_w, b_S2)` - (64, 64) @ (64, 32) 3. `tl.dot(b_qg, b_S1)` - (64, 64) @ (64, 32) 4. `tl.dot(b_qg, b_S2)` - (64, 64) @ (64, 32) 5. `tl.dot(b_Aqk, b_v)` - (64, 64) @ (64, 32) 6. `tl.dot(b_kg.T, b_v)` - (64, 64).T @ (64, 32) = (64, 64) @ (64, 32) 7. Another `tl.dot(b_kg.T, b_v)` for the second K tile That's 7 matmuls of size (64, 64) @ (64, 32) per chunk. For 32 chunks: 224 matmuls per block. With 64 thread blocks (B=2, H=8, V_tiles=4 for BV=32), total matmuls = 224 * 64 = 14,336. Each matmul is 64*64*32*2 = 262K FLOPs. Total FLOPs = 14,336 * 262K = 3.76B FLOPs. At 200 TFLOPS, this is 0.019ms. But the actual time is 0.28ms, which is 15x slower. The overhead comes from: 1. Loading/storing data for each chunk 2. Kernel launch and synchronization overhead between chunks 3. Triton compiler not generating optimal code for SM120 For (2), since all chunks are in a single kernel, there's no kernel launch overhead between chunks. But there might be instruction scheduling overhead. For (3), Triton 3.6 might not fully optimize for Blackwell yet. Let me try a different approach: write the inter-chunk kernel in CUDA instead of Triton. This gives me more control over the memory access patterns and might avoid Triton's suboptimal code generation. Actually, let me first check if there are any obvious issues with my Triton kernel. One thing I notice is that I'm loading `b_glast1` and `b_glast2` using direct pointer arithmetic instead of `tl.load` with masks. Let me check if this is correct. ```python last_idx = t0 + BT - 1 p_glast1 = g_base + last_idx * H * K + tl.arange(0, 64) p_glast2 = g_base + last_idx * H * K + 64 + tl.arange(0, 64) b_glast1 = tl.load(p_glast1, mask=tl.arange(0, 64) < 64, other=0.0).to(tl.float32) b_glast2 = tl.load(p_glast2, mask=tl.arange(0, 64) < 64, other=0.0).to(tl.float32) ``` Wait, `g_base` is a pointer to the start of the g tensor. For a given (b, h), `g_base = g_ptr + (b * T * H + h) * K`. Then `g_base + last_idx * H * K + offset` points to `g[b, last_idx, h, offset]`. The stride in the T dimension is `H * K`, and in the K dimension is `1`. So this is correct. Another thing: in the state update, I compute: ```python b_kg = b_k * tl.exp(b_glast1[None, :] - b_g) ``` `b_glast1` has shape `(64,)`. `b_glast1[None, :]` has shape `(1, 64)`. `b_g` has shape `(64, 64)` (BT, BK). The subtraction broadcasts correctly. Then `b_S1 += tl.dot(b_kg.to(b_v.dtype).T, b_v.to(b_k.dtype))` `b_kg.T` has shape `(64, 64)` (BK, BT). `b_v` has shape `(64, 32)` (BT, BV). The dot gives `(64, 32)` which matches `b_S1`. Correct. Hmm, the kernel logic seems correct. The slowness is probably from Triton not generating optimal code. Let me try writing a CUDA kernel for the inter-chunk part. It will be more work but might be much faster. For the CUDA kernel, each block handles one (B, H, V_tile). I'll use shared memory for the state and for loading tiles. Actually, I realize there's another optimization I can try first. In the Triton kernel, I have a lot of `tl.dot` operations. Triton might be using more shared memory than necessary. Let me try explicitly specifying `num_stages=1` and see if that helps. I already do that. Let me also try using bf16 for the matmul inputs instead of fp32. Triton's `tl.dot` with bf16 inputs might use Tensor Cores more efficiently on Blackwell. Currently, I do: ```python b_v -= tl.dot(b_w, b_S1.to(b_w.dtype)) ``` Where `b_w` is loaded from the tensor (bf16) and `b_S1` is fp32. The `.to(b_w.dtype)` converts to bf16. So the matmul is in bf16. Wait, but `b_S1` is fp32 and I convert it to bf16 for the dot. The accumulation is still fp32 (Triton's default). This should use Tensor Cores. Let me check if the issue is that Triton is not using Tensor Cores for these small shapes. On some architectures, Tensor Cores have a minimum tile size. Actually, let me try running with `CUDA_VISIBLE_DEVICES=0` and checking ncu. But I don't have ncu installed. Let me check what's available.
Shell
args
{
  "command": "which ncu || which nv-nsight-cu-cli || echo \"ncu not found\""
}
tool
stdout (75 chars)
<system>Command executed successfully.</system>
/usr/local/cuda-13/bin/ncu
assistant
reasoning (65 chars)
Let me run ncu on the inter-chunk kernel to see what's happening.
Shell
args
{
  "command": "<3242 chars \u2014 see below>",
  "timeout": 120
}
command (3242 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import triton
import reference
import solution
import shapes

device = torch.device('cuda:0')
shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
sol_model = solution.Model(*init_args).to(device).eval()

torch.manual_seed(2026)
inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]

# Warmup
with torch.no_grad():
    for _ in range(5):
        _ = sol_model(*inputs)

# Now run just the inter-chunk kernel with ncu
from solution import kda_inter_chunk_kernel

B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
BT = shape['CHUNK_SIZE']
BV = 32

with torch.no_grad():
    qf = inputs[0].float() * (float(K) ** -0.5)
    kf = inputs[1].float()
    vf = inputs[2].float()
    gf = inputs[3].float()
    bf = inputs[4].float()
    
    B_, T_, H_, K_ = qf.shape
    V_ = vf.shape[-1]
    NT_ = T_ // BT
    
    qf = qf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    kf = kf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    vf = vf.view(B_, NT_, BT, H_, V_).permute(0, 3, 1, 2, 4).contiguous()
    gf = gf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    bf = bf.view(B_, NT_, BT, H_).permute(0, 3, 1, 2).contiguous()
    
    gf = gf.cumsum(-2)
    
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    BHN = B_ * H_ * NT_
    kg_flat = kg.reshape(BHN, BT, K_)
    kgn_flat = kgn.reshape(BHN, BT, K_)
    A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_upper = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=0)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    A_flat = A.view(BHN, BT, BT).contiguous()
    A_flat = solution._fwd_subst_mod.fwd_subst(A_flat)
    A = A_flat.view(B_, H_, NT_, BT, BT)
    I = torch.eye(BT, device=device, dtype=torch.float32)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    qg_flat = qg.reshape(BHN, BT, K_)
    Aqk = torch.bmm(qg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_strict = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=1)
    Aqk = Aqk.masked_fill(mask_strict, 0)
    
    q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    k_flat = kf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    u_flat = u.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, V_)
    w_flat = w.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    g_flat = gf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    Aqk_flat = Aqk.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, BT)
    o = torch.empty_like(inputs[2])
    
    scale = float(K_) ** -0.5
    
    grid = (triton.cdiv(V_, BV), B_ * H_)
    
    # Run many times for profiling
    for _ in range(100):
        kda_inter_chunk_kernel[grid](
            q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o,
            B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV, scale=scale,
            num_warps=4, num_stages=1,
        )
    torch.cuda.synchronize()
    print('Done')
" 2>&1 | tail -5
tool
stdout (53 chars)
<system>Command executed successfully.</system>
Done
assistant
reasoning (92 chars)
Let me run ncu on just the inter-chunk kernel to understand its performance characteristics.
Shell
args
{
  "command": "<3246 chars \u2014 see below>",
  "timeout": 120
}
command (3246 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && ncu --kernel-name kda_inter_chunk_kernel --metrics sm__warps_active.avg.pct_of_peak_sustained_elapsed,gpu__time_duration.avg,launch__block_size python -c "
import torch
import triton
import reference
import solution
import shapes

device = torch.device('cuda:0')
shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
sol_model = solution.Model(*init_args).to(device).eval()

torch.manual_seed(2026)
inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]

from solution import kda_inter_chunk_kernel

B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
BT = shape['CHUNK_SIZE']
BV = 32

with torch.no_grad():
    qf = inputs[0].float() * (float(K) ** -0.5)
    kf = inputs[1].float()
    vf = inputs[2].float()
    gf = inputs[3].float()
    bf = inputs[4].float()
    
    B_, T_, H_, K_ = qf.shape
    V_ = vf.shape[-1]
    NT_ = T_ // BT
    
    qf = qf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    kf = kf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    vf = vf.view(B_, NT_, BT, H_, V_).permute(0, 3, 1, 2, 4).contiguous()
    gf = gf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    bf = bf.view(B_, NT_, BT, H_).permute(0, 3, 1, 2).contiguous()
    
    gf = gf.cumsum(-2)
    
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    BHN = B_ * H_ * NT_
    kg_flat = kg.reshape(BHN, BT, K_)
    kgn_flat = kgn.reshape(BHN, BT, K_)
    A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_upper = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=0)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    A_flat = A.view(BHN, BT, BT).contiguous()
    A_flat = solution._fwd_subst_mod.fwd_subst(A_flat)
    A = A_flat.view(B_, H_, NT_, BT, BT)
    I = torch.eye(BT, device=device, dtype=torch.float32)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    qg_flat = qg.reshape(BHN, BT, K_)
    Aqk = torch.bmm(qg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_strict = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=1)
    Aqk = Aqk.masked_fill(mask_strict, 0)
    
    q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    k_flat = kf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    u_flat = u.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, V_)
    w_flat = w.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    g_flat = gf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    Aqk_flat = Aqk.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, BT)
    o = torch.empty_like(inputs[2])
    
    scale = float(K_) ** -0.5
    
    grid = (triton.cdiv(V_, BV), B_ * H_)
    
    for _ in range(10):
        kda_inter_chunk_kernel[grid](
            q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o,
            B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV, scale=scale,
            num_warps=4, num_stages=1,
        )
    torch.cuda.synchronize()
" 2>&1 | grep -E "(Duration|Warp|block_size|Kernel)" | head -20
tool
stdout (47 chars)
<system>Command executed successfully.</system>
assistant
reasoning (82 chars)
The ncu command didn't produce output. Let me try a different approach to run ncu.
Shell
args
{
  "command": "<3126 chars \u2014 see below>",
  "timeout": 120
}
command (3126 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && ncu --kernel-name-regex "kda_inter" --metrics gpu__time_duration.avg python -c "
import torch
import triton
import reference
import solution
import shapes

device = torch.device('cuda:0')
shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
sol_model = solution.Model(*init_args).to(device).eval()

torch.manual_seed(2026)
inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]

from solution import kda_inter_chunk_kernel

B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
BT = shape['CHUNK_SIZE']
BV = 32

with torch.no_grad():
    qf = inputs[0].float() * (float(K) ** -0.5)
    kf = inputs[1].float()
    vf = inputs[2].float()
    gf = inputs[3].float()
    bf = inputs[4].float()
    
    B_, T_, H_, K_ = qf.shape
    V_ = vf.shape[-1]
    NT_ = T_ // BT
    
    qf = qf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    kf = kf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    vf = vf.view(B_, NT_, BT, H_, V_).permute(0, 3, 1, 2, 4).contiguous()
    gf = gf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    bf = bf.view(B_, NT_, BT, H_).permute(0, 3, 1, 2).contiguous()
    
    gf = gf.cumsum(-2)
    
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    BHN = B_ * H_ * NT_
    kg_flat = kg.reshape(BHN, BT, K_)
    kgn_flat = kgn.reshape(BHN, BT, K_)
    A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_upper = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=0)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    A_flat = A.view(BHN, BT, BT).contiguous()
    A_flat = solution._fwd_subst_mod.fwd_subst(A_flat)
    A = A_flat.view(B_, H_, NT_, BT, BT)
    I = torch.eye(BT, device=device, dtype=torch.float32)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    qg_flat = qg.reshape(BHN, BT, K_)
    Aqk = torch.bmm(qg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_strict = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=1)
    Aqk = Aqk.masked_fill(mask_strict, 0)
    
    q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    k_flat = kf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    u_flat = u.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, V_)
    w_flat = w.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    g_flat = gf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    Aqk_flat = Aqk.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, BT)
    o = torch.empty_like(inputs[2])
    
    scale = float(K_) ** -0.5
    
    grid = (triton.cdiv(V_, BV), B_ * H_)
    
    for _ in range(100):
        kda_inter_chunk_kernel[grid](
            q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o,
            B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV, scale=scale,
            num_warps=4, num_stages=1,
        )
    torch.cuda.synchronize()
" 2>&1 | tail -30
tool
stdout (133 chars)
<system>Command executed successfully.</system>
==ERROR== unrecognised option '--kernel-name-regex'. Use --help for further details.
assistant
reasoning (34 chars)
Let me fix the ncu command syntax.
Shell
args
{
  "command": "<3109 chars \u2014 see below>",
  "timeout": 120
}
command (3109 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && ncu -k "kda_inter" --metrics gpu__time_duration.avg python -c "
import torch
import triton
import reference
import solution
import shapes

device = torch.device('cuda:0')
shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
sol_model = solution.Model(*init_args).to(device).eval()

torch.manual_seed(2026)
inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]

from solution import kda_inter_chunk_kernel

B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
BT = shape['CHUNK_SIZE']
BV = 32

with torch.no_grad():
    qf = inputs[0].float() * (float(K) ** -0.5)
    kf = inputs[1].float()
    vf = inputs[2].float()
    gf = inputs[3].float()
    bf = inputs[4].float()
    
    B_, T_, H_, K_ = qf.shape
    V_ = vf.shape[-1]
    NT_ = T_ // BT
    
    qf = qf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    kf = kf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    vf = vf.view(B_, NT_, BT, H_, V_).permute(0, 3, 1, 2, 4).contiguous()
    gf = gf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    bf = bf.view(B_, NT_, BT, H_).permute(0, 3, 1, 2).contiguous()
    
    gf = gf.cumsum(-2)
    
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    BHN = B_ * H_ * NT_
    kg_flat = kg.reshape(BHN, BT, K_)
    kgn_flat = kgn.reshape(BHN, BT, K_)
    A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_upper = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=0)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    A_flat = A.view(BHN, BT, BT).contiguous()
    A_flat = solution._fwd_subst_mod.fwd_subst(A_flat)
    A = A_flat.view(B_, H_, NT_, BT, BT)
    I = torch.eye(BT, device=device, dtype=torch.float32)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    qg_flat = qg.reshape(BHN, BT, K_)
    Aqk = torch.bmm(qg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_strict = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=1)
    Aqk = Aqk.masked_fill(mask_strict, 0)
    
    q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    k_flat = kf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    u_flat = u.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, V_)
    w_flat = w.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    g_flat = gf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    Aqk_flat = Aqk.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, BT)
    o = torch.empty_like(inputs[2])
    
    scale = float(K_) ** -0.5
    
    grid = (triton.cdiv(V_, BV), B_ * H_)
    
    for _ in range(100):
        kda_inter_chunk_kernel[grid](
            q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o,
            B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV, scale=scale,
            num_warps=4, num_stages=1,
        )
    torch.cuda.synchronize()
" 2>&1 | tail -30
tool
stdout (401 chars)
<system>Command executed successfully.</system>
==PROF== Connected to process 380195 (/usr/bin/python3.12)
==PROF== Disconnected from process 380195
==WARNING== No kernels were profiled.
Available Kernels:
1. Kernel2
2. elementwise_kernel
3. fwd_subst_kernel
4. kda_inter_chunk_kernel
5. tensor_kernel_scan_outer_dim
6. triu_tril_kernel
7. unrolled_elementwise_kernel
8. vectorized_elementwise_kernel
assistant
reasoning (44 chars)
Let me run ncu with the correct kernel name.
Shell
args
{
  "command": "<3218 chars \u2014 see below>",
  "timeout": 120
}
command (3218 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && ncu -k "kda_inter_chunk_kernel" --metrics gpu__time_duration.avg,sm__warps_active.avg.pct_of_peak_sustained_elapsed python -c "
import torch
import triton
import reference
import solution
import shapes

device = torch.device('cuda:0')
shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
sol_model = solution.Model(*init_args).to(device).eval()

torch.manual_seed(2026)
inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]

from solution import kda_inter_chunk_kernel

B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
BT = shape['CHUNK_SIZE']
BV = 32

with torch.no_grad():
    qf = inputs[0].float() * (float(K) ** -0.5)
    kf = inputs[1].float()
    vf = inputs[2].float()
    gf = inputs[3].float()
    bf = inputs[4].float()
    
    B_, T_, H_, K_ = qf.shape
    V_ = vf.shape[-1]
    NT_ = T_ // BT
    
    qf = qf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    kf = kf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    vf = vf.view(B_, NT_, BT, H_, V_).permute(0, 3, 1, 2, 4).contiguous()
    gf = gf.view(B_, NT_, BT, H_, K_).permute(0, 3, 1, 2, 4).contiguous()
    bf = bf.view(B_, NT_, BT, H_).permute(0, 3, 1, 2).contiguous()
    
    gf = gf.cumsum(-2)
    
    kg = kf * gf.exp()
    kgn = kf * (-gf).exp()
    BHN = B_ * H_ * NT_
    kg_flat = kg.reshape(BHN, BT, K_)
    kgn_flat = kgn.reshape(BHN, BT, K_)
    A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_upper = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=0)
    A = A * bf[..., None]
    A = -A.masked_fill(mask_upper, 0)
    A_flat = A.view(BHN, BT, BT).contiguous()
    A_flat = solution._fwd_subst_mod.fwd_subst(A_flat)
    A = A_flat.view(B_, H_, NT_, BT, BT)
    I = torch.eye(BT, device=device, dtype=torch.float32)
    A = (A + I) * bf[..., None, :]
    w = torch.matmul(A, (gf.exp() * kf))
    u = torch.matmul(A, vf)
    qg = qf * gf.exp()
    qg_flat = qg.reshape(BHN, BT, K_)
    Aqk = torch.bmm(qg_flat, kgn_flat.transpose(-2, -1)).view(B_, H_, NT_, BT, BT)
    mask_strict = torch.triu(torch.ones(BT, BT, device=device, dtype=torch.bool), diagonal=1)
    Aqk = Aqk.masked_fill(mask_strict, 0)
    
    q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    k_flat = kf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    u_flat = u.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, V_)
    w_flat = w.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    g_flat = gf.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, K_)
    Aqk_flat = Aqk.permute(0, 2, 3, 4, 1).reshape(B_, T_, H_, BT)
    o = torch.empty_like(inputs[2])
    
    scale = float(K_) ** -0.5
    
    grid = (triton.cdiv(V_, BV), B_ * H_)
    
    for _ in range(100):
        kda_inter_chunk_kernel[grid](
            q_flat, k_flat, u_flat, w_flat, g_flat, Aqk_flat, o,
            B=B_, T=T_, H=H_, K=K_, V=V_, BT=BT, BV=BV, scale=scale,
            num_warps=4, num_stages=1,
        )
    torch.cuda.synchronize()
" 2>&1 | grep -E "(Duration|Warp|Kernel|kda_inter)" | head -20
tool
stdout (47 chars)
<system>Command executed successfully.</system>
assistant
reasoning (5419 chars)
ncu seems to have issues. Let me try a different approach - just measure the performance more carefully and try to optimize the PyTorch code to reduce copies and overhead. Looking at my profiler output, the `aten::copy_` takes 1.99ms for 10 iterations = 0.2ms per iteration. That's a lot! Let me trace where copies happen. Actually, let me first check if I can just make all the intermediate tensors contiguous to reduce copies. And use in-place operations. Also, I should check if the `to(torch.float32)` conversions are causing copies. In the forward method: ```python qf, kf, vf, gf, bf = (x.to(torch.float32) for x in (q, k, v, g, beta)) ``` If q is already float32 (but it's bf16), this creates a copy. That's expected. Let me focus on the operations AFTER the conversions. One big issue: in my current code, I do: ```python qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4) ``` This creates a non-contiguous tensor. Then all subsequent operations on `qf` might create copies. If I add `.contiguous()` after the permute, it adds one copy upfront but makes all subsequent ops faster. Also, for the final reshape to pass to the Triton kernel, instead of doing: ```python q_flat = qf.permute(0, 2, 3, 4, 1).reshape(B, T, H, K) ``` I can just use the ORIGINAL `q` tensor (after scaling) since it has the correct layout! The Triton kernel reads q in standard (B, T, H, K) layout. Wait, but q is bf16, and the Triton kernel expects the same dtype as the pointer. In my kernel, `q_ptr` is passed as `q_flat` which is fp32. But the original `q` is bf16. Actually, looking at my kernel code: ```python b_q = tl.load(p_q, boundary_check=(0, 1)) ``` `p_q` is a block pointer to `q_flat` (which is fp32). So `b_q` will be fp32. But in my current code, `q_flat` comes from `qf.permute(...).reshape(...)`, where `qf` is fp32. If I pass the original `q` (bf16), the kernel would load bf16 values. I need to check if the kernel handles bf16 correctly. Actually, the kernel doesn't explicitly cast the loaded values. `tl.load` returns values in the tensor's dtype. Then `b_qg = (b_q * tl.exp(b_g)).to(b_q.dtype)` - this assumes `b_q` and `b_g` have compatible dtypes. If `q` is bf16 and `g` is fp32, then `b_q * tl.exp(b_g)` would be fp32 (since exp returns fp32), and `.to(b_q.dtype)` would convert to bf16. For the matmuls: `tl.dot(b_qg, b_S1.to(b_qg.dtype))` - if `b_qg` is bf16 and `b_S1` is fp32, then `b_S1.to(b_qg.dtype)` converts to bf16, and `tl.dot` does bf16 matmul with fp32 accumulation. This is fine! So I can pass the original bf16 tensors directly to the Triton kernel, eliminating the need to create `q_flat`, `k_flat`, etc. from the chunked tensors. But wait, `u` and `w` are computed from `A` in fp32. So `u_flat` and `w_flat` need to be fp32. And `Aqk_flat` is also fp32. Actually, `u` and `w` are fp32 tensors. I can reshape them without copy if they're contiguous. For `g`, it's fp32. The original `g` is in (B, T, H, K) layout and fp32. I can pass it directly. For `Aqk`, it's fp32 and in (B, T, H, BT) layout. So the only fp32 tensors I need to create are `u`, `w`, and `Aqk`. The original `q`, `k`, `v`, `g` can be used directly (after scaling q). Wait, but `v` is bf16. In the Triton kernel, I load `u` (which is derived from v) as fp32. I don't need `v` in the kernel. Let me redesign the code: 1. Scale q in-place or create qf = q.float() * scale 2. For the intra-chunk computations, I still need the chunk layout. But I can work with contiguous chunked tensors. 3. For the Triton kernel, pass: - q (bf16, after scaling) - k (bf16) - u (fp32, computed from w, A, v) - w (fp32, computed from A, k, g) - g (fp32) - Aqk (fp32) - o (bf16 output) This eliminates several permute/reshape operations and copies! Actually, an even better optimization: can I avoid the chunked layout entirely for the intra-chunk computations? For A_kk and Aqk, I need to compute per-chunk matmuls. I can do this directly on the (B, T, H, K) layout by grouping T into chunks: ```python # q: (B, T, H, K) # Reshape to (B, N, C, H, K) q_chunks = q.view(B, N, C, H, K).permute(0, 3, 1, 2, 4).contiguous() ``` Then compute A_kk with bmm on (B*H*N, C, K) @ (B*H*N, C, K).T. This is what I already do, but I can make it more efficient by ensuring contiguity. Let me rewrite the forward method with these optimizations. Actually, there's another important optimization. Looking at the profiler: - `aten::to` takes 0.46ms for 10 iterations = 0.046ms per call - `aten::_to_copy` takes similar time These come from the dtype conversions. But since q, k, v, beta are bf16 and g is fp32, we only need to convert q, k, v, beta to fp32. Wait, but in the reference, ALL inputs are converted to fp32: ```python q, k, v, g, beta = (x.to(torch.float32) for x in (q, k, v, g, beta)) ``` I should do the same for correctness. Let me think about what the most impactful optimization would be. The profiler shows: 1. Triton kernel: 0.28ms 2. Copy/clone: 0.20ms 3. Elementwise: 0.15ms 4. BMM: 0.06ms 5. Fwd subst: 0.03ms 6. Matmul: 0.04ms 7. Cumsum: 0.03ms If I can eliminate the copies (0.20ms) and reduce elementwise overhead (0.15ms), I can save ~0.35ms, bringing the total from 0.71ms to ~0.36ms. That's a 2x speedup. For the Triton kernel itself, maybe I can try using a CUDA kernel instead. But let me first optimize the PyTorch part. Let me rewrite the solution to minimize copies.
WriteFile /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
diff (224 lines — TRUNCATED)
--- a//home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
+++ b//home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py
@@ -1,10 +1,9 @@
 """KDA forward solution with custom CUDA and Triton kernels."""
 from __future__ import annotations
 
-import math
-
 import torch
 import torch.nn as nn
+from torch.utils.cpp_extension import load_inline
 import triton
 import triton.language as tl
 
@@ -47,8 +46,8 @@
 }
 """
 
-_fwd_subst_mod = torch.utils.cpp_extension.load_inline(
-    name="kda_fwd_subst",
+_fwd_subst_mod = load_inline(
+    name="kda_fwd_subst_v2",
     cpp_sources="torch::Tensor fwd_subst(torch::Tensor A);",
     cuda_sources=_CUDA_FWD_SUBST_SRC,
     functions=["fwd_subst"],
@@ -85,12 +84,9 @@
 
     NT = T // BT
 
-    # State tiles: K is fixed at 128, split into two 64-wide tiles
-    # S1: (64, BV), S2: (64, BV)
     b_S1 = tl.zeros((64, BV), dtype=tl.float32)
     b_S2 = tl.zeros((64, BV), dtype=tl.float32)
 
-    # Pointers base
     q_base = q_ptr + (i_b * T * H + i_h) * K
     k_base = k_ptr + (i_b * T * H + i_h) * K
     u_base = u_ptr + (i_b * T * H + i_h) * V
@@ -102,31 +98,25 @@
     for i_t in range(NT):
         t0 = i_t * BT
 
-        # Load u_i tile (BT, BV)
         p_u = tl.make_block_ptr(
             u_base, (T, V), (H * V, 1), (t0, i_v * BV), (BT, BV), (1, 0)
         )
         b_v = tl.load(p_u, boundary_check=(0, 1)).to(tl.float32)
 
-        # v_i = u_i - w_i @ S
-        # First K tile (0:64)
         p_w = tl.make_block_ptr(
             w_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
         )
         b_w = tl.load(p_w, boundary_check=(0, 1))
         b_v -= tl.dot(b_w, b_S1.to(b_w.dtype))
 
-        # Second K tile (64:128)
         p_w = tl.make_block_ptr(
             w_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
         )
         b_w = tl.load(p_w, boundary_check=(0, 1))
         b_v -= tl.dot(b_w, b_S2.to(b_w.dtype))
 
-        # Compute o_i = (q_i * exp(g_i)) @ S + Aqk @ v_i
         b_o = tl.zeros((BT, BV), dtype=tl.float32)
 
-        # qS from first K tile
         p_q = tl.make_block_ptr(
             q_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
         )
@@ -138,7 +128,6 @@
         b_qg = (b_q * tl.exp(b_g)).to(b_q.dtype)
         b_o += tl.dot(b_qg, b_S1.to(b_qg.dtype))
 
-        # qS from second K tile
         p_q = tl.make_block_ptr(
             q_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
         )
@@ -152,25 +141,20 @@
 
         b_o *= scale
 
-        # Aqk @ v_i
         p_Aqk = tl.make_block_ptr(
             Aqk_base, (T, BT), (H * BT, 1), (t0, 0), (BT, BT), (1, 0)
         )
         b_Aqk = tl.load(p_Aqk, boundary_check=(0, 1))
-        # Mask to strict lower triangular
         o_i = tl.arange(0, BT)
         m_s = o_i[:, None] >= o_i[None, :]
         b_Aqk = tl.where(m_s, b_Aqk, 0.0).to(b_v.dtype)
         b_o += tl.dot(b_Aqk, b_v.to(b_Aqk.dtype))
 
-        # Store o_i
         p_o = tl.make_block_ptr(
             o_base, (T, V), (H * V, 1), (t0, i_v * BV), (BT, BV), (1, 0)
         )
         tl.store(p_o, b_o.to(o_ptr.dtype.element_ty), boundary_check=(0, 1))
 
-        # Update state S
-        # decay = exp(g_i[:, -1])
         last_idx = t0 + BT - 1
         p_glast1 = g_base + last_idx * H * K + tl.arange(0, 64)
         p_glast2 = g_base + last_idx * H * K + 64 + tl.arange(0, 64)
@@ -181,9 +165,6 @@
         b_S1 *= b_decay1[:, None]
         b_S2 *= b_decay2[:, None]
 
-        # S += k_decay.T @ v_i
-        # k_decay = exp(g_last - g_i) * k_i
-        # First K tile
         p_k = tl.make_block_ptr(
             k_base, (T, K), (H * K, 1), (t0, 0), (BT, 64), (1, 0)
         )
@@ -195,7 +176,6 @@
         b_kg = b_k * tl.exp(b_glast1[None, :] - b_g)
         b_S1 += tl.dot(b_kg.to(b_v.dtype).T, b_v.to(b_k.dtype))
 
-        # Second K tile
         p_k = tl.make_block_ptr(
             k_base, (T, K), (H * K, 1), (t0, 64), (BT, 64), (1, 0)
         )
@@ -237,69 +217,66 @@
         qf, kf, vf, gf, bf = (x.to(torch.float32) for x in (q, k, v, g, beta))
         qf = qf * self.scale
 
-        # Reshape to chunk form: (B, H, N, C, D)
-        qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
-        kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
-        vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4)
-        gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4)
-        bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2)
-
-        # In-chunk cumsum
+        # Chunked layout contiguous
+        qf = qf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).contiguous()
+        kf = kf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).contiguous()
+        vf = vf.view(B, NT, BT, H, V).permute(0, 3, 1, 2, 4).contiguous()
+        gf = gf.view(B, NT, BT, H, K).permute(0, 3, 1, 2, 4).contiguous()
+        bf = bf.view(B, NT, BT, H).permute(0, 3, 1, 2).contiguous()
+
         gf = gf.cumsum(-2)
 
         # ---- Intra-chunk A_kk ----
         kg = kf * gf.exp()
         kgn = kf * (-gf).exp()
 
-        # B,H,N,C,K -> BHN,C,K for bmm
         BHN = B * H * NT
         kg_flat = kg.reshape(BHN, BT, K)
         kgn_flat = kgn.reshape(BHN, BT, K)
 
-        A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1))  # (BHN, C, C)
+        A = torch.bmm(kg_flat, kgn_flat.transpose(-2, -1))
         A = A.view(B, H, NT, BT, BT)
 
         mask_diag_upper = torch.triu(torch.ones(BT, BT, dtype=torch.bool, device=q.device), diagonal=0)
         A = A * bf[..., None]
         A = -A.masked_fill(mask_diag_upper, 0)
 
-        # Forward substitution via custom CUDA kernel
-        A_flat = A.view(BHN, BT, BT).contiguous()
+        A_flat = A.view(BHN, BT, BT)
         A_flat = _fwd_subst_mod.fwd_subst(A_flat)
         A = A_flat.view(B, H, NT, BT, BT)
 
         I = torch.eye(BT, dtype=torch.float32, device=q.device)
         A = (A + I) * bf[..., None, :]
 
-        # w and u
-        w = torch.matmul(A, (gf.exp() * kf))  # (B, H, N, C, K)
-        u = torch.

... (1956 more chars)
args
{
  "path": "/home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass/solution.py",
  "content": "<10407 chars \u2014 see diff>"
}
tool
stdout (74 chars)
<system>File successfully overwritten. Current size: 10407 bytes.</system>
assistant
reasoning (70 chars)
Let me run check.py first to make sure the refactored code is correct.
Shell
args
{
  "command": "cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python check.py",
  "timeout": 120
}
tool
stdout (53 chars)
<system>Command executed successfully.</system>
PASS
assistant
reasoning (38 chars)
Good, it passes. Let me time it again.
Shell
args
{
  "command": "<1334 chars \u2014 see below>",
  "timeout": 120
}
command (1334 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import solution
import shapes

device = torch.device('cuda:0')
for shape_idx, shape in enumerate(shapes.SHAPES):
    for k, v in shape.items():
        setattr(reference, k, v)
    
    init_args = reference.get_init_inputs()
    sol_model = solution.Model(*init_args).to(device).eval()
    
    torch.manual_seed(2026)
    inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]
    
    # Warmup
    with torch.no_grad():
        for _ in range(10):
            _ = sol_model(*inputs)
    torch.cuda.synchronize()
    
    # Time
    start = torch.cuda.Event(enable_timing=True)
    end = torch.cuda.Event(enable_timing=True)
    start.record()
    with torch.no_grad():
        for _ in range(50):
            _ = sol_model(*inputs)
    end.record()
    torch.cuda.synchronize()
    ms = start.elapsed_time(end) / 50
    
    # FLOPs
    B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
    CHUNK_SIZE = shape['CHUNK_SIZE']
    flops = 4 * B * T * H * (K * V + CHUNK_SIZE * K + CHUNK_SIZE * V)
    tflops = flops / (ms * 1e-3) / 1e12
    peak_frac = tflops / 200.0
    
    print(f'Shape {shape_idx}: {ms:.3f} ms, {tflops:.2f} TFLOPS, peak_fraction={peak_frac:.4f}')
"
tool
stdout (260 chars)
<system>Command executed successfully.</system>
Shape 0: 0.341 ms, 6.30 TFLOPS, peak_fraction=0.0315
Shape 1: 0.681 ms, 6.31 TFLOPS, peak_fraction=0.0315
Shape 2: 0.949 ms, 4.53 TFLOPS, peak_fraction=0.0226
Shape 3: 0.384 ms, 2.79 TFLOPS, peak_fraction=0.0140
assistant
reasoning (8502 chars)
The performance improved slightly (from 0.71ms to 0.68ms for shape 1), but we're still at only 3.2% peak fraction. I need to be at 10%. Let me think about what's fundamentally limiting performance. The SOTA gets 0.2ms, which is 3.4x faster than my 0.68ms. The difference is that FLA has highly optimized Triton kernels for ALL parts, while I have: 1. PyTorch for data movement and some compute 2. A CUDA kernel for forward substitution 3. A Triton kernel for inter-chunk The inter-chunk Triton kernel alone takes ~0.25ms. The rest takes ~0.43ms. Even if I could make the inter-chunk instantaneous, I'd still be at 0.43ms, which is 2.1x slower than SOTA. So the bottleneck is actually the PyTorch ops for the intra-chunk part! Let me look at what those ops are and how to optimize them. For the intra-chunk part, the main ops are: 1. `view + permute + contiguous` for all inputs 2. `cumsum` 3. `kg = kf * gf.exp()` and `kgn = kf * (-gf).exp()` 4. `torch.bmm` for A 5. `masked_fill` 6. `fwd_subst` CUDA kernel 7. `matmul` for w and u 8. `bmm` for Aqk 9. `masked_fill` for Aqk 10. `permute + reshape` for Triton inputs The profiler earlier showed that `aten::copy_`, `aten::clone`, and elementwise kernels take a lot of time. Even with `.contiguous()`, there are still many intermediate tensors being created. One approach: write a Triton kernel for the entire intra-chunk computation! For each (B, H, chunk), the intra-chunk kernel would: 1. Load k, g, beta, v, q for the 64 tokens 2. Compute A = (k*exp(g)) @ (k*exp(-g)).T 3. Apply masking and beta 4. Forward substitution on A 5. Compute w = A @ (k*exp(g)) and u = A @ v 6. Compute Aqk = (q*exp(g)) @ (k*exp(-g)).T 7. Apply masking to Aqk 8. Store w, u, Aqk This is a lot of work for one kernel, but it would eliminate all the intermediate copies and kernel launch overhead. For K=128, V=128, C=64, each chunk has: - Loads: k(8K), g(8K fp32), beta(64), v(8K), q(8K) = ~40KB - Stores: w(8K), u(8K), Aqk(4K) = ~20KB - Compute: A(64×128@128×64) = 1M FLOPs, w(64×64@64×128) = 1M FLOPs, u(64×64@64×128) = 1M FLOPs, Aqk(64×128@128×64) = 1M FLOPs - Forward substitution: negligible with custom algorithm Total compute per chunk: ~4M FLOPs. For 512 chunks: ~2B FLOPs. At 200 TFLOPS: 0.01ms. Memory: 512 * 60KB = 30MB. At 1.8TB/s: 0.017ms. So theoretically, a fused intra-chunk kernel could run in ~0.02ms. Plus the inter-chunk kernel at ~0.25ms, total ~0.27ms. That's still above SOTA but much closer. Actually, the inter-chunk kernel should also be optimizable. FLA gets 0.2ms TOTAL, so their inter-chunk is probably ~0.05-0.1ms. For now, let me focus on writing a Triton kernel for the intra-chunk part to eliminate the PyTorch overhead. Actually, I just realized something. The `permute + contiguous` operations at the beginning are creating 5 large tensors. For B=2, T=2048, H=8, K=128: - qf: 2*2048*8*128*4 = 16.7MB - kf: 16.7MB - vf: 16.7MB - gf: 2*2048*8*128*4 = 16.7MB (already fp32) - bf: 2*2048*8*4 = 131KB That's ~67MB of copies just for the initial layout changes! At 1.8TB/s, that's 0.037ms. But in practice, with multiple copies and non-contiguous access, it might take more. Then the `cumsum` creates another 16.7MB tensor. Then `kg` and `kgn` create another 33.4MB. Then `A` creates a 4MB tensor. Then `w` and `u` create 16.7MB + 16.7MB. Then `Aqk` creates 4MB. Total intermediate memory: ~160MB per forward pass. That's a lot! For comparison, FLA's kernels probably use much less intermediate memory because they fuse operations. To really compete, I need to write more fused kernels. Let me write a Triton kernel for the intra-chunk part. For the intra-chunk kernel, I'll process one chunk per thread block. Grid: (NT, B*H). The kernel needs to: 1. Load k, g, beta into shared memory or registers 2. Compute A_kk = (k*exp(g)) @ (k*exp(-g)).T 3. Mask A_kk to strictly lower triangular 4. Do forward substitution on A_kk 5. Compute w = A_kk @ (k*exp(g)) and u = A_kk @ v 6. Compute Aqk = (q*exp(g)) @ (k*exp(-g)).T 7. Mask Aqk to lower triangular (including diagonal) 8. Store w, u, Aqk For K=128, I'll tile K into 64-wide blocks. For V=128, I'll tile V into 64-wide or 32-wide blocks. This is getting complex. Let me write a simplified version. Actually, for the forward substitution in Triton, I can use the same sequential loop approach but on a per-block basis. The 64×64 matrix can be stored in shared memory (16KB). Let me draft this kernel: ```python @triton.jit def kda_intra_chunk_kernel( q_ptr, k_ptr, v_ptr, g_ptr, beta_ptr, w_ptr, u_ptr, Aqk_ptr, B, T, H, K, V, BT, scale, BK: tl.constexpr, BV: tl.constexpr, ): i_t, i_bh = tl.program_id(0), tl.program_id(1) i_b, i_h = i_bh // H, i_bh % H t0 = i_t * BT # Load beta p_b = tl.make_block_ptr(beta_ptr + (i_b * T * H + i_h), (T,), (H,), (t0,), (BT,), (0,)) b_b = tl.load(p_b, boundary_check=(0,)).to(tl.float32) # Compute A_kk in shared memory # A = zeros(BT, BT) # For each k tile: # load k_tile, g_tile # kg = k * exp(g) # kgn = k * exp(-g) # A += kg @ kgn.T # But Triton doesn't have shared memory arrays easily... # Actually, we can accumulate A in registers by iterating over token pairs ``` This is tricky in Triton because we need to store a 64×64 matrix per block. With 64 threads, each thread could store 64 fp32 values = 256 bytes. That's 16KB total, which fits in shared memory. But Triton manages shared memory automatically. Actually, let me think about whether I can just compute A in a more Triton-friendly way. Since A[i,j] = sum_k kg[i,k] * kgn[j,k], this is exactly a matmul. I can compute it as: ```python b_A = tl.zeros((BT, BT), dtype=tl.float32) for i_k in range(tl.cdiv(K, BK)): p_k = tl.make_block_ptr(k_base, (T, K), (H*K, 1), (t0, i_k*BK), (BT, BK), (1, 0)) p_g = tl.make_block_ptr(g_base, (T, K), (H*K, 1), (t0, i_k*BK), (BT, BK), (1, 0)) b_k = tl.load(p_k, boundary_check=(0, 1)) b_g = tl.load(p_g, boundary_check=(0, 1)).to(tl.float32) b_kg = b_k * tl.exp(b_g) b_kgn = b_k * tl.exp(-b_g) b_A += tl.dot(b_kg, tl.trans(b_kgn)) ``` This computes the full A matrix. Then apply masking and beta: ```python o_i = tl.arange(0, BT) m_diag = o_i[:, None] > o_i[None, :] # strictly lower b_A = -tl.where(m_diag, b_A * b_b[:, None], 0.0) ``` Then forward substitution. This is the hard part in Triton. Let me see if I can do it with a sequential loop: ```python # Forward substitution in shared memory # Store b_A in a local array... but Triton doesn't support mutable arrays well ``` Actually, Triton does support sequential loops with `tl.store` and `tl.load` to shared memory. But for a 64×64 matrix, it's awkward. For simplicity, I can compute A in the Triton kernel, store it to global memory, then use my CUDA kernel for the forward substitution, then load it back for computing w and u. But this creates more memory traffic. Alternatively, I can do the forward substitution on the CPU since it's only 512 matrices of size 64×64. But 512*64 = 32K iterations, which would be slow on CPU. Wait, actually I can use the divide-and-conquer approach in PyTorch more efficiently. Earlier I had a batched DC approach that took 0.874ms for 512 matrices. But that was without trying to optimize it further. Let me try to write a more efficient PyTorch DC approach using only 2-3 bmm calls per level. Actually, for the DC approach, the main cost is the stacking and unstacking. Let me try a different formulation. For C=64, the matrix (I - A)^{-1} can be computed using the fact that A is strictly lower triangular. The DC formula is: For M = [T, 0; O, B] where T and B are lower triangular: M^{-1} = [T^{-1}, 0; -B^{-1} @ O @ T^{-1}, B^{-1}] We can compute this using `torch.block_diag` and `torch.matmul` on the appropriate slices. But this is still complex to vectorize efficiently. Let me try a completely different approach. What if I use the `torch.linalg.solve_triangular` function? ```python L = torch.tril(A, diagonal=-1) # strictly lower triangular I = torch.eye(BT, device=A.device, dtype=A.dtype).expand_as(A) # We want (I - L)^{-1} # This is equivalent to solving (I - L) @ X = I for X ``` But `solve_triangular` requires the matrix to be triangular, and I-L is unit lower triangular. We can use: ```python X = torch.linalg.solve_triangular(I - L, I, upper=False) ``` But this operates on each matrix in the batch. For 512 matrices of size 64×64, let me test its performance.
Shell
args
{
  "command": "<835 chars \u2014 see below>",
  "timeout": 60
}
command (835 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import time

C = 64
BHN = 512
A = torch.randn(BHN, C, C, device='cuda') * 0.1
mask = torch.tril(torch.ones(C, C, device='cuda'), diagonal=-1)
A = A * mask
I = torch.eye(C, device='cuda').expand_as(A)

# Test solve_triangular
start = time.time()
for _ in range(100):
    L = I - A
    X = torch.linalg.solve_triangular(L, I, upper=False)
torch.cuda.synchronize()
print(f'solve_triangular: {(time.time()-start)/100*1000:.3f} ms')

# Reference forward substitution
start = time.time()
for _ in range(100):
    ref = A.clone()
    for i in range(1, C):
        ref[:, i, :i] = ref[:, i, :i] + (ref[:, i, :, None] * ref[:, :, :i]).sum(-2)
    ref = ref + I
torch.cuda.synchronize()
print(f'fwd subst loop: {(time.time()-start)/100*1000:.3f} ms')
"
tool
stdout (100 chars)
<system>Command executed successfully.</system>
solve_triangular: 0.489 ms
fwd subst loop: 1.291 ms
assistant
reasoning (3303 chars)
`solve_triangular` is 0.489ms, which is faster than the loop (1.291ms) but slower than my CUDA kernel (0.034ms). So my CUDA kernel is still the best for forward substitution. Now, the key insight is that the intra-chunk part without forward substitution takes ~0.2ms, and with my CUDA kernel it takes ~0.23ms. The inter-chunk kernel takes ~0.25ms. But there are also many copies and overhead operations taking ~0.2ms. So to get to SOTA performance, I need to: 1. Fuse the intra-chunk computations into fewer kernels 2. Optimize the inter-chunk kernel 3. Eliminate copies For step 1, I can write a Triton kernel that computes A, w, u, Aqk all in one go. But the forward substitution is hard in Triton. What if I keep my CUDA kernel for forward substitution, but wrap the rest in Triton? Actually, let me look at this from a different angle. The problem says I can use "CUTLASS CuTe on SM120 but Triton, CUDA C++ via load_inline, or inline PTX are also fine". What if I write the ENTIRE forward pass in a single CUDA kernel using load_inline? This would give me maximum control and eliminate all PyTorch overhead. For each (B, H, V_tile), the CUDA kernel would: 1. Initialize state S = zeros(K, V_tile) in shared memory 2. For each chunk i_t: a. Load q, k, v, g, beta for 64 tokens into shared memory b. Compute A_kk in shared memory c. Forward substitution on A_kk in shared memory d. Compute w, u, Aqk e. Compute output and update state f. Store output This is complex but feasible. Let me estimate the shared memory needed: - State S: K * V_tile = 128 * 32 = 4K fp32 = 16KB - For V_tile=32: - q tile: 64 * 64 = 4K bf16 = 8KB (per K tile, need 2 loads) - Actually, we can load directly from global memory for matmuls using CUDA's warp matrix multiply Wait, for CUDA C++, I can use the WMMA (Warp Matrix Multiply Accumulate) API or just regular shared memory + thread-level loops. For simplicity, let me write a CUDA kernel that: 1. Uses shared memory for the state S (128×32 fp32 = 16KB) 2. For each chunk, loads tiles into shared memory as needed 3. Uses simple thread-level matmuls (each thread computes one or more output elements) For a 64×64 @ 64×32 matmul: - Output is 64×32 = 2048 elements - With 128 threads, each thread computes 16 elements - Each element requires a dot product of length 64 - Total FLOPs per thread: 16 * 64 * 2 = 2048 FLOPs This is very manageable. And with 64 thread blocks (B=2, H=8, V_tiles=4 for V_tile=32), we have 64 * 128 = 8192 threads. Let me write this CUDA kernel. I'll need to handle: - Loading data from global memory in (B, T, H, K/V) layout - Computing A_kk = k_exp_g @ k_exp_neg_g.T - Forward substitution on A_kk - Computing w = A_kk @ k_exp_g - Computing u = A_kk @ v - Computing Aqk = q_exp_g @ k_exp_neg_g.T - Computing v_i = u_i - w_i @ S - Computing o_i = q_exp_g @ S + Aqk @ v_i - Updating S For the matmuls, I'll use a simple approach where threads cooperatively load tiles into shared memory and compute partial sums. Actually, this is a LOT of code. Let me see if there's a simpler approach. What if I use `torch.compile` with `fullgraph=True` and `mode='max-autotune'` on the entire forward method? Maybe the compiler can fuse more operations than I'm doing manually. Let me try compiling the forward method.
Shell
args
{
  "command": "<1588 chars \u2014 see below>",
  "timeout": 300
}
command (1588 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import solution
import shapes

device = torch.device('cuda:0')
shape = shapes.SHAPES[1]
for k, v in shape.items():
    setattr(reference, k, v)

init_args = reference.get_init_inputs()
sol_model = solution.Model(*init_args).to(device).eval()

# Compile the forward method
compiled_model = torch.compile(sol_model, mode='max-autotune')

torch.manual_seed(2026)
inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]

# Warmup
with torch.no_grad():
    for _ in range(10):
        _ = compiled_model(*inputs)

torch.cuda.synchronize()

# Time
start = torch.cuda.Event(enable_timing=True)
end = torch.cuda.Event(enable_timing=True)
start.record()
with torch.no_grad():
    for _ in range(50):
        _ = compiled_model(*inputs)
end.record()
torch.cuda.synchronize()
ms = start.elapsed_time(end) / 50

B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
CHUNK_SIZE = shape['CHUNK_SIZE']
flops = 4 * B * T * H * (K * V + CHUNK_SIZE * K + CHUNK_SIZE * V)
tflops = flops / (ms * 1e-3) / 1e12
peak_frac = tflops / 200.0

print(f'Compiled: {ms:.3f} ms, {tflops:.2f} TFLOPS, peak_fraction={peak_frac:.4f}')

# Baseline
start.record()
with torch.no_grad():
    for _ in range(50):
        _ = sol_model(*inputs)
end.record()
torch.cuda.synchronize()
ms2 = start.elapsed_time(end) / 50
tflops2 = flops / (ms2 * 1e-3) / 1e12
peak_frac2 = tflops2 / 200.0
print(f'Eager: {ms2:.3f} ms, {tflops2:.2f} TFLOPS, peak_fraction={peak_frac2:.4f}')
"
tool
stdout (11741 chars) — TRUNCATED
<system>Command executed successfully.</system>
/home/infatoshi/.local/lib/python3.12/site-packages/torch/_dynamo/variables/functions.py:2082: UserWarning: Dynamo does not know how to trace the builtin `kda_fwd_subst_v2.pybind11_detail_function_record_v1_system_libstdcpp_gxx_abi_1xxx_use_cxx11_abi_1.fwd_subst.` This function is either a Python builtin (e.g. _warnings.warn) or a third-party C/C++ Python extension (perhaps created with pybind).
If it is a Python builtin, please file an issue on GitHub so the PyTorch team can add support for it and see the next case for a workaround.
If it is a third-party C/C++ Python extension, please either wrap it into a PyTorch-understood custom operator (see https://pytorch.org/tutorials/advanced/custom_ops_landing_page.html for more details) or, if it is traceable, use `torch.compiler.allow_in_graph`.
  torch._dynamo.utils.warn_once(explanation + "\n" + "\n".join(hints))
/home/infatoshi/.local/lib/python3.12/site-packages/torch/_inductor/compile_fx.py:322: UserWarning: TensorFloat32 tensor cores for float32 matrix multiplication available but not enabled. Consider setting `torch.set_float32_matmul_precision('high')` for better performance.
  warnings.warn(
E0428 10:41:28.605000 382171 torch/_inductor/select_algorithm.py:3541] [0/0_1] Exception No valid triton configs. OutOfMemoryError: out of resource: triton_bmm Required: 131072 Hardware limit:101376 Reducing block sizes or `num_stages` may help. for benchmark choice TritonTemplateCaller

... (10241 more chars)
assistant
reasoning (423 chars)
`torch.compile` improved performance from 0.68ms to 0.53ms for the headline shape, giving 4.1% peak fraction. That's better but still far from 10%. Wait, the eager baseline in that test was 10.6ms because it included the compilation time of the inline CUDA kernel and Triton kernel on the first call. My earlier eager timing of 0.68ms was after warmup. Let me measure the compiled model more carefully with proper warmup.
Shell
args
{
  "command": "<1421 chars \u2014 see below>",
  "timeout": 300
}
command (1421 chars)
cd /home/infatoshi/cuda/KernelBench-Hard/problems/02_kda_cutlass && python -c "
import torch
import reference
import solution
import shapes

device = torch.device('cuda:0')
for shape_idx, shape in enumerate(shapes.SHAPES):
    for k, v in shape.items():
        setattr(reference, k, v)
    
    init_args = reference.get_init_inputs()
    sol_model = solution.Model(*init_args).to(device).eval()
    compiled_model = torch.compile(sol_model, mode='max-autotune')
    
    torch.manual_seed(2026)
    inputs = [t.to(device) if hasattr(t, 'to') else t for t in reference.get_inputs()]
    
    # Extensive warmup
    with torch.no_grad():
        for _ in range(20):
            _ = compiled_model(*inputs)
    torch.cuda.synchronize()
    
    # Time
    start = torch.cuda.Event(enable_timing=True)
    end = torch.cuda.Event(enable_timing=True)
    start.record()
    with torch.no_grad():
        for _ in range(50):
            _ = compiled_model(*inputs)
    end.record()
    torch.cuda.synchronize()
    ms = start.elapsed_time(end) / 50
    
    # FLOPs
    B, T, H, K, V = shape['B'], shape['T'], shape['H'], shape['K'], shape['V']
    CHUNK_SIZE = shape['CHUNK_SIZE']
    flops = 4 * B * T * H * (K * V + CHUNK_SIZE * K + CHUNK_SIZE * V)
    tflops = flops / (ms * 1e-3) / 1e12
    peak_frac = tflops / 200.0
    
    print(f'Shape {shape_idx}: {ms:.3f} ms, {tflops:.2f} TFLOPS, peak_fraction={peak_frac:.4f}')
"
tool
stdout (16877 chars) — TRUNCATED
<system>Command executed successfully.</system>
/home/infatoshi/.local/lib/python3.12/site-packages/torch/_dynamo/variables/functions.py:2082: UserWarning: Dynamo does not know how to trace the builtin `kda_fwd_subst_v2.pybind11_detail_function_record_v1_system_libstdcpp_gxx_abi_1xxx_use_cxx11_abi_1.fwd_subst.` This function is either a Python builtin (e.g. _warnings.warn) or a third-party C/C++ Python extension (perhaps created with pybind).
If it is a Python builtin, please file an issue on GitHub so the PyTorch team can add support for it and see the next case for a workaround.
If it is a third-party C/C++ Python extension, please either wrap it into a PyTorch-understood custom operator (see https://pytorch.org/tutorials/advanced/custom_ops_landing_page.html for more details) or, if it is traceable, use `torch.compiler.allow_in_graph`.
  torch._dynamo.utils.warn_once(explanation + "\n" + "\n".join(hints))
/home/infatoshi/.local/lib/python3.12/site-packages/torch/_inductor/compile_fx.py:322: UserWarning: TensorFloat32 tensor cores for float32 matrix multiplication available but not enabled. Consider setting `torch.set_float32_matmul_precision('high')` for better performance.
  warnings.warn(
E0428 10:42:00.129000 382720 torch/_inductor/select_algorithm.py:3541] [0/0_1] Exception No valid triton configs. OutOfMemoryError: out of resource: triton_bmm Required: 131072 Hardware limit:101376 Reducing block sizes or `num_stages` may help. for benchmark choice TritonTemplateCaller

... (15377 more chars)